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boost::python and automatic conversion for const std::string&

I have a lot of functions returning "const std::string&". Every time I
wrap one of those I have to do it like this:

class_.def("nam e", &someclass::bla ,
boost::python:: return_value_po licy<boost::pyt hon::copy_const _reference>()
);

Is there a way to register a return value conversion for "const
std::string&" so I can omit it every time I have to wrap functions
returning "const std::string&" ? I wan't those strings to be copied to
python as new strings (I don't want to hold a pointer to them).
Thanks

Dec 21 '06 #1
1 1974
On 21 Dec 2006 07:30:41 -0800, ga************* ***@gmail.com
<ga************ ****@gmail.comw rote:
I have a lot of functions returning "const std::string&". Every time I
wrap one of those I have to do it like this:

class_.def("nam e", &someclass::bla ,
boost::python:: return_value_po licy<boost::pyt hon::copy_const _reference>()
);

Is there a way to register a return value conversion for "const
std::string&" so I can omit it every time I have to wrap functions
returning "const std::string&" ? I wan't those strings to be copied to
python as new strings (I don't want to hold a pointer to them).
I am not sure, you'd better ask this question o Boost.Python mailing list:
http://mail.python.org/mailman/listinfo/c++-sig/
Py++, Boost.Python code generator, does it for you: http://tinyurl.com/ygwdkz
--
Roman Yakovenko
C++ Python language binding
http://www.language-binding.net/
Dec 21 '06 #2

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