Hi,
I have a list of url names like this, and I am trying to strip out the
domain name using the following code: http://www.cnn.com www.yahoo.com http://www.ebay.co.uk
pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
but none of the site matched, can you please tell me what am i
missing?
Thank you. 8  7012 
<Ma***********@ gmail.comwrote:
Hi,
I have a list of url names like this, and I am trying to strip out the
domain name using the following code:
http://www.cnn.com
www.yahoo.com
http://www.ebay.co.uk
pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
but none of the site matched, can you please tell me what am i
missing?
You're using reverse slashes in your RE pattern, to start with, while
the URLs contain plain slashes (or don't have any slashes, in the case
of the second one).
Anyway, forget REs, and use standard library module urlparse,
specifically its urlparse.urlspl it function.
Alex
On Apr 13, 2007, at 11:49 PM, Ma***********@g mail.com wrote:
Hi,
I have a list of url names like this, and I am trying to strip out the
domain name using the following code:
http://www.cnn.com
www.yahoo.com
http://www.ebay.co.uk
pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
but none of the site matched, can you please tell me what am i
missing?
change re.compile("htt p:\\\\(.*)\.(.* )", re.S) to re.compile("htt p:\/
\/(.*)\.(.*)", re.S)
On Apr 14, 12:02 am, Michael Bentley <mich...@jedimi ndworks.com>
wrote:
On Apr 13, 2007, at 11:49 PM, Marko.Cain...@g mail.com wrote:
Hi,
I have a list of url names like this, and I am trying to strip out the
domain name using the following code:
http://www.cnn.com
www.yahoo.com
http://www.ebay.co.uk
pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
but none of the site matched, can you please tell me what am i
missing?
change re.compile("htt p:\\\\(.*)\.(.* )", re.S) to re.compile("htt p:\/
\/(.*)\.(.*)", re.S)
Thanks. I try this:
but when the 'line' is http://www.cnn.com, I get 's2' com,
but i want 'cnn.com' (everything after the first '.'), how can I do
that?
pattern = re.compile("htt p:\/\/(.*)\.(.*)", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
On Apr 14, 10:36 am, Marko.Cain...@g mail.com wrote:
On Apr 14, 12:02 am, Michael Bentley <mich...@jedimi ndworks.com>
wrote:
On Apr 13, 2007, at 11:49 PM, Marko.Cain...@g mail.com wrote:
Hi,
I have a list of url names like this, and I am trying to strip out the
domain name using the following code:
>http://www.cnn.com
>www.yahoo.com
>http://www.ebay.co.uk
pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
but none of the site matched, can you please tell me what am i
missing?
change re.compile("htt p:\\\\(.*)\.(.* )", re.S) to re.compile("htt p:\/
\/(.*)\.(.*)", re.S)
Thanks. I try this:
but when the 'line' ishttp://www.cnn.com, I get 's2' com,
but i want 'cnn.com' (everything after the first '.'), how can I do
that?
pattern = re.compile("htt p:\/\/(.*)\.(.*)", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
Can anyone please help me with my problem? I still can't solve it.
Basically, I want to strip out the text after the first '.' in url
address: http://www.cnn.com -cnn.com
In <11************ *********@y5g20 00hsa.googlegro ups.com>, Marko.Cain.23
wrote:
On Apr 14, 10:36 am, Marko.Cain...@g mail.com wrote:
>On Apr 14, 12:02 am, Michael Bentley <mich...@jedimi ndworks.com>
wrote:
On Apr 13, 2007, at 11:49 PM, Marko.Cain...@g mail.com wrote:
Hi,
I have a list of url names like this, and I am trying to strip out the
domain name using the following code:
>http://www.cnn.com
www.yahoo.com
http://www.ebay.co.uk
pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
but none of the site matched, can you please tell me what am i
missing?
change re.compile("htt p:\\\\(.*)\.(.* )", re.S) to re.compile("htt p:\/
\/(.*)\.(.*)", re.S)
Thanks. I try this:
but when the 'line' ishttp://www.cnn.com, I get 's2' com,
but i want 'cnn.com' (everything after the first '.'), how can I do
that?
pattern = re.compile("htt p:\/\/(.*)\.(.*)", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
Can anyone please help me with my problem? I still can't solve it.
