how to use execfile with argument under windows

[baur79]

Hi everybody

i need to execute this command line (different source for n times)

filename.exe -type png -source sourcearg -file filename.png
i try with python (python script and filename.exe in same directory)

import os
.......
.......
execfile("filen ame.exe -type png -source sourcearg -file filename.png")

error output
IOError: [Errno 2] No such file or directory:"file name.exe -type png
-source sourcearg -file filename.png"

try
execfile("d:\pa thto\filename.e xe -type png -source sourcearg -file
filename.png")

error output
IOError: [Errno 2] No such file or directory:"d:\p athto\filename. exe
filename.exe -type png -source sourcearg -file filename.png"
please help to solve problem
thanks

[Matimus]

>
error output
IOError: [Errno 2] No such file or directory:"file name.exe -type png
-source sourcearg -file filename.png"

Use 'os.system' not 'execfile'. 'execfile' is for executing other
python scripts, not arbitrary command line.

Try this:

import os
....
....
os.system("file name.exe -type png -source sourcearg -file
filename.png")

try
execfile("d:\pa thto\filename.e xe -type png -source sourcearg -file
filename.png")

error output
IOError: [Errno 2] No such file or directory:"d:\p athto\filename. exe
filename.exe -type png -source sourcearg -file filename.png"

be careful with your '\'s they tend to get interpreted as escape
characters. You can prefix the string with an 'r', double them up or
use forward slashes.

One of the following should work:
r"d:\pathto\fil ename.exe -type png -source sourcearg -file
filename.png"
"d:\\pathto\\fi lename.exe -type png -source sourcearg -file
filename.png"
"d:/pathto/filename.exe -type png -source sourcearg -file filename.png"

[Peter Otten]

baur79 wrote:

i need to execute this command line (different source for n times)

filename.exe -type png -source sourcearg -file filename.png

i try with python (python script and filename.exe in same directory)

execfile("filen ame.exe -type png -source sourcearg -file filename.png")

That does not do what you think it does, see

http://docs.python.org/lib/built-in-funcs.html#l2h-26

You need os.system() or, for more complex applications, the subprocess
module.

Peter

[baur79]

os.system() solve my problem

thanks you guys and happy new year

with best wishes from Kazakhstan / Shymkent city / sodbisystems.kz
On Jan 2, 11:49 pm, Peter Otten <__pete...@web. dewrote:

baur79 wrote:

i need to execute this command line (different source for n times)

filename.exe -type png -source sourcearg -file filename.png
i try with python (python script and filename.exe in same directory)
execfile("filen ame.exe -type png -source sourcearg -file filename.png")T hat does not do what you think it does, see

http://docs.python.org/lib/built-in-funcs.html#l2h-26

You need os.system() or, for more complex applications, the subprocess
module.

Peter