I used the following method to remove duplicate items in a list and
got confused by the error. a
[[1, 2], [1, 2], [2, 3]] noDups=[ u for u in a if u not in locals()['_[1]'] ]
Traceback (most recent call last):
File "<interacti ve input>", line 1, in ?
TypeError: iterable argument required 4 3633
Shi Mu wrote: I used the following method to remove duplicate items in a list and got confused by the error.
a [[1, 2], [1, 2], [2, 3]] noDups=[ u for u in a if u not in locals()['_[1]'] ] Traceback (most recent call last): File "<interacti ve input>", line 1, in ? TypeError: iterable argument required a
[[1, 2], [1, 2], [2, 3]] c=[] for x in a:
.... if x not in c: c.append(x)
.... c
[[1, 2], [2, 3]]
or (Python 2.4)
a
[[1, 2], [1, 2], [2, 3]] set([frozenset(u) for u in a])
set([frozenset([1, 2]), frozenset([2, 3])])
hth Daniel
Shi Mu wrote: I used the following method to remove duplicate items in a list and got confused by the error.
a [[1, 2], [1, 2], [2, 3]] noDups=[ u for u in a if u not in locals()['_[1]'] ] Traceback (most recent call last): File "<interacti ve input>", line 1, in ? TypeError: iterable argument required a
[[1, 2], [1, 2], [2, 3]] c=[] for x in a:
.... if x not in c: c.append(x)
.... c
[[1, 2], [2, 3]]
or (Python 2.4)
a
[[1, 2], [1, 2], [2, 3]] set([frozenset(u) for u in a])
set([frozenset([1, 2]), frozenset([2, 3])])
hth Daniel
On Mon, 21 Nov 2005 02:49:56 -0800, Shi Mu wrote: I used the following method to remove duplicate items in a list and got confused by the error.
a [[1, 2], [1, 2], [2, 3]] noDups=[ u for u in a if u not in locals()['_[1]'] ]
Traceback (most recent call last): File "<interacti ve input>", line 1, in ? TypeError: iterable argument required
Confused by the error? I'm confused by your code!!!
If you want to remove duplicate items in a list, try something like this:
def remove_dups(L):
"""Removes duplicate items from list L in place."""
# Work backwards from the end of the list.
for i in range(len(L)-1, -1, -1):
# Check to see if the current item exists elsewhere in
# the list, and if it does, delete it.
if L[i] in L[:i]:
del L[i]
Instead of deleting duplicate items in place, we can create a new list
containing just the unique items:
def unique_items(L) :
"""Returns a new list containing the unique items from L."""
U = []
for item in L:
if item not in U:
U.append(item)
return U
The trick you are trying to do with _ is undocumented and, even if you get
it to work *now*, is probably not going to work in the future. Don't do it.
--
Steven.
On Mon, 21 Nov 2005 02:49:56 -0800, Shi Mu wrote: I used the following method to remove duplicate items in a list and got confused by the error.
a [[1, 2], [1, 2], [2, 3]] noDups=[ u for u in a if u not in locals()['_[1]'] ]
Traceback (most recent call last): File "<interacti ve input>", line 1, in ? TypeError: iterable argument required
Confused by the error? I'm confused by your code!!!
If you want to remove duplicate items in a list, try something like this:
def remove_dups(L):
"""Removes duplicate items from list L in place."""
# Work backwards from the end of the list.
for i in range(len(L)-1, -1, -1):
# Check to see if the current item exists elsewhere in
# the list, and if it does, delete it.
if L[i] in L[:i]:
del L[i]
Instead of deleting duplicate items in place, we can create a new list
containing just the unique items:
def unique_items(L) :
"""Returns a new list containing the unique items from L."""
U = []
for item in L:
if item not in U:
U.append(item)
return U
The trick you are trying to do with _ is undocumented and, even if you get
it to work *now*, is probably not going to work in the future. Don't do it.
--
Steven. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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