I know about os.path.split() , but Is there any standard function for
"fully" splitting a file's pathname? A function that is the opposite of
the os.path.join() function? For example:
>>ret = myster_function (./foo/bar/moo/lar/myfile.txt) print ret
['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']
In the meanwhile, I'll do this by hand. I'm just curious if there is a
standard way to do this. 3 1373
I don't know if it's "standard," but why not just:
dir = './foo/bar/moo/lar/myfile.txt'
dir.split('/')
['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']
rd
tac-tics wrote:
I know about os.path.split() , but Is there any standard function for
"fully" splitting a file's pathname? A function that is the opposite of
the os.path.join() function? For example:
>ret = myster_function (./foo/bar/moo/lar/myfile.txt) print ret
['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']
In the meanwhile, I'll do this by hand. I'm just curious if there is a
standard way to do this.
Simple function using os.path.split (so it should be fairly
compatible):
def split(path):
h,t = os.path.split(p ath)
if h == path:
return [h]
else:
return split(h) + [t]
You could throw in os.path.splitdr ive and os.path.splitun c, if you
wanted to be really complete.
Iain
BartlebyScriven er wrote:
I don't know if it's "standard," but why not just:
dir = './foo/bar/moo/lar/myfile.txt'
dir.split('/')
['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']
rd
There's also os.path.sep, from the docs: "The character used by the
operating system to separate pathname components."
But a recursive function like the one Iain King posted is likely the
best way to go.
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