hi,
i'm trying to get the date of the day one month ago.
for example:
today = 12.apr.2006
one-month-ago = 12.mar.2006
so:
one-month-ago(12.apr.2006 ) = 12.mar.2006
of course sometimes it gets more complicated, like:
one-month-ago(31.mar.2006 )
or
one-month-ago(1.jan.2006)
the datetime.timede lta objects only work with hours or days or weeks,
not month (i understand why)...
but is there a way to calculate this in python?
i really don't want to calculate it by myself :-))
thanks,
gabor 4 10112
gabor wrote: hi,
i'm trying to get the date of the day one month ago.
for example:
today = 12.apr.2006 one-month-ago = 12.mar.2006
so:
one-month-ago(12.apr.2006 ) = 12.mar.2006
of course sometimes it gets more complicated, like:
one-month-ago(31.mar.2006 )
or
one-month-ago(1.jan.2006)
the datetime.timede lta objects only work with hours or days or weeks, not month (i understand why)...
but is there a way to calculate this in python?
i really don't want to calculate it by myself :-))
It is application specific. So how *do* you want
one-month-ago(31.mar.2006 ) or one-month-ago(28.feb.2006 ) to work? No one
can know but you.
--
hilsen/regards Max M, Denmark http://www.mxm.dk/
IT's Mad Science
Phone: +45 66 11 84 94
Mobile: +45 29 93 42 96
gabor wrote: hi,
i'm trying to get the date of the day one month ago.
for example:
today = 12.apr.2006 one-month-ago = 12.mar.2006
dateutil has one implementation of this: http://labix.org/python-dateutil
Kent
Max M wrote: gabor wrote: hi,
i'm trying to get the date of the day one month ago.
for example:
today = 12.apr.2006 one-month-ago = 12.mar.2006
so:
one-month-ago(12.apr.2006 ) = 12.mar.2006
of course sometimes it gets more complicated, like:
one-month-ago(31.mar.2006 )
or
one-month-ago(1.jan.2006)
the datetime.timede lta objects only work with hours or days or weeks, not month (i understand why)...
but is there a way to calculate this in python?
i really don't want to calculate it by myself :-))
It is application specific. So how *do* you want one-month-ago(31.mar.2006 ) or one-month-ago(28.feb.2006 ) to work? No one can know but you.
well, give me a solution for ANY behaviour :)
or, let's specify it then:
i want the day that you get by intutively saying "one month ago". means
usually picking the same day in the previous month. if that day does not
exist, i want the nearest day that exist and was BEFORE the nonexistent day.
one-month-ago(31.mar.2006 ) = 28.feb.2006
one-month-ago(28.feb.2006 ) = 28.jan.2006
so, now that we have a spec, is there a way to achieve this in python
without writing the algorithm by myself?
thanks,
gabor
On Wed, 12 Apr 2006 13:42:15 +0200, rumours say that gabor
<ga***@nekomanc er.net> might have written: i want the day that you get by intutively saying "one month ago". means usually picking the same day in the previous month. if that day does not exist, i want the nearest day that exist and was BEFORE the nonexistent day.
one-month-ago(31.mar.2006 ) = 28.feb.2006 one-month-ago(28.feb.2006 ) = 28.jan.2006
def submonth(d):
year, month= d.year, d.month
if month == 1:
year-= 1; month= 12
else:
month-= 1
try:
return d.replace(year= year, month=month)
except ValueError:
return d.replace(day=1 ) - datetime.timede lta(1) submonth(dateti me.date(2006,3, 31))
datetime.date(2 006, 2, 28) submonth(dateti me.date(2006,2, 28))
datetime.date(2 006, 1, 28)
--
TZOTZIOY, I speak England very best.
"Dear Paul,
please stop spamming us."
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