Threading module question

[Andrew Gregory]

I've written a Tkinter application (Windows) that uses the threading
module, which I've reduced to the test case below (apologies if it's a
bit long). Using the Queue module to pass messages the callable
function in ClassDoRun can be started and interrupted via 'Start' and
'Abort' buttons. Having started then interrupted the function I
expected to be able to execute the function again from the beginning
using the 'Start' button - but I get an error message saying that the
thread is already running, even though the function has been exited.
How do I fix this?

Andrew.

# threaddemo.py
#
# Python 2.3.4 (requires Tix)
#
import threading, Queue, Tix, time

# In the full program the function below
# controls various instruments and collects data.
# A much-shortened version is given here.
class ClassDoRun:

def __init__(self, CS):
self.CS = CS

def __call__(self):
CS = self.CS
for i in range(10):
CS.Counter.set( i) # write a value for display in GUI
time.sleep(1.0)
if CS.AbortRun: break

class CommonStuff: # to provide two-way common access to variables
# and functions by GUI and 'run' threads
def __init__(self, root):
self.root=root
self.root.title ("threaddemo.py , vs 12-Jul-2004")
self.frame = Tix.Frame(root)
self.frame.bind ("<Destroy>",se lf.CleanUp)
self.AbortRun=0
self.Counter=Ti x.IntVar()

def myquit(self):
self.root.destr oy()

def CleanUp(self, event):
print "Cleaning up after Tkinter closed"

def ButtonBoxWidget (Fquit, Frun, Fabort, frame):
butbox = Tix.ButtonBox(f rame, orientation=Tix .HORIZONTAL)
butbox.add('sta rt', text='Start', underline=0, width=6,
command=Frun)
butbox.add('abo rt', text='Abort', underline=0, width=6,
command=Fabort)
butbox.add('qui t', text='Quit', underline=0, width=6,
command=Fquit)
return butbox

class MainWidget(Comm onStuff, Tix.TixWidget):
def __init__(self, CS, Qput):
self.CS = CS
self.Qput = Qput
self.Lcounter = Tix.Label(CS.fr ame, textvariable=CS .Counter)
self.Lcounter.g rid(row=0, column=0, pady=5)
self.butbox = ButtonBoxWidget (CS.myquit, self.SendRunMes sage,
self.SendAbortM essage, CS.frame)
self.butbox.gri d(row=1, column=0)

def SendRunMessage( self):
self.Qput('run' )

def SendAbortMessag e(self):
self.Qput('abor t')
class Application:
def __init__(self, CS):
self.CS = CS
self.Q = Queue.Queue() # Pass messages to separate run
# thread via the queue Q
self.displayedw idget=MainWidge t(CS, self.Q.put)
CS.frame.pack()
self.RunnableOb ject = ClassDoRun(CS)
self.thread = threading.Threa d(target=self.R unnableObject)
self.poll()

def MessageQueue(se lf): # messages e.g. Run, Abort
self.CS.root.up date()
while self.Q.qsize():
try:
msg = self.Q.get(0)
if msg=="abort": self.CS.AbortRu n = 1
if msg=="run":
self.CS.AbortRu n=0
if not self.thread.isA live(): self.thread.sta rt()
except Queue.Empty: pass

def poll(self):
#print self.thread.isA live()
self.MessageQue ue()
self.CS.root.af ter(100, self.poll)
if __name__ == '__main__':
root = Tix.Tk()
CS = CommonStuff(roo t)
mainWin = Application(CS)
root.mainloop()

[Dennis Lee Bieber]

On 13 Jul 2004 07:40:14 -0700, an************@ npl.co.uk (Andrew Gregory)
declaimed the following in comp.lang.pytho n:

expected to be able to execute the function again from the beginning
using the 'Start' button - but I get an error message saying that the
Read the manual...
"""
start( )

Start the thread's activity.
This must be called at most once per thread object. It arranges for the
object's run() method to be invoked in a separate thread of control.

"""

Note the clause: "... once per thread object"
thread is already running, even though the function has been exited.
How do I fix this?
As the old joke finishes: "Stop doing that"

I'd use a sequence of joining the dead thread, deleting it, and
creating a whole new thread object.

-- =============== =============== =============== =============== == <
wl*****@ix.netc om.com | Wulfraed Dennis Lee Bieber KD6MOG <
wu******@dm.net | Bestiaria Support Staff <
=============== =============== =============== =============== == <
Home Page: <http://www.dm.net/~wulfraed/> <
Overflow Page: <http://wlfraed.home.ne tcom.com/> <

[Andrew Gregory]

Solution: You cannot re-run a threaded function, but you can delete
the thread
a create a new one. I'm sure that I should have thought of that
before, but this is the first occasion that I've tried to use use
threads, and this was not obvious to me from the docs. I've posted the
code in case it's useful to others.
I know that it could be shortened, but it is a model for a much longer
script.

