Problem with win32pipe.popen 2

[diego]

I'm trying to understand how popen2 works. Found in this group, that
popen2.popen2 can cause trouble so i chose win32pipe.popen 2.

have a look a the listing of 2 files:
ekmain.py:
**************
import win32pipe

(stdin1, stdout1) = win32pipe.popen 2("test1.py")
stdin1.write("1 \n")
print stdout1.readlin es() # This will print the result.
**************

test1.py:
**************
a=raw_input("a= ")
print "***a=",a
print "finished!"
**************
i do not understand, why ekmain.py produces only following output:
['a=']

why is the stdin1.write("1 \n") command ignored?

i tried to find an answer in this group by searching through existing
article, but i had no success.

tanks for you help!
ernst
p.s.: i working with python 2.3 on win2000.

[Gabriel Genellina]

At Monday 15/1/2007 07:24, diego wrote:

>I'm trying to understand how popen2 works. Found in this group, that
popen2.popen 2 can cause trouble so i chose win32pipe.popen 2.

have a look a the listing of 2 files:
ekmain.py:
************ **
import win32pipe

(stdin1, stdout1) = win32pipe.popen 2("test1.py")
stdin1.write(" 1\n")
print stdout1.readlin es() # This will print the result.
************ **

test1.py:
************ **
a=raw_input("a =")
print "***a=",a
print "finished!"
************ **
i do not understand, why ekmain.py produces only following output:
['a=']

why is the stdin1.write("1 \n") command ignored?

Using popen4 instead of popen2 we get stderr too, and there is a traceback:
['a=Traceback (most recent call last):\n', ' File
"C:\\TEMP\\test 1.py", line 1,
in ?\n', ' a=raw_input("a= ")\n', 'EOFError: EOF when reading a line\n']

Using "python test1.py" as the popen4 argument we get the expected result:

C:\TEMP>main.py
['a=***a= 1\n', 'finished!\n']

(I don't know why)

>p.s.: i working with python 2.3 on win2000.

I used 2.4 on XPSP2.
--
Gabriel Genellina
Softlab SRL


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