Basically, I want to strip out the text after the first '.' in url
address:
http://www.cnn.com -cnn.com
from urlparse import urlsplit
def get_domain(url) :
net_location = urlsplit(url)[1]
return '.'.join(net_lo cation.rsplit(' .', 2)[-2:])
def main():
print get_domain('htt p://www.cnn.com')
Ciao,
Marc 'BlackJack' Rintsch
On Apr 15, 11:57 am, Marc 'BlackJack' Rintsch <bj_...@gmx.net wrote:
In <1176654669.737 355.78...@y5g20 00hsa.googlegro ups.com>, Marko.Cain.23
wrote:
On Apr 14, 10:36 am, Marko.Cain...@g mail.com wrote:
On Apr 14, 12:02 am, Michael Bentley <mich...@jedimi ndworks.com>
wrote:
On Apr 13, 2007, at 11:49 PM, Marko.Cain...@g mail.com wrote:
Hi,
I have a list of url names like this, and I am trying to strip out the
domain name using the following code:
>http://www.cnn.com
>www.yahoo.com
>http://www.ebay.co.uk
pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
but none of the site matched, can you please tell me what am i
missing?
change re.compile("htt p:\\\\(.*)\.(.* )", re.S) to re.compile("htt p:\/
\/(.*)\.(.*)", re.S)
Thanks. I try this:
but when the 'line' ishttp://www.cnn.com, I get 's2' com,
but i want 'cnn.com' (everything after the first '.'), how can I do
that?
pattern = re.compile("htt p:\/\/(.*)\.(.*)", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
Can anyone please help me with my problem? I still can't solve it.
Basically, I want to strip out the text after the first '.' in url
address:
http://www.cnn.com-cnn.com
from urlparse import urlsplit
def get_domain(url) :
net_location = urlsplit(url)[1]
return '.'.join(net_lo cation.rsplit(' .', 2)[-2:])
def main():
print get_domain('htt p://www.cnn.com')
Ciao,
Marc 'BlackJack' Rintsch
Thanks for your help.
But if the input string is "http://www.ebay.co.uk/", I only get
"co.uk"
how can I change it so that it works for both www.ebay.co.uk and www.cnn.com? Ma***********@g mail.com wrote:
On Apr 15, 11:57 am, Marc 'BlackJack' Rintsch <bj_...@gmx.net wrote:
>In <1176654669.737 355.78...@y5g20 00hsa.googlegro ups.com>, Marko.Cain.23
wrote:
>>On Apr 14, 10:36 am, Marko.Cain...@g mail.com wrote:
On Apr 14, 12:02 am, Michael Bentley <mich...@jedimi ndworks.com>
wrote:
On Apr 13, 2007, at 11:49 PM, Marko.Cain...@g mail.com wrote:
>Hi,
>I have a list of url names like this, and I am trying to strip out the
>domain name using the following code:
>http://www.cnn.com
>www.yahoo.com
>http://www.ebay.co.uk
>pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
>match = re.findall(patt ern, line)
>if (match):
> s1, s2 = match[0]
> print s2
>but none of the site matched, can you please tell me what am i
>missing?
change re.compile("htt p:\\\\(.*)\.(.* )", re.S) to re.compile("htt p:\/
\/(.*)\.(.*)", re.S)
Thanks. I try this:
but when the 'line' ishttp://www.cnn.com, I get 's2' com,
but i want 'cnn.com' (everything after the first '.'), how can I do
that?
pattern = re.compile("htt p:\/\/(.*)\.(.*)", re.S)
match = re.findall(patt ern, line)
if (match):
s1, s2 = match[0]
print s2
Can anyone please help me with my problem? I still can't solve it.
