For a given list:
fruits=["apples","orang es","mangoes"," bananas"]
Is it possible to do wildcard matches like shown below?
1. "man*" in fruits
2. fruits.index("m an*")
3. "*nanas*" in fruits
4. fruits.index("* nanas")
or is there any way to achieve an equivalent effect
short of doing a while loop? 1 3479
Jon Perez wrote: For a given list:
fruits=["apples","orang es","mangoes"," bananas"]
Is it possible to do wildcard matches like shown below?
1. "man*" in fruits
2. fruits.index("m an*")
3. "*nanas*" in fruits
4. fruits.index("* nanas") or is there any way to achieve an equivalent effect short of doing a while loop? import fnmatch def find(seq, pattern):
.... pattern = pattern.lower()
.... for i, n in enumerate(seq):
.... if fnmatch.fnmatch (n.lower(), pattern):
.... return i
.... return -1
.... def index(seq, pattern):
.... result = find(seq, pattern)
.... if result == -1:
.... raise ValueError
.... return result
.... def contains(seq, pattern):
.... return find(seq, pattern) != -1
.... fruit = "apples oranges mangoes bananas".split( ) contains(fruit, "man*")
True contains(fruit, "*nas")
True index(fruit, "*ANA*")
3 find(fruit, "*")
0 find(fruit, "m*s")
2 find(fruit, "m*x")
-1
If you want case-sensitive matches, use fnmatchcase() and remove the
..lower() conversions.
Peter This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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