Ik have an uml file I want to read with readlines. I have the following
code:
infile = open("out2.txt" ,"r")
for line in infile.readline s():
print line
The print statement just gives the data, not the uml headings. Is there
a solution which also gives the uml headings. 4 1463
wscrsurfdude wrote:
Ik have an uml file
What is an "uml file" ?
I want to read with readlines. I have the following
code:
infile = open("out2.txt" ,"r")
for line in infile.readline s():
print line
The print statement just gives the data,
You get what can be read from the file when opened as a text file and
read line by line. Be sure that neither file.readlines( ) nor print won't
invent data that are not in the file.
not the uml headings. Is there
a solution which also gives the uml headings.
If they're not in the file, obviously, no - whatever "uml heading" might
be.
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in 'o****@xiludom. gro'.split('@')])"
Sorry it is so hot in here, I make mistakes, I meant it to be an xml
file. But still sthe same problem
wscrsurfdude wrote:
Ik have an xml file I want to read with readlines. I have the following
code:
infile = open("out2.txt" ,"r")
for line in infile.readline s():
print line
The print statement just gives the data, not the xml headings. Is there
a solution which also gives the uml headings.
wscrsurfdude wrote:
Sorry it is so hot in here, I make mistakes, I meant it to be an xml
file. But still sthe same problem
>
>>Ik have an xml file I want to read with readlines. I have the following code: infile = open("out2.txt" ,"r") for line in infile.readline s(): print line
The print statement just gives the data, not the xml headings.
Still the same question : what is an "xml heading" ? xml is a textual
markup language. It has elements ('tags') which can have content and
attributes - but nothing like "headings".
file.readlines( ) iterates over lines of a opened text file - it doesn't
give a damn about what this text is, xml, python code, csv or whatever.
If your file contains xml and you want to interpret the xml, you have to
use a xml parser.
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in 'o****@xiludom. gro'.split('@')])" This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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