Hi Pythoners...
It seems to me the Asterisk (*) sign in python means many things...
if a python code line looks like this:
def__init__(sel f, func, *param):
bla bla bla...
and then u have something like this:
func(*param)
and then something like this:
def Wrapper(select, func, param):
bla bla bla...
I took this section of code from the 'Python Cookbook' textbook page
223 about 'Running Functions in the future'...
I just cant figure out what is the asterisk (*) sign for and what is
the different between *param and param??
Many thanks Pythoners...
Regards
sarmin 3 4140
"sarmin" <sa********@yah oo.com> wrote in message
news:ma******** *************** **************@ python.org... Hi Pythoners...
It seems to me the Asterisk (*) sign in python means many things...
if a python code line looks like this: def__init__(sel f, func, *param): bla bla bla...
and then u have something like this: func(*param)
and then something like this: def Wrapper(select, func, param): bla bla bla...
I took this section of code from the 'Python Cookbook' textbook page 223 about 'Running Functions in the future'...
I just cant figure out what is the asterisk (*) sign for and what is the different between *param and param??
Many thanks Pythoners...
Regards sarmin
It's for variable length parameter lists. In a function
definition, one * is a list of additional positional
parameters, two **s is a dictionary of additional
keyword parameters.
In a function call, one * is a list of additional
positional parameters, two **s is a dictionary
of additional keyword parameters.
John Roth
At some point, "John Roth" <ne********@jhr othjr.com> wrote: "sarmin" <sa********@yah oo.com> wrote in message news:ma******** *************** **************@ python.org... Hi Pythoners...
It seems to me the Asterisk (*) sign in python means many things...
if a python code line looks like this: def__init__(sel f, func, *param): bla bla bla...
and then u have something like this: func(*param)
and then something like this: def Wrapper(select, func, param): bla bla bla...
I took this section of code from the 'Python Cookbook' textbook page 223 about 'Running Functions in the future'...
I just cant figure out what is the asterisk (*) sign for and what is the different between *param and param??
Many thanks Pythoners...
Regards sarmin
It's for variable length parameter lists. In a function definition, one * is a list of additional positional parameters, two **s is a dictionary of additional keyword parameters.
In a function call, one * is a list of additional positional parameters, two **s is a dictionary of additional keyword parameters.
Don't forget multiplicaton:
2 * 2
and power
2 ** 2
:-)
--
|>|\/|<
/--------------------------------------------------------------------------\
|David M. Cooke
|cookedm(at)phy sics(dot)mcmast er(dot)ca
Hi Sarmin, and then u have something like this: func(*param)
[...] I just cant figure out what is the asterisk (*) sign for and what is the different between *param and param??
The asterisk is used for multiple parameters, which are passed to
the function as a tuple.
If your function might be called with a varying number of arguments:
myfunc(10)
or
myfunc(10, 20, 30)
or
myfunc(10, "ten", 20, "twenty")
you could write it as:
def myfunc(*param):
print param
and you would get myfunc(10)
(10,) myfunc(10, 20, 30)
(10, 20, 30) myfunc(10, "ten", 20, "twenty")
(10, 'ten', 20, 'twenty')
If you had defined your function without the
asterisk, you could only use a single parameter:
def myfunc(param):
print param
myfunc(10)
10 myfunc(10, 20, 30)
Traceback (most recent call last):
File "<pyshell#2 7>", line 1, in -toplevel-
myfunc(10, 20, 30)
TypeError: myfunc() takes exactly 1 argument (3 given)
You can have non-optional parameters before the asterisk parameter:
def myfunc(required , necessary, *optional):
print "required", required
print "necessary" , necessary
print "optional", optional
myfunc(10, 20, 30, 40)
required 10
necessary 20
optional (30, 40) myfunc(10)
Traceback (most recent call last):
File "<pyshell#3 5>", line 1, in -toplevel-
myfunc(10)
TypeError: myfunc() takes at least 2 arguments (1 given)
Regards, Myles. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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Hi Pythoners...
I am definitely confused with the use of asterisk (*) sign in python...
I quoted the following code from 'python cookbook' text book page 223 about 'running functions in the future'...
it says:
def __init__(self,func, *param):
bla bla bla...
then it says:
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