Hi all
I have a file with a bunch of perl regular expressions like so:
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/ #
bold
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/
b>''$3/ # italic bold
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ #
italic
These are all find/replace expressions delimited as '/search/replace/
# comment' where 'search' is the regular expression we're searching
for and 'replace' is the replacement expression.
Is there an easy and general way that I can split these perl-style
find-and-replace expressions into something I can use with Python, eg
re.sub('search' ,'replace',str) ?
I though generally it would be good enough to split on '/' but as you
see the <\/bmesses that up. I really don't want to learn perl
here :-)
Cheers
JP
8  2724 
John Pye wrote:
Hi all
I have a file with a bunch of perl regular expressions like so:
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/ #
bold
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/
b>''$3/ # italic bold
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ #
italic
These are all find/replace expressions delimited as '/search/replace/
# comment' where 'search' is the regular expression we're searching
for and 'replace' is the replacement expression.
Is there an easy and general way that I can split these perl-style
find-and-replace expressions into something I can use with Python, eg
re.sub('search' ,'replace',str) ?
I though generally it would be good enough to split on '/' but as you
see the <\/bmesses that up. I really don't want to learn perl
here :-)
Cheers
JP
This could be more general, in principal a perl regex could end with a
"\", e.g. "\\/", but I'm guessing that won't happen here.
pyfor p in perlish:
.... print p
....
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/b>''$3/
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/
pyimport re
pysplitter = re.compile(r'[^\\]/')
pyfor p in perlish:
.... print splitter.split( p)
....
['/(^|[\\s\\(])\\*([^ ].*?[^ ])\\*([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1'''$2''' $", '']
['/(^|[\\s\\(])\\_\\_([^ ].*?[^ ])\\_\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''<b>$2< \\/b>''$", '']
['/(^|[\\s\\(])\\_([^ ].*?[^ ])\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''$2''$" , '']
(I'm hoping this doesn't wrap!)
James
John Pye wrote:
I have a file with a bunch of perl regular expressions like so:
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/ #
bold
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/
b>''$3/ # italic bold
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ #
italic
These are all find/replace expressions delimited as '/search/replace/
# comment' where 'search' is the regular expression we're searching
for and 'replace' is the replacement expression.
Is there an easy and general way that I can split these perl-style
find-and-replace expressions into something I can use with Python, eg
re.sub('search' ,'replace',str) ?
I though generally it would be good enough to split on '/' but as you
see the <\/bmesses that up. I really don't want to learn perl
here :-)
How about matching all escaped chars and '/', and then throwing away the
former:
def split(s):
breaks = re.compile(r"(\ \.)|(/)").finditer (s)
left, mid, right = [b.start() for b in breaks if b.group(2)]
return s[left+1:mid], s[mid+1:right]
Peter
James Stroud wrote:
John Pye wrote:
>Hi all
I have a file with a bunch of perl regular expressions like so:
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/ #
bold
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/
b>''$3/ # italic bold
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ #
italic
These are all find/replace expressions delimited as '/search/replace/
# comment' where 'search' is the regular expression we're searching
for and 'replace' is the replacement expression.
Is there an easy and general way that I can split these perl-style
find-and-replace expressions into something I can use with Python, eg
re.sub('search ','replace',str ) ?
I though generally it would be good enough to split on '/' but as you
see the <\/bmesses that up. I really don't want to learn perl
here :-)
Cheers
JP
This could be more general, in principal a perl regex could end with a
"\", e.g. "\\/", but I'm guessing that won't happen here.
pyfor p in perlish:
... print p
...
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/b>''$3/
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/
pyimport re
pysplitter = re.compile(r'[^\\]/')
pyfor p in perlish:
... print splitter.split( p)
...
['/(^|[\\s\\(])\\*([^ ].*?[^ ])\\*([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1'''$2''' $", '']
['/(^|[\\s\\(])\\_\\_([^ ].*?[^ ])\\_\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''<b>$2< \\/b>''$", '']
['/(^|[\\s\\(])\\_([^ ].*?[^ ])\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''$2''$" , '']
(I'm hoping this doesn't wrap!)
James
I realized that threw away the closing parentheses. This is the correct
version:
pysplitter = re.compile(r'(? <!\\)/')
pyfor p in perlish:
.... print splitter.split( p)
....
['', '(^|[\\s\\(])\\*([^ ].*?[^ ])\\*([\\s\\)\\.\\,\\: \\;\\!\\?]|$)',
"$1'''$2''' $3", '']
['', '(^|[\\s\\(])\\_\\_([^ ].*?[^
])\\_\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$)', "$1''<b>$2< \\/b>''$3", '']
['', '(^|[\\s\\(])\\_([^ ].*?[^ ])\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$)',
"$1''$2''$3 ", '']
James
James Stroud wrote:
James Stroud wrote:
>John Pye wrote:
>>Hi all
I have a file with a bunch of perl regular expressions like so:
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/ #
bold
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/
b>''$3/ # italic bold
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ #
italic
These are all find/replace expressions delimited as '/search/replace/
# comment' where 'search' is the regular expression we're searching
for and 'replace' is the replacement expression.
Is there an easy and general way that I can split these perl-style
find-and-replace expressions into something I can use with Python, eg
re.sub('searc h','replace',st r) ?