Basically, I want to strip out the text after the first '.' in url
address:
http://www.cnn.com-cnn.com
from urlparse import urlsplit
def get_domain(url) :
net_location = urlsplit(url)[1]
return '.'.join(net_lo cation.rsplit(' .', 2)[-2:])
def main():
print get_domain('htt p://www.cnn.com')
Ciao,
Marc 'BlackJack' Rintsch
Thanks for your help.
But if the input string is "http://www.ebay.co.uk/", I only get
"co.uk"
how can I change it so that it works for both www.ebay.co.uk and www.cnn.com?
>>def get_domain(url) :
... net_location = urlsplit(url)[1]
... return net_location.sp lit(".", 1)[1]
...
>>print get_domain('htt p://www.cnn.com')
cnn.com
>>print get_domain('htt p://www.ebay.co.uk' )
ebay.co.uk
>>>
regards
Steve
--
Steve Holden +44 150 684 7255 +1 800 494 3119
Holden Web LLC/Ltd http://www.holdenweb.com
Skype: holdenweb http://del.icio.us/steve.holden
Recent Ramblings http://holdenweb.blogspot.com
On Apr 15, 2007, at 4:24 PM, Ma***********@g mail.com wrote:
On Apr 15, 11:57 am, Marc 'BlackJack' Rintsch <bj_...@gmx.net wrote:
>In <1176654669.737 355.78...@y5g20 00hsa.googlegro ups.com>,
Marko.Cain.2 3
wrote:
>>On Apr 14, 10:36 am, Marko.Cain...@g mail.com wrote:
On Apr 14, 12:02 am, Michael Bentley <mich...@jedimi ndworks.com>
wrote:
>>>>On Apr 13, 2007, at 11:49 PM, Marko.Cain...@g mail.com wrote:
>>>>>Hi,
>>>>>I have a list of url names like this, and I am trying to strip
>out the
>domain name using the following code:
>>>>>http://www.cnn.com
>www.yahoo.com
>http://www.ebay.co.uk
>>>>>pattern = re.compile("htt p:\\\\(.*)\.(.* )", re.S)
>match = re.findall(patt ern, line)
>>>>>if (match):
> s1, s2 = match[0]
>>>>> print s2
>>>>>but none of the site matched, can you please tell me what am i
>missing?
>>>>change re.compile("htt p:\\\\(.*)\.(.* )", re.S) to re.compile
("http:\/
\/(.*)\.(.*)", re.S)
>>>Thanks. I try this:
>>>but when the 'line' ishttp://www.cnn.com, I get 's2' com,
but i want 'cnn.com' (everything after the first '.'), how can I do
that?
>>>pattern = re.compile("htt p:\/\/(.*)\.(.*)", re.S)
>>> match = re.findall(patt ern, line)
>>> if (match):
>>> s1, s2 = match[0]
>>> print s2
>>Can anyone please help me with my problem? I still can't solve it.
>>Basically, I want to strip out the text after the first '.' in url
address:
>>http://www.cnn.com-cnn.com
from urlparse import urlsplit
def get_domain(url) :
net_location = urlsplit(url)[1]
return '.'.join(net_lo cation.rsplit(' .', 2)[-2:])
def main():
print get_domain('htt p://www.cnn.com')
Ciao,
Marc 'BlackJack' Rintsch
Thanks for your help.
But if the input string is "http://www.ebay.co.uk/", I only get
"co.uk"
how can I change it so that it works for both www.ebay.co.uk and
www.cnn.com?
from urlparse import urlsplit
def get_domain(url) :
net_location = (
urlsplit(url)[1]
and urlsplit(url)[1].split('.')
or urlsplit(url)[2].split('.')
) # tricksy way to get long line into email
if net_location[0].lower() == 'www':
net_location = net_location[1:]
return '.'.join(net_lo cation)
def main():
testItems = ['http://www.cnn.com',
'www.yahoo.com' ,
'http://www.ebay.co.uk']
for testItem in testItems:
print get_domain(test Item)
if __name__ == '__main__':
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