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# Problem with returning prime number in a simple calculation program

Hello, I'm new to Python (I've learned everything up to iterators so
far) and fairly new to Programming. This would be my first real
program:

#Coordinate Geometry (The whole program is not shown)

import math
import sys

print "Welcome to the Coordinate Geometry Calculator!"
print "Type 'terms' for a list of commands"

def main():
print
command = raw_input("Comm and? ")
if command == "terms":
terms()
main()
elif command == "distance":
distance()
main()
elif command == "slope":
slope()
main()
elif command == "endpoint":
endpoint()
main()
elif command == "midpoint":
midpoint()
main()
elif command == "prime":
prime()
main()
elif command == "quit":
sys.exit
else:
print "Not a valid command"
main()

#...Declaring functions here...

def prime():
num = input("Number ")
i = num - 1
divcounter = 0
while i 1:
if num % i != 0:
divcounter += 1
i -= 1
if divcounter == num - 2:
print num, "is a prime number"
else:
print num, "is not a prime number"

#Start the program
main()

As it says in the title, I'm having trouble with the prime number
function. It will print the sentence if the number is prime, but it
if isn't, the program goes into a state in the terminal where the
program never ends and you can just keep on typing. Maybe the else
statement is ineffective? Any ideas on how to fix this?

Mar 3 '07 #1
2 2613
QH******@gmail. com wrote:
[reformatted indentation]
def prime():
num = input("Number ")
i = num - 1
divcounter = 0
while i 1:
if num % i != 0
divcounter += 1
i -= 1
if divcounter == num - 2:
print num, "is a prime number"
else:
print num, "is not a prime number"
[...]
As it says in the title, I'm having trouble with the prime number
function. It will print the sentence if the number is prime, but
it if isn't, the program goes into a state in the terminal where
the program never ends and you can just keep on typing.
Sure thing. You designed the function to behave this way.

Look at the while loop -- especially think what happens if
(num % i == 0). i will never be decremented then and the function
will not terminate.

Try inserting print statements for debugging if you don't get what I
meant here.
Maybe the else statement is ineffective?

Regards,
Björn

--
BOFH excuse #86:

Runt packets

Mar 3 '07 #2
On Sat, 03 Mar 2007 15:36:36 -0800, QHorizon wrote:
Hello, I'm new to Python (I've learned everything up to iterators so
far) and fairly new to Programming. This would be my first real
program:

#Coordinate Geometry (The whole program is not shown)

import math
import sys

print "Welcome to the Coordinate Geometry Calculator!"
print "Type 'terms' for a list of commands"

def main():
[snip big boring series of if...elif... statements]

You're eventually going to run into a run time recursion error if you run
that for long enough. Can you see why?

A better way to do a command loop is something like this:
# called when the user enters an unrecognized command
print "Unknown command, please try again"

class QuitException(E xception):
# used for exiting the loop
pass
def main():
# Make a "dispatch table" that maps the name of a command
# (as typed by the user) with a function to call.
dispatcher = {'slope': do_slope,
'primes': do_primes,
'quit': do_quit,
# ... and more here
}
try:
# loop forever (until we jump out of it)
while True:
cmd = get_command_fro m_user()
# you have to write get_command_fro m_user yourself
result = func()
print result
except QuitException:
print "Goodbye, come again soon!"
Now you just need to define your individual functions do_slope, do_primes,
etc. The only "special" one is do_quit.

def do_quit():
raise QuitException
Now let's look at the do_primes function. (You call it "prime".)
def prime():
num = input("Number ")
That's a good way to have malicious users do really, really really bad

Safer is to do this:

num = int(raw_input(" Number "))
i = num - 1
divcounter = 0
while i 1:
if num % i != 0:
divcounter += 1
i -= 1
That's an inefficient algorithm, if it even works. I'm not sure that it
works, and I'm too lazy to find out :)

if divcounter == num - 2:
print num, "is a prime number"
else:
print num, "is not a prime number"
This will only work if divcounter happens to equal the original number
less two. If it equals something else, nothing will be printed.

Here's a simple algorithm to check if a number is prime.

# Warning: untested.
def do_primes():
num = int(raw_input(" Number ")
if num <= 1:
return "%n is not prime" % num
if num == 2:
return "%n is prime" % num
elif num % 2 == 0:
# even numbers other than 2 aren't prime
return "%n is not prime" % num
for i in range(3, num, 2):
if num % i == 0:
return "%n is not prime" % num
return "%n is prime" % num
Now, this is deliberately not an efficient algorithm. There are things you
can do to make it more efficient, or you can re-write it completely.
The thing to remember is, don't PRINT the result, RETURN it. Your
do_primes() function should only calculate the result, and pass that
result up to the main loop for printing (or writing to a text file, or
emailing, or whatever).

Have fun!

--
Steven.

Mar 4 '07 #3

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