an error in commented code?

[John Salerno]

Here's my code, with the error following it:

props = ['A', 'B', 'C', 'D']
group1 = ['C', 'A', 'D', 'B', 17]
group2 = ['A', 'B', 'D', 'C', 32]
group3 = ['D', 'B', 'C', 'A', 34]
group4 = ['B', 'A', 'C', 'D', 17]

# Submitter: Michael Davies
def all_perms(str):
if len(str) <=1:
yield str
else:
for perm in all_perms(str[1:]):
for i in range(len(perm) +1):
#nb str[0:1] works in both string and list contexts
yield perm[:i] + str[0:1] + perm[i:]

def checkOrder(x, y):
x_votes = 0
y_votes = 0

if group1.index(x) < group1.index(y) :
x_votes += group1[4]
else:
y_votes += group1[4]

if group2.index(x) < group2.index(y) :
x_votes += group2[4]
else:
y_votes += group2[4]

if group3.index(x) < group3.index(y) :
x_votes += group3[4]
else:
y_votes += group3[4]

if group4.index(x) < group4.index(y) :
x_votes += group4[4]
else:
y_votes += group4[4]

if x_votes > y_votes:
return x
else:
return y

for order in all_perms(props ):
# if reduce(checkOrd er, order) == 'A':
# print 'A wins:'
# print order
# if reduce(checkOrd er, order) == 'B':
# print 'B wins:'
# print order
if reduce(checkOrd er, order) == 'C':
print 'C wins:'
print order
# if reduce(checkOrd er, order) == 'D':
# print 'D wins:'
# print order

*** Error in script or command!

Traceback (most recent call last):
File "C:\Python24\my scripts\ecco\1-1-1.py", line 60
# print order
^
SyntaxError: invalid syntax

Line 60 also happens to be the very last line, which is commented. I've
tried a couple of different things to see if it's a whitespace problem,
but it doesn't seem to be. I'm just confused why it detects an error in
the commented code anyway.

Thanks.

[André]

Tried adding a "\n" (i.e. press the enter key) after the last line
(i.e. right after the word "order") so that you don't end with a
comment.

André

[John Salerno]

André wrote:

Tried adding a "\n" (i.e. press the enter key) after the last line
(i.e. right after the word "order") so that you don't end with a
comment.

André

Weird, but it worked! :)

[Gerard Flanagan]

John Salerno wrote:

Here's my code, with the error following it:

props = ['A', 'B', 'C', 'D']
group1 = ['C', 'A', 'D', 'B', 17]
group2 = ['A', 'B', 'D', 'C', 32]
group3 = ['D', 'B', 'C', 'A', 34]
group4 = ['B', 'A', 'C', 'D', 17]

# Submitter: Michael Davies
def all_perms(str):
if len(str) <=1:
yield str
else:
for perm in all_perms(str[1:]):
for i in range(len(perm) +1):
#nb str[0:1] works in both string and list contexts
yield perm[:i] + str[0:1] + perm[i:]

def checkOrder(x, y):
x_votes = 0
y_votes = 0

if group1.index(x) < group1.index(y) :
x_votes += group1[4]
else:
y_votes += group1[4]

if group2.index(x) < group2.index(y) :
x_votes += group2[4]
else:
y_votes += group2[4]

if group3.index(x) < group3.index(y) :
x_votes += group3[4]
else:
y_votes += group3[4]

if group4.index(x) < group4.index(y) :
x_votes += group4[4]
else:
y_votes += group4[4]

if x_votes > y_votes:
return x
else:
return y

for order in all_perms(props ):
# if reduce(checkOrd er, order) == 'A':
# print 'A wins:'
# print order
# if reduce(checkOrd er, order) == 'B':
# print 'B wins:'
# print order
if reduce(checkOrd er, order) == 'C':
print 'C wins:'
print order
# if reduce(checkOrd er, order) == 'D':
# print 'D wins:'
# print order

I don't think you need all those 'ifs'.

groups = [group1, group2, group3, group4]

def checkOrder(x, y):
x_votes = 0
y_votes = 0
for group in groups:
if group.index(x) < group.index(y):
x_votes += group[4]
else:
y_votes += group[4]

for order in all_perms(props ):
winner = reduce(checkOrd er, order)
print '%s wins!' % winner
print order

Gerard

[John Salerno]

Gerard Flanagan wrote:

I don't think you need all those 'ifs'.

groups = [group1, group2, group3, group4]

def checkOrder(x, y):
x_votes = 0
y_votes = 0
for group in groups:
if group.index(x) < group.index(y):
x_votes += group[4]
else:
y_votes += group[4]

for order in all_perms(props ):
winner = reduce(checkOrd er, order)
print '%s wins!' % winner
print order

Nice. I was shuddering as I copy and pasted each if block. :)