I'm working on a basic web spider, and I'm having problems with the
urlparser.
This is the effected function:
------------------------------
def FindLinks(Websi te):
WebsiteLen = len(Website)+1
CurrentLink = ''
i = 0
SpliceStart = 0
SpliceEnd = 0
LinksString = ""
LinkQueue = open('C:/LinkQueue.txt', 'a')
while (i < WebsiteLen) and (i != -1):
#Debugging info
#print '-----'
#print 'Length = ' + str(WebsiteLen)
#print 'SpliceStart = ' + str(SpliceStart )
#print 'SpliceEnd = ' + str(SpliceEnd)
#print 'i = ' + str(i)
SpliceStart = Website.find('< a href="', (i+1))
SpliceEnd = (Website.find(' ">', SpliceStart))
ParsedURL =
urlparse((Websi te[SpliceStart+9:( SpliceEnd+1)]))
robotparser.set _url(ParsedURL. hostname + '/' +
'robots.txt')
robotparser.rea d()
if (robotparser.ca n_fetch("*",
(Website[SpliceStart+9:( SpliceEnd+1)])) == False):
i = i - 1
else:
LinksString = LinksString + "\n" +
(Website[SpliceStart+9:( SpliceEnd+1)])
LinksString = LinksString[:(len(LinksStri ng) - 1)]
#print 'found ' + LinksString
i = SpliceEnd
LinkQueue.write (LinksString)
LinkQueue.close ()
------------------------------
Sorry if it's uncommented. When I run my program, I get this error:
-----
Traceback (most recent call last):
File "C:/Documents and Settings/Andrew/Desktop/ScoutCode-0.09.py",
line 120, in <module>
FindLinks(Websi te)
File "C:/Documents and Settings/Andrew/Desktop/ScoutCode-0.09.py",
line 84, in FindLinks
robotparser.rea d()
File "C:\Program Files\Python25\ lib\robotparser .py", line 61, in read
f = opener.open(sel f.url)
File "C:\Program Files\Python25\ lib\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Program Files\Python25\ lib\urllib.py", line 451, in
open_file
return self.open_local _file(url)
File "C:\Program Files\Python25\ lib\urllib.py", line 465, in
open_local_file
raise IOError(e.errno , e.strerror, e.filename)
IOError: [Errno 2] The system cannot find the path specified:
'en.wikipedia.o rg\\robots.txt'
Note the last line 'en.wikipedia.o rg\\robots.txt' . I want
'en.wikipedia.o rg/robots.txt'! What am I doing wrong?
If this has been answered before, please just give me a link to the
proper thread. If you need more contextual code, I can post more. 3 1596
In <11************ **********@b28g 2000cwb.googleg roups.com>, i80and wrote:
return self.open_local _file(url)
File "C:\Program Files\Python25\ lib\urllib.py", line 465, in
open_local_file
raise IOError(e.errno , e.strerror, e.filename)
IOError: [Errno 2] The system cannot find the path specified:
'en.wikipedia.o rg\\robots.txt'
Note the last line 'en.wikipedia.o rg\\robots.txt' . I want
'en.wikipedia.o rg/robots.txt'! What am I doing wrong?
You don't have that file on you local computer. :-)
If you look at the messages above you'll see there's a function
`open_local_fil e()` involved. This function is chosen by `urllib` because
your path looks like a local file, i.e. it lacks the protocol information.
You don't want 'en.wikipedia.o rg/robots.txt', you want
'http://en.wikipedia.or g/robots.txt'!
Ciao,
Marc 'BlackJack' Rintsch
At Thursday 9/11/2006 20:23, i80and wrote:
>I'm working on a basic web spider, and I'm having problems with the urlparser. [...]
