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How do I catch ExpatError exception?

Hey!

I am getting this exception.

xml.parsers.exp at.ExpatError

But I am not able to catch it with "except
xml.parsers.exp at.ExpatError:" It says "NameError: global name 'xml' is
not defined".

I am also not able to catch it with "except ExpatError:" Gives
"NameError: global name 'xml' is not defined"

How do I catch it? (I am parsing an xml file)

Also, how do I get the line number where an exception was thrown?

Thanks.

Aug 16 '06 #1
3 5564
Shuaib wrote:
Hey!

I am getting this exception.

xml.parsers.exp at.ExpatError

But I am not able to catch it with "except
xml.parsers.exp at.ExpatError:" It says "NameError: global name 'xml' is
not defined".

I am also not able to catch it with "except ExpatError:" Gives
"NameError: global name 'xml' is not defined"

How do I catch it? (I am parsing an xml file)
Have you imported xml.parsers.exp at to get it properly scoped?
>
Also, how do I get the line number where an exception was thrown?
Try looking at the 'sys.exc_info' and the 'traceback' module
documentation. Also see Python Cookbook recipe Recipe 8.6. Getting More
Information from Tracebacks (Bryn Keller)
Thanks.
Aug 16 '06 #2
Shuaib wrote:
Hey!

I am getting this exception.

xml.parsers.exp at.ExpatError

But I am not able to catch it with "except
xml.parsers.exp at.ExpatError:" It says "NameError: global name 'xml' is
not defined".

I am also not able to catch it with "except ExpatError:" Gives
"NameError: global name 'xml' is not defined"

How do I catch it? (I am parsing an xml file)
import xml.parsers.exp at

That way the interpreter will be able to resolve the reference to the
exception.
Also, how do I get the line number where an exception was thrown?
#
# Exception traceback test
#
def r():
return 1/0

try:
print r()
except:
import sys
t, v, tb = sys.exc_info()

print "exception on line", tb.tb_lineno

regards
Steve
--
Steve Holden +44 150 684 7255 +1 800 494 3119
Holden Web LLC/Ltd http://www.holdenweb.com
Skype: holdenweb http://holdenweb.blogspot.com
Recent Ramblings http://del.icio.us/steve.holden

Aug 17 '06 #3
Steve Holden wrote:
import xml.parsers.exp at

Thanks, that worked.

>
def r():
return 1/0

try:
print r()
except:
import sys
t, v, tb = sys.exc_info()

print "exception on line", tb.tb_lineno
How do I get the helpful text that is thrown with the exception? Like
if the exception is " IOError: [Errno 2] No such file or directory:
'out.xml' "

How do I get the the text after IOError: ?

Thanks again.

Aug 17 '06 #4

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