How do i fill 1 byte and 4 bytes in a single array? This array contains
packet information.
Python code...
from array import *
size = 526
pData = array("B", '\0'* 526)
# Destination MAC address
destAddress = FFFFFFFFFFFF
for i in range(0, len(destAddress ), 2):
pData[i/2] = int(destAddress[i:i+2], 16)
pattern = 0xAAAAAAAA
for i in range( 512):
pData[i+6] = long(pattern, 16)
print pData
OverflowError: long int too large to covert to int
def test(pData.buff er_info()[0])
....
....
Any help appreciated.
-Ashton
1  1757 
You probably want to look at using struct.pack. That will allow you
to back heterogenious groups of data into a string that can be saved
to disk or sent over the network. It also does a really good job of
taking care of byte order for you(if you tell it to).
-Chris
On 8 Jun 2005 10:40:43 -0700, as*****@gmail.c om <do*****@gmail. com> wrote: How do i fill 1 byte and 4 bytes in a single array? This array contains
packet information.
Python code...
from array import *
size = 526
pData = array("B", '\0'* 526)
# Destination MAC address
destAddress = FFFFFFFFFFFF
for i in range(0, len(destAddress ), 2):
pData[i/2] = int(destAddress[i:i+2], 16)
pattern = 0xAAAAAAAA
for i in range( 512):
pData[i+6] = long(pattern, 16)
print pData
OverflowError: long int too large to covert to int
def test(pData.buff er_info()[0])
....
....
Any help appreciated.
-Ashton
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Christopher Lambacher la******@comput er.org This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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