How to convert a timedelta object to a string?

[Carl J. Van Arsdall]

Basically I used the datetime module and timedelta objects to calculate
a difference between two times. Now I'm trying to figure out how I make
that time delta a string HH:MM:SS to show elapsed time. I've spent tons
of time looking at the module's documentation but I'm not seeing how
those methods will help me. Can anyone help me with this?

Here's what I'm trying to do, assum that resultsDict is a dictionary of
objects that have various pieces of information including a start time
and a stop time that are strings which I extracted from a file in an
earlier part of the program. I use regEx to split up the hours,
minutes, and seconds and create timedelta objects, which I then subtract
to get the different. What I need is to get the value in duration as
HH:MM:SS as a string:
#There's lots of other code above this, but I just need help with this part
timeRegex = re.compile(r'(\ d\d):(\d\d):(\d \d)')
for key in resultsDict.key s():
if resultsDict[key].stop != None:
parsedTime = timeRegex.match (resultsDict[key].start)
startDelta = datetime.timede lta(seconds=int (parsedTime.gro up(3)),
minutes=int(par sedTime.group(2 )), hours=int(parse dTime.group(1)) )
parsedTime = timeRegex.match (resultsDict[key].stop)
stopDelta = datetime.timede lta(seconds=int (parsedTime.gro up(3)),
minutes=int(par sedTime.group(2 )), hours=int(parse dTime.group(1)) )
duration = stopDelta - startDelta


Thanks,

-carl
--

Carl J. Van Arsdall
cv*********@mvi sta.com
Build and Release
MontaVista Software

[tobiah]

Carl J. Van Arsdall wrote:

Basically I used the datetime module and timedelta objects to calculate
a difference between two times. Now I'm trying to figure out how I make
that time delta a string HH:MM:SS

Oddly enough, str(tdobject) does what you want.

--
Posted via a free Usenet account from http://www.teranews.com

[Carl J. Van Arsdall]

tobiah wrote:

Carl J. Van Arsdall wrote:

>Basically I used the datetime module and timedelta objects to calculate
a difference between two times. Now I'm trying to figure out how I make
that time delta a string HH:MM:SS

Oddly enough, str(tdobject) does what you want.

Well, kinda, although I can work with this, str(tdobject) returns a
string that looks like:

-1 day, 7:34:32

Granted, I can parse that, I was looking for a way to just get the
actual duration. But for now I'll just parse the string, thanks.

-c

--

Carl J. Van Arsdall
cv*********@mvi sta.com
Build and Release
MontaVista Software

[Paul McGuire]

"Carl J. Van Arsdall" <cv*********@mv ista.comwrote in message
news:ma******** *************** *************** @python.org...

Basically I used the datetime module and timedelta objects to calculate a
difference between two times. Now I'm trying to figure out how I make
that time delta a string HH:MM:SS to show elapsed time. I've spent tons
of time looking at the module's documentation but I'm not seeing how those
methods will help me. Can anyone help me with this?
Here's what I'm trying to do, assum that resultsDict is a dictionary of
objects that have various pieces of information including a start time and
a stop time that are strings which I extracted from a file in an earlier
part of the program. I use regEx to split up the hours, minutes, and
seconds and create timedelta objects, which I then subtract to get the
different. What I need is to get the value in duration as HH:MM:SS as a
string:

From the Python console:

>>startTime = datetime.timede lta(seconds=45, minutes=22,hour s=10)
stopTime = datetime.timede lta(seconds=25, minutes=2,hours =4)
delta = startTime-stopTime
time.strftime ("%H:%M:%S",tim e.gmtime(delta. seconds))

'06:20:20'

-- Paul

[tobiah]

Well, kinda, although I can work with this, str(tdobject) returns a
string that looks like:

-1 day, 7:34:32

Oh yeah. I had tried it on a positive timedelta, which does give HH:MM:SS

--
Posted via a free Usenet account from http://www.teranews.com

[skip]

>>startTime = datetime.timede lta(seconds=45, minutes=22,hour s=10)
stopTime = datetime.timede lta(seconds=25, minutes=2,hours =4)
delta = startTime-stopTime
time.strftime ("%H:%M:%S",tim e.gmtime(delta. seconds))

'06:20:20'

Which, alas, will lose any subsecond resolution:

>>str(datetime. timedelta(secon ds=0.1))

'0:00:00.100000 '

Skip

[Bryan Olson]

Paul McGuire wrote:

"Carl J. Van Arsdall" wrote:

>Basically I used the datetime module and timedelta objects to calculate a
difference between two times. Now I'm trying to figure out how I make
that time delta a string HH:MM:SS to show elapsed time.

[...]

From the Python console:

>>>startTime = datetime.timede lta(seconds=45, minutes=22,hour s=10)
stopTime = datetime.timede lta(seconds=25, minutes=2,hours =4)
delta = startTime-stopTime
time.strftim e("%H:%M:%S",ti me.gmtime(delta .seconds))

'06:20:20'

On the other hand:

>>startTime = datetime.timede lta(hours=28)
stopTime = datetime.timede lta(hours=4)
delta = startTime-stopTime
time.strftime ("%H:%M:%S",tim e.gmtime(delta. seconds))

'00:00:00'
--
--Bryan