General comment: Writing Tkinter and Tix GUI applications is quite
easy most of the time, quite often I find that I can just copy and
paste from something that I've written before. It only becomes tricky
when programming something that you haven't tried before. What would
really help would be a good selection of examples (PYTHONCARD is quite
good in this respect). I know there are some (e.g. in the Tix
download), but more would help. Does anyone know any good sites for
examples?

# threaddemo.py
#
# Demonstrate a Tix GUI which can launch and interrupt
# a function in a separate thread.
#
# A. P. Gregory, 15th July 2004.
#
# Python 2.3.4 (requires Tix)
#
import threading, Queue, Tix, time
import tkFont

class ClassDoRun:

def __init__(self, CS):
self.CS = CS
CS.Counter.set( 'Press to start\ncountdow n')

def __call__(self):
CS = self.CS
for i in range(0,10):
CS.Counter.set( str(10-i)+'/10') # write a value for
display in GUI
time.sleep(1.0)
if CS.AbortRun:
CS.Counter.set( 'Aborted\n(can re-start)')
return
CS.Counter.set( 'Bang!')
class CommonStuff: # to provide two-way common access to variables
# and functions by GUI and 'run' threads
def __init__(self, root):
self.root=root
self.root.title ("threaddemo.py , vs 15-Jul-2004")
self.frame = Tix.Frame(root)
self.frame.bind ("<Destroy>",se lf.CleanUp)
self.AbortRun=0
self.Counter=Ti x.StringVar()

def myquit(self):
self.root.destr oy()

def CleanUp(self, event):
print "Cleaning up after Tkinter closed"

class ButtonBoxWidget :
def __init__(self, Fquit, Frun, Fabort, frame):
butbox = Tix.ButtonBox(f rame, orientation=Tix .HORIZONTAL)
self.butbox = butbox
butbox.add('sta rt', text='Start', underline=0, width=6,
command=Frun)
butbox.add('abo rt', text='Abort', underline=0, width=6,
command=Fabort)
butbox.add('qui t', text='Quit', underline=0, width=6,
command=Fquit)
def grid(self, **kwargs): self.butbox.gri d(kwargs)

class MainWidget(Comm onStuff, Tix.TixWidget):
def __init__(self, CS, Qput):
self.CS = CS
self.Qput = Qput
self.Lcounter = Tix.Label(CS.fr ame, textvariable=CS .Counter,
font=('Sans Serif', 16, 'bold'), fg='blue', bg='white', padx=16,
height=2, width=8)
self.Lcounter.g rid(row=0, column=0, pady=15)
self.butbox = ButtonBoxWidget (CS.myquit, self.SendRunMes sage,
self.SendAbortM essage, CS.frame)
self.butbox.gri d(row=1, column=0)

def SendRunMessage( self):
self.Qput('run' )

def SendAbortMessag e(self):
self.Qput('abor t')
class Application:
def __init__(self, CS):
self.CS = CS
self.Q = Queue.Queue() # Pass messages to separate run thread
via the queue Q
self.displayedw idget=MainWidge t(CS, self.Q.put)
CS.frame.pack()
self.RunnableOb ject = ClassDoRun(CS)
self.thread = threading.Threa d(target=self.R unnableObject)
self.poll()

def MessageQueue(se lf): # messages e.g. Run, Abort
self.CS.root.up date()
while self.Q.qsize():
try:
msg = self.Q.get(0)
if msg=="abort": self.CS.AbortRu n = 1
if msg=="run":
self.CS.AbortRu n=0
if not self.thread.isA live():
del self.thread # Cannot re-run
function,
# but can delete
thread
# and run as new.
self.thread = threading.Threa d(
target=self.Run nableObject)
self.thread.sta rt()
except Queue.Empty: pass

def poll(self):
#print self.thread.isA live()
self.MessageQue ue()
self.CS.root.af ter(100, self.poll)
if __name__ == '__main__':
root = Tix.Tk()
CS = CommonStuff(roo t)
mainWin = Application(CS)
root.mainloop()

[Aahz]

In article <28************ **************@ posting.google. com>,
Andrew Gregory <an************ @npl.co.uk> wrote:

Solution: You cannot re-run a threaded function, but you can delete
the thread a create a new one. I'm sure that I should have thought of
that before, but this is the first occasion that I've tried to use use
threads, and this was not obvious to me from the docs. I've posted the
code in case it's useful to others.

Better answer: re-use the thread. Have the thread you create sitting on
a Queue, waiting for input.
--
Aahz (aa**@pythoncra ft.com) <*> http://www.pythoncraft.com/

Barbara Boxer speaks for me:
http://buffaloreport.com/2004/040713....marriage.html