Lists are weird when they are instance members

[python newbie]

hey,
okay, I'm trying to figure out why my books: Quick Python, Python in a
Nutshell, Python Cookbook and Learning Python don't say anything about the
weird behavior of a list when you have one as an object instance member.

for instance (my first pun of 2004), if I have,

test.py
----------------

global_filegrou p_array = [] # array of filegroup objects

class FileGroup:
a = 0
mylist = [] # here it is

def put_stuff_in_my _list(self, anyfile):
self.mylist.app end( get just a single string from file) #
pls excuse the psuedo

def __init__(self):
put_stuff_in_my _list(anyfile)

def main(): # do ten times: instantiate the
above object, and add to the global array
for i in xrange(10):
filegroup = FileGroup()
global_filegrou p_array.append( filegroup)
# print the list contents
print global_filegrou p_array[0].mylist

------------ end of file

Output is: [u'.string1', u'.string2', u'.string3' ] # only
u'string1' should show up

No matter which index I use into the global array, I always get ALL of
the strings
showing up. I should only get u'string1' showing up, and u'string2'
if
I used "[1].mylist"
How I resolved it, is by slipping in

self.mylist = []

before

put_stuff_in_my _list(anyfile)

in __init__(self)

Why should I have to empty out the list when it's a member of a newly
instantiated object?

thanks

p.s. ( I'm actually not doing exactly the thing with the
files, but instead iterating through a xml file with dom,
debugging it showed the behavior )

[Robin Becker]

In article <ff************ *****@newssvr29 .news.prodigy.c om>, python
newbie <me*******@hotm ail.com> writes

I think you're not grokking that using

class A:
mylist = []

makes mylist a class attribute ie all instances share the same version
of mylist. To get an instance version you need to assign self.mylist.
That would normally be done using an __init__method. so

class A:
def __init__(self):
self.mylist = []

then each instance sets up its own empty list at creation time.

Hope that helps.
--
Robin Becker

[Mathias Waack]

python newbie wrote:

test.py
----------------

global_filegrou p_array = [] # array of filegroup objects

class FileGroup:
a = 0
mylist = [] # here it is
This is a class variable, not a member or instance variable. Make
sure you know the difference.
def put_stuff_in_my _list(self, anyfile):
self.mylist.app end( get just a single string from
file)

This line creates a member variable "mylist" of the current instance
"self" of class "FileGroup" as a copy of the class variable
"FileGroup.myli st".

Just create your member variables in the c'tor function __init__.
This should solve all your problems (ok, at least this problem;)

And btw. Python in a nutshell (I haven't read the other books you've
mentioned) explains the differences between class and member
variables.

Mathias

[Troels Therkelsen]

In article <ff************ *****@newssvr29 .news.prodigy.c om>, python newbie wrote:

hey,
okay, I'm trying to figure out why my books: Quick Python, Python in a
Nutshell, Python Cookbook and Learning Python don't say anything about the
weird behavior of a list when you have one as an object instance member.

for instance (my first pun of 2004), if I have,

test.py
----------------

global_filegrou p_array = [] # array of filegroup objects

class FileGroup:
a = 0
mylist = [] # here it is
mylist in this case is a class variable; what this means is that it is shared
amongst all *instances* of the class. Only if an instance of the class rebinds
mylist is it local to the particular class instance doing this.

def put_stuff_in_my _list(self, anyfile):
self.mylist.app end( get just a single string from file) #
pls excuse the psuedo
Because lists are mutable, when you use mylist.append(. ..) you don't rebind
mylist, but change its contents. Since mylist is a class variable, this
change is available to the class as well as all instances of the class.

def __init__(self):
put_stuff_in_my _list(anyfile)

def main(): # do ten times: instantiate the
above object, and add to the global array
for i in xrange(10):
filegroup = FileGroup()
global_filegrou p_array.append( filegroup)
# print the list contents
print global_filegrou p_array[0].mylist

------------ end of file

Output is: [u'.string1', u'.string2', u'.string3' ] # only
u'string1' should show up

No matter which index I use into the global array, I always get ALL of
the strings
showing up. I should only get u'string1' showing up, and u'string2'
if
I used "[1].mylist"
How I resolved it, is by slipping in

self.mylist = []

before

put_stuff_in_my _list(anyfile)

in __init__(self)

Why should I have to empty out the list when it's a member of a newly
instantiated object?

Because __init__() is called when a class is about to be instantiated. You are
masking the *class variable* mylist with a local *instance variable* of the
same name. The latter is not shared amongst all instances of the class, but
remains unique to the particular instance.

Hope this helps,

/Troels Therkelsen

[python newbie]

thanks for the helpful replies.
I guess I was just in confusion as to why I was able to leave alone the
string variables in class FileGroup, such
as sourceDir and destinDir, and nothing unpredictable happened with those,
but with the list variable, I had to treat differently.
But after I again read closely, Python In a Nutshell, I'm sure I will
understand.
"python newbie" <me*******@hotm ail.com> wrote in message
news:ff******** *********@newss vr29.news.prodi gy.com...

hey,
okay, I'm trying to figure out why my books: Quick Python, Python in a
Nutshell, Python Cookbook and Learning Python don't say anything about the
weird behavior of a list when you have one as an object instance member.

for instance (my first pun of 2004), if I have,

test.py
----------------

global_filegrou p_array = [] # array of filegroup objects

class FileGroup:
a = 0
mylist = [] # here it is

def put_stuff_in_my _list(self, anyfile):
self.mylist.app end( get just a single string from file) #
pls excuse the psuedo

def __init__(self):
put_stuff_in_my _list(anyfile)

def main(): # do ten times: instantiate the
above object, and add to the global array
for i in xrange(10):
filegroup = FileGroup()
global_filegrou p_array.append( filegroup)
# print the list contents
print global_filegrou p_array[0].mylist

------------ end of file

Output is: [u'.string1', u'.string2', u'.string3' ] # only
u'string1' should show up

No matter which index I use into the global array, I always get ALL of
the strings
showing up. I should only get u'string1' showing up, and u'string2'
if
I used "[1].mylist"
How I resolved it, is by slipping in

self.mylist = []

before

put_stuff_in_my _list(anyfile)

in __init__(self)

Why should I have to empty out the list when it's a member of a newly
instantiated object?

thanks

p.s. ( I'm actually not doing exactly the thing with the
files, but instead iterating through a xml file with dom,
debugging it showed the behavior )

[python newbie]

I didn't say that right. I meant to say that I now finally understood
what's going on now, with your replies, but I will take a slight break from
the app I'm writing, and do some ingesting of the core Python concepts.

"python newbie" <me*******@hotm ail.com> wrote in message
news:Vf******** ********@newssv r29.news.prodig y.com...

thanks for the helpful replies.
I guess I was just in confusion as to why I was able to leave alone the
string variables in class FileGroup, such
as sourceDir and destinDir, and nothing unpredictable happened with those,
but with the list variable, I had to treat differently.
But after I again read closely, Python In a Nutshell, I'm sure I will
understand.