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Is it possible to access Methods of a class without creating object?

440 Contributor
HI,

Is it possible to access the Methods of a class without creating object?


Thanks
PSB
Mar 17 '07 #1
10 3444
bartonc
6,596 Recognized Expert Expert
HI,

Is it possible to access the Methods of a class without creating object?


Thanks
PSB
The Python Manuals says:
Class instance methods are either bound or unbound, referring to whether the method was accessed through an instance or a class, respectively. When a method is unbound, its im_self attribute will be None and if called, an explicit self object must be passed as the first argument. In this case, self must be an instance of the unbound method's class (or a subclass of that class), otherwise a TypeError is raised.

in section 2.3.10 Other Built-in Types sub 2.3.10.4 Methods (version 2.4.4)
Mar 17 '07 #2
bvdet
2,851 Recognized Expert Moderator Specialist
HI,

Is it possible to access the Methods of a class without creating object?


Thanks
PSB
You can access class methods without creating a class instance.
Expand|Select|Wrap|Line Numbers
  1. class Point(object):
  2.     def __init__(self, x=0.0, y=0.0, z=0.0):
  3.         self.x = float(x)
  4.         self.y = float(y)
  5.         self.z = float(z)
  6.     def test(cls):
  7.         print 'You can access a class method without creating an instance.'
  8.     test = classmethod(test)
>>> Point.test()
You can access a class method without creating an instance.
>>>
In Python 2.4, class methods can be created with the @classmethod decorator.
Mar 17 '07 #3
bartonc
6,596 Recognized Expert Expert
You can access class methods without creating a class instance.
Expand|Select|Wrap|Line Numbers
  1. class Point(object):
  2.     def __init__(self, x=0.0, y=0.0, z=0.0):
  3.         self.x = float(x)
  4.         self.y = float(y)
  5.         self.z = float(z)
  6.     def test(cls):
  7.         print 'You can access a class method without creating an instance.'
  8.     test = classmethod(test)
>>> Point.test()
You can access a class method without creating an instance.
>>>
In Python 2.4, class methods can be created with the @classmethod decorator.
True. But doesn't this negate the reason for having an object in the first place? Without access to self.anyThing, test() should be refactored into a different (module, perhaps) scope.
Mar 18 '07 #4
bvdet
2,851 Recognized Expert Moderator Specialist
True. But doesn't this negate the reason for having an object in the first place? Without access to self.anyThing, test() should be refactored into a different (module, perhaps) scope.
I agree. I have never needed a class method without an instance.
Mar 18 '07 #5
psbasha
440 Contributor
Thanks for the reply.

This helps us when we dont want to create the object of the class and make use of everywhere (helpful in creating a MathUtil module).I hope this functionality is similar to using a static functions in a class or namespace methods in C++.

Static function:
------------------------
class Sample{

public :

static void Func1(){}

};

void main(){

Sample::Func1() ;
}

Namespace:
------------------------
namespace Sample1{

public :

void Func1(){}

};

void main(){

Sample1::Func1( );
}

-PSB
Mar 18 '07 #6
psbasha
440 Contributor
If I want to access all the Methods of the classes ,so I have to define all the methods similar to " test = classmethod(tes t)"

class X:

def Func1():
print "Func1()"

def Func2():
print "Func2()"

.............
def Funcn():
print "Funcn()"

Func1= classmethod(Fun c1)
Func2= classmethod(Fun c2)

.....

Funcn= classmethod(Fun cn)

-PSB
Mar 18 '07 #7
bvdet
2,851 Recognized Expert Moderator Specialist
If I want to access all the Methods of the classes ,so I have to define all the methods similar to " test = classmethod(tes t)"

class X:

def Func1():
print "Func1()"

def Func2():
print "Func2()"

.............
def Funcn():
print "Funcn()"

Func1= classmethod(Fun c1)
Func2= classmethod(Fun c2)

.....

Funcn= classmethod(Fun cn)

-PSB
If you use Python 2.4 or higher, use decorators:
Expand|Select|Wrap|Line Numbers
  1.     @classmethod
  2.     def Funcn():
  3.         print "Funcn()"
Why can't you use code tags?
Mar 18 '07 #8
bvdet
2,851 Recognized Expert Moderator Specialist
If you use Python 2.4 or higher, use decorators:
Expand|Select|Wrap|Line Numbers
  1.     @classmethod
  2.     def Funcn():
  3.         print "Funcn()"
Why can't you use code tags?
I failed to mention that the class object is passed to a class method, so you must have an argument in the argument list. By convention, the name of this argument is cls.
Expand|Select|Wrap|Line Numbers
  1.     @classmethod
  2.     def Funcn(cls):
  3.         print "Funcn()"
You may want to use static methods instead:
Expand|Select|Wrap|Line Numbers
  1. class Point(object):
  2.     def __init__(self, x=0.0, y=0.0, z=0.0):
  3.         self.x = float(x)
  4.         self.y = float(y)
  5.         self.z = float(z)
  6.     def test(cls):
  7.         print 'You can access a class method without creating an instance.'
  8.     test = classmethod(test)
  9.     def test2():
  10.         print 'I have never used a static method.'
  11.     test2 = staticmethod(test2)
Expand|Select|Wrap|Line Numbers
  1. >>> Point.test2()
  2. I have never used a static method.
  3. >>> Point.test()
  4. You can access a class method without creating an instance.
  5. >>> 
Mar 18 '07 #9
psbasha
440 Contributor
Thanks for the reply.

Here both are performing the same functionality "accessing the methods of a class without creating the object".Then why two.

Is there anything different in memory management of it?.

Thanks
PSB
Mar 18 '07 #10

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