[Linux] Detect a key press

[Jia,Lu]

Hi all
I write a program to detect key press,but , why there is a *space*
before the character I typed.??

#!/usr/bin/env python

import sys
import tty
import termios

i = sys.stdin.filen o()
o = sys.stdout.file no()

backup = termios.tcgetat tr(i)

def loop():
while 1:
ch = sys.stdin.read( 1)
print "->%s"%ch
if ch == 'q':break

try:
tty.setraw(i)
loop()
finally:
termios.tcsetat tr(i, termios.TCSADRA IN, backup)

[hanumizzle]

On 5 Oct 2006 21:45:47 -0700, Jia,Lu <Ro*****@gmail. comwrote:

Hi all
I write a program to detect key press,but , why there is a *space*
before the character I typed.??

Puzzles me too, but I know this is really easy in Curses (on top of
that, it isn't specific to Linux; curses works on many terminals)

http://www.amk.ca/python/howto/curses/

-- Theerasak

[Sergei Organov]

"Jia,Lu" <Ro*****@gmail. comwrites:

Hi all
I write a program to detect key press,but , why there is a *space*
before the character I typed.??

There is none. The output I see when I type 1 2 q is:

->1
->2
->q

If that is what you see, the problem is in your

print "->%s"%ch

statement. It implicitly outputs '\n' at the end, and when terminal is
set in raw mode, this is not translated into '\r\n' as when terminal is
in canonical mode.

Try

print "->%s\r" % ch

or just

sys.stdout.writ e(ch)

-- Sergei.

[hanumizzle]

On 10/6/06, Sergei Organov <os*@javad.comw rote:

Try

print "->%s\r" % ch

or just

sys.stdout.writ e(ch)

Ah!