Is there a way to do this as a list comprehension? def recu(alist, blist=[]):
.... if len(alist)==0: print blist
.... for i in range(len(alist )):
.... blist.append(al ist.pop(i))
.... recu(alist, blist)
.... alist.insert(i, blist.pop())
recu(list("abc" ))
['a', 'b', 'c']
['a', 'c', 'b']
['b', 'a', 'c']
['b', 'c', 'a']
['c', 'a', 'b']
['c', 'b', 'a']
Cheers
SimonVC
keywords: python recursive permutations algorithm combination jumble 1  4206 
"SimonVC" <py****@simon.v c> wrote in message
news:fa******** *************** ***@posting.goo gle.com... Is there a way to do this as a list comprehension?
def recu(alist, blist=[]): ... if len(alist)==0: print blist
... for i in range(len(alist )):
... blist.append(al ist.pop(i))
... recu(alist, blist)
... alist.insert(i, blist.pop())
recu(list("abc" ))
['a', 'b', 'c']
['a', 'c', 'b']
['b', 'a', 'c']
['b', 'c', 'a']
['c', 'a', 'b']
['c', 'b', 'a']
Cheers
SimonVC
keywords: python recursive permutations algorithm combination jumble
Perhaps this cookbook recipe would be of help to you: http://aspn.activestate.com/ASPN/Coo.../Recipe/204297
It describes how to access the current list comp from within the list comp
itself.
-- Paul This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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