Hello list,
gzip documentation states that calling the .close() method on a GzipFile
doesn't really close it. If I'm really through with it, what's the best
way to close it? I'm using Python2.2 (but the gzip module doesn't seem to
be any different from 2.4).
Here's my code snippet, if it's relevant:
oldfileobj= file(oldfile, 'r')
oldmd5 = md5.new()
tellold = 0
tellnew = 1
while tellold != tellnew:
line = oldfileobj.read line()
tellold = tellnew
tellnew = oldfileobj.tell ()
oldmd5.update(l ine)
At this point, I'm finished reading the file, and would like to properly
close it. Should I just del oldfileobj?
Also, while I'm asking, does anyone know a better way to iterate through a
gzipped file? The gzip module doesn't support iteration, nor xreadlines.
I need to avoid reading the entire file contents into memory, so I can't
use "for line in oldfileobj.read lines()"
Thanks for the pointers.
Justin Guerin
0  1049  This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
by: Greg Bakken |
last post by:
I am writing a python program that recieves 'compressed and encoded'
strings from another piece of software. I can successfully uncompress
and decode the strings via
import base64, zlib
def getString(s):
s = base64.decodestring(s)
s = zlib.decompress(s, -15)
return s
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last post by:
I have a tar file. The content of the file are as following.
rohits@sandman 12-08-04 $ tar tvf 20041208.tar
drwxr-xr-x root/root 0 2004-12-08 21:39:19 20041208/
-rw-r--r-- root/root 1576 2004-12-08 21:39:19 20041208/README
drwxr-xr-x root/root 0 2004-12-08 21:27:31
20041208/snapshot_01/
-rw-r--r-- was/was 103010606 2004-12-08 16:37:38
20041208/snapshot_01/tpv-2004 1208-1350.xml.gz
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by: Xah Lee |
last post by:
today i need to use Python to decompress gzip files.
since i'm familiar with Python doc and have 10 years of computing
experience with 4 years in unix admin and perl, i have quickly located
the official doc:
http://python.org/doc/2.4.1/lib/module-gzip.html
but after a minute of scanning, please someone tell me what the fuck is
it talking about?
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by: Bill |
last post by:
I've written a small program that, in part, reads in a file and parses
it. Sometimes, the file is gzipped. The code that I use to get the
file object is like so:
if filename.endswith(".gz"):
file = GzipFile(filename)
else:
file = open(filename)
Then I parse the contents of the file in the usual way (for line in
|
by: bob |
last post by:
I'm using the code below to read the zipped, base64 encoded WMF file
saved in an XML file with "Save as XML" from MS Word. As the "At this
point" comment shows, I know that the base64 decoding is going fine,
but unzipping from the decodedVersion StringIO object isn't getting me
anything, because the len(fileContent) call is returning 0. Any
suggestions?
thanks,
Bob
| | |
by: Nader |
last post by:
Hello,
I have a gzip file and I try to read from this file withe the next
statements:
gunziped_file = gzip.GzipFile('gzip-file')
input_file = open(gunziped_file,'r')
But I get the nezt error message:
|
by: Nader |
last post by:
Hello,
I have a gzip file and I try to read from this file withe the next
statements:
gunziped_file = gzip.GzipFile('gzip-file')
input_file = open(gunziped_file,'r')
But I get the nezt error message:
|
by: Gabriel Genellina |
last post by:
En Wed, 19 Nov 2008 13:25:03 -0200, Barak, Ron <Ron.Barak@lsi.com>
escribió:
Note *where* the exception is raised. Until something is actually read, no
check is made for the file format.
--
Gabriel Genellina
|
by: Barak, Ron |
last post by:
Thanks Gabriel,
Okay, I get it: I was under the impression that the format check would be done on the open.
Bye,
Ron.
-----Original Message-----
From: Gabriel Genellina
Sent: Thursday, November 20, 2008 02:06
To: python-list@python.org
Subject: Re: Why is try...except in my code not working (gzip/text files) ?
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