how to remove multiple occurrences of a string within a list?

[bahoo]

Hi,

I have a list like ['0024', 'haha', '0024']
and as output I want ['haha']

If I
myList.remove(' 0024')

then only the first instance of '0024' is removed.

It seems like regular expressions is the rescue, but I couldn't find
the right tool.

Thanks!
bahoo

[Matimus]

It depends on your application, but a 'set' might really be what you
want, as opposed to a list.

>>s = set(["0024","haha"," 0024"])
s

set(["0024","hah a"])

>>s.remove("002 4")
s

set(["haha"])

[kyosohma]

On Apr 3, 1:31 pm, "Matimus" <mccre...@gmail .comwrote:

It depends on your application, but a 'set' might really be what you
want, as opposed to a list.

>s = set(["0024","haha"," 0024"])
s

set(["0024","hah a"])>>s.remove("00 24")

>s

set(["haha"])

If you want, you can also loop over the list, like so:

counter = 0
your_list = ["0024","haha"," 0024"]
for i in your_list:
if i == '0024':
your_list.pop(c ounter)
counter += 1
Mike

[Thomas Nelson]

bahoo wrote:

Hi,

I have a list like ['0024', 'haha', '0024']
and as output I want ['haha']

If I
myList.remove(' 0024')

then only the first instance of '0024' is removed.

It seems like regular expressions is the rescue, but I couldn't find
the right tool.

Thanks!
bahoo

It's hard to imagine using regular expressions here. Here's a simple
attempt:

def removeall(mylis t,obj):
while obj in mylist:
mylist.remove(o bj)

Or, if you don't need the changes in place:

[x for x in mylist if x!= obj]

Tom

[Thomas Nelson]

On Apr 3, 1:49 pm, kyoso...@gmail. com wrote:

On Apr 3, 1:31 pm, "Matimus" <mccre...@gmail .comwrote:

It depends on your application, but a 'set' might really be what you
want, as opposed to a list.

>>s = set(["0024","haha"," 0024"])
>>s

set(["0024","hah a"])>>s.remove("00 24")

>>s

set(["haha"])

If you want, you can also loop over the list, like so:

counter = 0
your_list = ["0024","haha"," 0024"]
for i in your_list:
if i == '0024':
your_list.pop(c ounter)
counter += 1

Mike

This method doesn't work.

>>li = list('hello larry')
count = 0
for i in li:

.... if i=='l':
.... li.pop(count)
.... coun += 1
....
'l'
'l'

>>l

['h', 'e', 'l', 'o', ' ', 'a', 'r', 'r', 'y']

because the indexes change as you pop, it gets some of them but not
all.

[kyosohma]

On Apr 3, 1:49 pm, kyoso...@gmail. com wrote:

On Apr 3, 1:31 pm, "Matimus" <mccre...@gmail .comwrote:

It depends on your application, but a 'set' might really be what you
want, as opposed to a list.

>>s = set(["0024","haha"," 0024"])
>>s

set(["0024","hah a"])>>s.remove("00 24")

>>s

set(["haha"])

If you want, you can also loop over the list, like so:

counter = 0
your_list = ["0024","haha"," 0024"]
for i in your_list:
if i == '0024':
your_list.pop(c ounter)
counter += 1

Mike

If you want to get really fancy, you could do a list comprehension
too:

your_list = ["0024","haha"," 0024"]
new_list = [i for i in your_list if i != '0024']

Mike

[7stud]

On Apr 3, 12:20 pm, "bahoo" <b83503...@yaho o.comwrote:

Hi,

I have a list like ['0024', 'haha', '0024']
and as output I want ['haha']

If I
myList.remove(' 0024')

then only the first instance of '0024' is removed.

It seems like regular expressions is the rescue, but I couldn't find
the right tool.

Thanks!
bahoo

Here are a couple of ways:

target = "0024"
l = ["0024", "haha", "0024"]

------------------------------------
while(True):
try:
l.remove(target )
except ValueError:
break

print l
-------------------------------------

for index, val in enumerate(l):
if val==target:
del l[index]

print l

[bahoo]

On Apr 3, 2:31 pm, "Matimus" <mccre...@gmail .comwrote:

It depends on your application, but a 'set' might really be what you
want, as opposed to a list.

>s = set(["0024","haha"," 0024"])
s

set(["0024","hah a"])>>s.remove("00 24")

>s

set(["haha"])

This sounds cool.
But is there a command I can convert the "set" back to a "list"?

[Matimus]

On Apr 3, 12:13 pm, "bahoo" <b83503...@yaho o.comwrote:

On Apr 3, 2:31 pm, "Matimus" <mccre...@gmail .comwrote:

It depends on your application, but a 'set' might really be what you
want, as opposed to a list.

>>s = set(["0024","haha"," 0024"])
>>s

set(["0024","hah a"])>>s.remove("00 24")

>>s

set(["haha"])

This sounds cool.
But is there a command I can convert the "set" back to a "list"?

yeah...

>>l = list(s)
l

["haha"]

[Steve Holden]

bahoo wrote:

On Apr 3, 2:31 pm, "Matimus" <mccre...@gmail .comwrote:

>It depends on your application, but a 'set' might really be what you
want, as opposed to a list.

>>>>s = set(["0024","haha"," 0024"])
s

set(["0024","hah a"])>>s.remove("00 24")

>>>>s

set(["haha"])

This sounds cool.
But is there a command I can convert the "set" back to a "list"?

That would be list(). So what you want is

s = set(["0024","haha"," 0024"])
s.remove("0024" )
l = list(s)

or something like it. It seems, a priori, unlikely that you only want to
remove items with that specific value, Is this part of some larger problem?

regards
Steve
--
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