I though generally it would be good enough to split on '/' but as you
see the <\/bmesses that up. I really don't want to learn perl
here :-)
Cheers
JP
This could be more general, in principal a perl regex could end with a
"\", e.g. "\\/", but I'm guessing that won't happen here.
pyfor p in perlish:
... print p
...
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/
/(^|[\s\(])\_\_([^ ].*?[^
])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/b>''$3/ /(^|[\s\(])\_([^ ].*?[^
])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ pyimport re
pysplitter = re.compile(r'[^\\]/')
pyfor p in perlish:
... print splitter.split( p)
...
['/(^|[\\s\\(])\\*([^ ].*?[^ ])\\*([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1'''$2'''$ ", '']
['/(^|[\\s\\(])\\_\\_([^ ].*?[^ ])\\_\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''<b>$2<\ \/b>''$", '']
['/(^|[\\s\\(])\\_([^ ].*?[^ ])\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''$2''$" , '']
(I'm hoping this doesn't wrap!)
James
I realized that threw away the closing parentheses. This is the correct
version:
pysplitter = re.compile(r'(? <!\\)/')
pyfor p in perlish:
... print splitter.split( p)
...
['', '(^|[\\s\\(])\\*([^ ].*?[^ ])\\*([\\s\\)\\.\\,\\: \\;\\!\\?]|$)',
"$1'''$2''' $3", '']
['', '(^|[\\s\\(])\\_\\_([^ ].*?[^
])\\_\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$)', "$1''<b>$2< \\/b>''$3", '']
['', '(^|[\\s\\(])\\_([^ ].*?[^ ])\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$)',
"$1''$2''$3 ", '']
There is another problem with escaped backslashes:
>>re.compile(r' (?<!\\)/').split(r"/abc\\/def/")
['', 'abc\\\\/def', '']
Peter
Peter Otten wrote:
James Stroud wrote:
>James Stroud wrote:
>>John Pye wrote:
Hi all
I have a file with a bunch of perl regular expressions like so:
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/ #
bold
/(^|[\s\(])\_\_([^ ].*?[^ ])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/
b>''$3/ # italic bold
/(^|[\s\(])\_([^ ].*?[^ ])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ #
italic
These are all find/replace expressions delimited as '/search/replace/
# comment' where 'search' is the regular expression we're searching
for and 'replace' is the replacement expression.
Is there an easy and general way that I can split these perl-style
find-and-replace expressions into something I can use with Python, eg
re.sub('sear ch','replace',s tr) ?
I though generally it would be good enough to split on '/' but as you
see the <\/bmesses that up. I really don't want to learn perl
here :-)
Cheers
JP
This could be more general, in principal a perl regex could end with a
"\", e.g. "\\/", but I'm guessing that won't happen here.
pyfor p in perlish:
... print p
...
/(^|[\s\(])\*([^ ].*?[^ ])\*([\s\)\.\,\:\;\!\ ?]|$)/$1'''$2'''$3/
/(^|[\s\(])\_\_([^ ].*?[^
])\_\_([\s\)\.\,\:\;\!\ ?]|$)/$1''<b>$2<\/b>''$3/ /(^|[\s\(])\_([^ ].*?[^
])\_([\s\)\.\,\:\;\!\ ?]|$)/$1''$2''$3/ pyimport re
pysplitter = re.compile(r'[^\\]/')
pyfor p in perlish:
... print splitter.split( p)
...
['/(^|[\\s\\(])\\*([^ ].*?[^ ])\\*([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1'''$2'''$" , '']
['/(^|[\\s\\(])\\_\\_([^ ].*?[^ ])\\_\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''<b>$2< \\/b>''$", '']
['/(^|[\\s\\(])\\_([^ ].*?[^ ])\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$',
"$1''$2''$" , '']
(I'm hoping this doesn't wrap!)
James
I realized that threw away the closing parentheses. This is the correct
version:
pysplitter = re.compile(r'(? <!\\)/')
pyfor p in perlish:
... print splitter.split( p)
...
['', '(^|[\\s\\(])\\*([^ ].*?[^ ])\\*([\\s\\)\\.\\,\\: \\;\\!\\?]|$)',
"$1'''$2'''$3" , '']
['', '(^|[\\s\\(])\\_\\_([^ ].*?[^
])\\_\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$)', "$1''<b>$2< \\/b>''$3", '']
['', '(^|[\\s\\(])\\_([^ ].*?[^ ])\\_([\\s\\)\\.\\,\\: \\;\\!\\?]|$)',
"$1''$2''$3" , '']
There is another problem with escaped backslashes:
>>>re.compile(r '(?<!\\)/').split(r"/abc\\/def/")
['', 'abc\\\\/def', '']
Peter
Yes, this would be a case of the expression (left side) ending with a
"\" as I mentioned above.
James
James Stroud wrote:
Yes, this would be a case of the expression (left side) ending with a
"\" as I mentioned above.
Sorry for not tracking the context.
Peter
John Pye wrote:
Is there an easy and general way that I can split these perl-style
find-and-replace expressions into something I can use with Python, eg
re.sub('search' ,'replace',str) ?
Another candidate:
>>re.compile(r" (?:/((?:\\.|[^/])*))").findall( r"/abc\\/def\/ghi//jkl")
['abc\\\\', 'def\\/ghi', '', 'jkl']
Peter
Thanks all for your suggestions on this. The 'splitter' idea was
particularly good, not something I'd thought of. Sorry for my late
reply.
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