Hi folks,
Id appreciate if you can help:
I want to start an exe which takes as an argument filename. What I tried
was:
os.spawnl(os.P_ NOWAIT,('proces sor.exe'),'file name.ext'))
I also tried:
os.execl(r'DRIV E:\WINNT\system 32\cmd.exe',
'/k',('processor. exe'),'filename .ext'))
but is simply the command line and stopped.
However I didnt achieve the expected result and got some number like:
788.
Can anyone help?
Thanx in advance
1  1795 
"questioner " <bs*******@dspa ce.de> wrote in message news:<28******* *************** ********@localh ost.talkaboutpr ogramming.com>. .. Hi folks,
Id appreciate if you can help:
I want to start an exe which takes as an argument filename. What I tried
was:
os.spawnl(os.P_ NOWAIT,('proces sor.exe'),'file name.ext'))
I also tried:
os.execl(r'DRIV E:\WINNT\system 32\cmd.exe',
'/k',('processor. exe'),'filename .ext'))
but is simply the command line and stopped.
However I didnt achieve the expected result and got some number like:
788.
Since you specified os.P_NOWAIT in the spawnl() call, it didn't return
an exit code, but rather the process ID of the spawned process. If
you were expecting the exit code, you should be using os.P_WAIT.
Other than that, we could really use more detail to help us answer
this question. What exactly did the system do and print when you made
the call? What did you expect/want it to do? This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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