Is there a simple way to zip and unzip files?
I'm looking for something along the lines of:
zfile = zipfile(r'c:\so mefile.zip')
zfile.extract(r 'c:\somefiles')
I've looked at the documentation for zlib and zipfile, and they seem
pretty comprehensive, but also extremely low level. If needed, I can
probably make a workable component from them, but I was wondering if
there is one already written that I'm just missing.
--
Doug Tolton
(format t "~a@~a~a.~a " "dtolton" "ya" "hoo" "com") 1 9787
Doug Tolton wrote: Is there a simple way to zip and unzip files?
I'm looking for something along the lines of:
zfile = zipfile(r'c:\so mefile.zip') zfile.extract(r 'c:\somefiles')
I've looked at the documentation for zlib and zipfile, and they seem pretty comprehensive, but also extremely low level. If needed, I can probably make a workable component from them, but I was wondering if there is one already written that I'm just missing.
Probably not, since it's likely to require slight differences in
each application. Try this (untested):
import os, zipfile
def extract(self, todir=''):
for name in self.namelist() :
f = open(os.path.jo in(todir, name), 'wb')
f.write(self.re ad(name))
f.close()
zipfile.ZipFile .extract = extract
Now you should be able to execute the two example lines you showed above...
-Peter This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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H
My application creates two files , i have to zip these two files to a a single file, how to use winzip functionality in c#
Is there any builtin functions available with visual c#
the two file are in text and binary formats , is it possible to Zip them and unzip in c#
-----need hel
---------seash
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