I am trying to split a string like so:
re.split(',|。|、 |!|:|,|?|“|”|)| (|;',
my_string)
Python complains like so:
Traceback (most recent call last):
File "C:\Python23\co des\regextest.p y", line 27, in
-toplevel-
ultimate =
re.split(',|。|、 |!|:|,|?|“|”|)| (|;',
ch[0])
File "c:\python23\li b\sre.py", line 156, in split
return _compile(patter n, 0).split(string ,
maxsplit)
File "c:\python23\li b\sre.py", line 229, in _compile
raise error, v # invalid expression
error: nothing to repeat
Does this mean that the regular expression I pass to
the split function is not valid?
That expression is just like ',|)|#|!', that is, an
or-ed list of punctuations. Then why invalid?
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Anthony Liu wrote: I am trying to split a string like so:
re.split(',|。|、 |!|:|,|?|“|”|)| (|;',
my_string)
Python complains like so:
Traceback (most recent call last):
File "C:\Python23\co des\regextest.p y", line 27, in
-toplevel-
ultimate =
re.split(',|。|、 |!|:|,|?|“|”|)| (|;',
ch[0])
File "c:\python23\li b\sre.py", line 156, in split
return _compile(patter n, 0).split(string ,
maxsplit)
File "c:\python23\li b\sre.py", line 229, in _compile
raise error, v # invalid expression
error: nothing to repeat
Does this mean that the regular expression I pass to
the split function is not valid?
That expression is just like ',|)|#|!', that is, an
or-ed list of punctuations. Then why invalid?
Because ?, (, and ) are special characters in regular expressions. You must
escape them with a backslash: re.split(',|。|、 |!|:|,|\\?|\\)| \\(|;', 'foo,bar(spam)' )
['foo', 'bar', 'spam', '']
HTH
--
- Eric Brunel <eric (underscore) brunel (at) despammed (dot) com> -
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