Hello,
on windows python 2.4.1 I have the following problem s = 'D:\\music\\D\\ Daniel Lanois\\For the beauty of Wynona' print s
D:\music\D\Dani el Lanois\For the beauty of Wynona t = 'D:\\music\\D\\ ' print t
D:\music\D\ s.lstrip(t)
'aniel Lanois\\For the beauty of Wynona'
why does lstrip strip the D of Daniel Lanois also?
thanks in advance
joram 4 3329
"joram gemma" <jo*********@pa ndora.be> wrote: Hello,
on windows python 2.4.1 I have the following problem
s = 'D:\\music\\D\\ Daniel Lanois\\For the beauty of Wynona' print s D:\music\D\Dani el Lanois\For the beauty of Wynona t = 'D:\\music\\D\\ ' print t D:\music\D\ s.lstrip(t) 'aniel Lanois\\For the beauty of Wynona'
why does lstrip strip the D of Daniel Lanois also?
Because the argument to lstrip is a *set of characters* to delete, not a
string to delete. The string you passed it contained a 'D', so the 'D' got
stripped. Imagine lstrip was defined something like:
def lstrip (self, chars):
temp = self
while temp[0] in chars:
temp = temp[1:]
return temp
and you should get the idea. I don't think the documentation for lstrip
really makes this clear. I'm going to open a bug on the doc, and see what
happens :-)
I suspect what you really want to be doing is using the os.path module.
It's got functions for tearing pathnames apart into components, and hides
all the uglyness like whether / or \ is the directory separator on your
particular system.
On Sun, 15 May 2005 15:24:25 +0200, "joram gemma" <jo*********@pa ndora.be> wrote: Hello,
on windows python 2.4.1 I have the following problem
s = 'D:\\music\\D\\ Daniel Lanois\\For the beauty of Wynona' print sD:\music\D\Dan iel Lanois\For the beauty of Wynona t = 'D:\\music\\D\\ ' print tD:\music\D\ s.lstrip(t)'aniel Lanois\\For the beauty of Wynona' why does lstrip strip the D of Daniel Lanois also?
Because the lstrip argument is a set of characters in the form of
a string, not a single substring to replace from the left. Note:
(repeating your example to start with) s = 'D:\\music\\D\\ Daniel Lanois\\For the beauty of Wynona' print s
D:\music\D\Dani el Lanois\For the beauty of Wynona t = 'D:\\music\\D\\ ' print t
D:\music\D\ s.lstrip(t)
'aniel Lanois\\For the beauty of Wynona'
Now we make an equivalent lstrip argument from your t argument t2 = ''.join(sorted( set(t))) print t2
:D\cimsu
Note that there is only one of each character in t2 (e.g. 'D' and '\\')
And the result is the same for t and t2:
s.lstrip(t)
'aniel Lanois\\For the beauty of Wynona' s.lstrip(t2)
'aniel Lanois\\For the beauty of Wynona'
If you want to replace an exact prefix, a regex could be a simple way
to get the startswith check and replace in one whack.
Regards,
Bengt Richter
On Sun, 15 May 2005 15:24:25 +0200, "joram gemma"
<jo*********@pa ndora.be> declaimed the following in comp.lang.pytho n: why does lstrip strip the D of Daniel Lanois also?
Because lstrip() does NOT strip a PREFIX string.
The characters you supply, individually, are considered
"strippable ". help("".lstr ip)
Help on built-in function lstrip:
lstrip(...)
S.lstrip([chars]) -> string or unicode
Return a copy of the string S with leading whitespace removed.
If chars is given and not None, remove characters in chars instead.
If chars is unicode, S will be converted to unicode before stripping
lstrip() will remove characters until it finds one that is NOT
IN the argument.
s ="D:\\music\\D\ \Daniel Lanois\\For the beauty of Wynona" t ="\\Dmscui:" s.lstrip(t)
'aniel Lanois\\For the beauty of Wynona'
"a" is the first character that does not appear in string t; if you want
to remove a fixed prefix, you need to match on the string itself.
t = "D:\\music\\D\\ " if s.startswith(t) :
.... s = s[len(t):]
.... s
'Daniel Lanois\\For the beauty of Wynona'
-- =============== =============== =============== =============== == < wl*****@ix.netc om.com | Wulfraed Dennis Lee Bieber KD6MOG < wu******@dm.net | Bestiaria Support Staff < =============== =============== =============== =============== == < Home Page: <http://www.dm.net/~wulfraed/> < Overflow Page: <http://wlfraed.home.ne tcom.com/> <
Roy Smith: I suspect what you really want to be doing is using the os.path
module. It's got functions for tearing pathnames apart into components, and
hides all the uglyness like whether / or \ is the directory separator on
your particular system.
I thought so too, maybe this will help. d = 'D:\\music\\D\\ Daniel Lanois\\For the beauty of Wynona' import os os.path.split(d )
('D:\\music\\D\ \Daniel Lanois', 'For the beauty of Wynona') os.path.basenam e(d)
'For the beauty of Wynona' os.path.dirname (d)
'D:\\music\\D\\ Daniel Lanois' os.path.splitex t(d)
('D:\\music\\D\ \Daniel Lanois\\For the beauty of Wynona', '') os.path.splitdr ive(d)
('D:', '\\music\\D\\Da niel Lanois\\For the beauty of Wynona') os.path.split(d )
('D:\\music\\D\ \Daniel Lanois', 'For the beauty of Wynona') q = os.path.split(d ) q
('D:\\music\\D\ \Daniel Lanois', 'For the beauty of Wynona') q = os.path.split(q[0]) q
('D:\\music\\D' , 'Daniel Lanois') q = os.path.split(q[0]) q
('D:\\music', 'D')
And another idea might be to do a split using os.sep: import os d = 'D:\\music\\D\\ Daniel Lanois\\For the beauty of Wynona' d.split(os.sep)
['D:', 'music', 'D', 'Daniel Lanois', 'For the beauty of Wynona']
Hth,
M.E.Farmer This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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