SpliceStart = Website.find('< a href="', (i+1))
SpliceEnd = (Website.find(' ">', SpliceStart))
ParsedURL = urlparse((Webs ite[SpliceStart+9:( SpliceEnd+1)]))
robotparser.set _url(ParsedURL. hostname + '/' + 'robots.txt' ) ----- Traceback (most recent call last):
File "C:/Documents and Settings/Andrew/Desktop/ScoutCode-0.09.py", line 120, in <module>
FindLinks(Websi te)
File "C:/Documents and Settings/Andrew/Desktop/ScoutCode-0.09.py", line 84, in FindLinks
robotparser.rea d()
File "C:\Program Files\Python25\ lib\robotparser .py", line 61, in read
f = opener.open(sel f.url)
File "C:\Program Files\Python25\ lib\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Program Files\Python25\ lib\urllib.py", line 451, in open_file
return self.open_local _file(url)
File "C:\Program Files\Python25\ lib\urllib.py", line 465, in open_local_fil e
raise IOError(e.errno , e.strerror, e.filename) IOError: [Errno 2] The system cannot find the path specified: 'en.wikipedia. org\\robots.txt '
Note the last line 'en.wikipedia.o rg\\robots.txt' . I want 'en.wikipedia. org/robots.txt'! What am I doing wrong?
No, you don't want 'en.wikipedia.o rg/robots.txt'; you want
'http://en.wikipedia.or g/robots.txt'
urllib treats the former as a file: request, here the \\ in the
normalized path.
You are parsing the link and then building a new URI using ONLY the
hostname part; that's wrong. Use urljoin(ParsedU RL, '/robots.txt') instead.
You may try Beautiful Soup for a better HTML parsing.
--
Gabriel Genellina
Softlab SRL
_______________ _______________ _______________ _____
Correo Yahoo!
Espacio para todos tus mensajes, antivirus y antispam ¡gratis!
¡Abrí tu cuenta ya! - http://correo.yahoo.com.ar
Thank you! Fixed my problem perfectly!
Gabriel Genellina wrote:
At Thursday 9/11/2006 20:23, i80and wrote:
I'm working on a basic web spider, and I'm having problems with the
urlparser.
[...]
SpliceStart = Website.find('< a href="', (i+1))
SpliceEnd = (Website.find(' ">', SpliceStart))
ParsedURL =
urlparse((Websi te[SpliceStart+9:( SpliceEnd+1)]))
robotparser.set _url(ParsedURL. hostname + '/' +
'robots.txt')
-----
Traceback (most recent call last):
File "C:/Documents and Settings/Andrew/Desktop/ScoutCode-0.09.py",
line 120, in <module>
FindLinks(Websi te)
File "C:/Documents and Settings/Andrew/Desktop/ScoutCode-0.09.py",
line 84, in FindLinks
robotparser.rea d()
File "C:\Program Files\Python25\ lib\robotparser .py", line 61, in read
f = opener.open(sel f.url)
File "C:\Program Files\Python25\ lib\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Program Files\Python25\ lib\urllib.py", line 451, in
open_file
return self.open_local _file(url)
File "C:\Program Files\Python25\ lib\urllib.py", line 465, in
open_local_file
raise IOError(e.errno , e.strerror, e.filename)
IOError: [Errno 2] The system cannot find the path specified:
'en.wikipedia.o rg\\robots.txt'
Note the last line 'en.wikipedia.o rg\\robots.txt' . I want
'en.wikipedia.o rg/robots.txt'! What am I doing wrong?
No, you don't want 'en.wikipedia.o rg/robots.txt'; you want
'http://en.wikipedia.or g/robots.txt'
urllib treats the former as a file: request, here the \\ in the
normalized path.
You are parsing the link and then building a new URI using ONLY the
hostname part; that's wrong. Use urljoin(ParsedU RL, '/robots.txt') instead.
You may try Beautiful Soup for a better HTML parsing.
--
Gabriel Genellina
Softlab SRL
_______________ _______________ _______________ _____
Correo Yahoo!
Espacio para todos tus mensajes, antivirus y antispam ¡gratis!
¡Abrí tu cuenta ya! - http://correo.yahoo.com.ar This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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