Calculating Inflation, retirement and cost of living adjustmentsover 30 years

[rbt]

Is this mathematically correct?
def inflation():
start = int(str.strip(r aw_input("How much money do you need each
month at the start of retirement: ")))
inflation = float(str.strip (raw_input("Wha t will inflation average
over the next 30 years(.03, .04, etc): ")))

for x in xrange(30):
start = start*inflation +start
print start

inflation()

[John Machin]

rbt wrote:

Is this mathematically correct?
def inflation():
start = int(str.strip(r aw_input("How much money do you need each
month at the start of retirement: ")))
inflation = float(str.strip (raw_input("Wha t will inflation average
over the next 30 years(.03, .04, etc): ")))

for x in xrange(30):
start = start*inflation +start
print start

inflation()

The *arithmetic* is tedious but "correct" -- we won't concern ourselves
with rounding errors here. The *mathematics* might be better expressed as

required = start * (1.0 + inflation_rate_ per_period) ** number_of_perio ds

[Roel Schroeven]

rbt wrote:

Is this mathematically correct?
def inflation():
start = int(str.strip(r aw_input("How much money do you need each
month at the start of retirement: ")))
inflation = float(str.strip (raw_input("Wha t will inflation average
over the next 30 years(.03, .04, etc): ")))

for x in xrange(30):
start = start*inflation +start
print start

inflation()

I'm not really familiar with financial calculations, but it looks
correct. There's a faster way though, since repeated multiplication is
the same as taking the power with the number of years as the exponent:

def inflation():
start = ... # same as before
inflation = ... # same as before

print start * (1+inflation)** 30
--
If I have been able to see further, it was only because I stood
on the shoulders of giants. -- Isaac Newton

Roel Schroeven