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Comparing variable types

type(i) == "<type 'float'>"
this always returns false. How come?
type(i)returns <type 'float'> if i is a float so why isn't == working?
Jul 18 '05
14 8661
In article <bn************ *@ID-198839.news.uni-berlin.de>,
"Kill Bill" <bi**@kill.co m> wrote:
Where can I find all the methods for Dictionaries? They list some here, but
is that all of them?
http://www.python.org/doc/2.3.2/tut/...00000000000000
I think it is, but I don't like how its written. I want it to be written
you know by method, constuctors, like in the Java API. Anyone know what I'm
talking about? Its so quick to skim through the API to see which method you
are looking for. Not the case here.


Try typing help(dict) to the Python interpreter.

--
David Eppstein http://www.ics.uci.edu/~eppstein/
Univ. of California, Irvine, School of Information & Computer Science
Jul 18 '05 #11
In article <ma************ *************** *********@pytho n.org>,
Andrew Bennetts <an************ ***@puzzling.or g> wrote:
On Sat, Oct 25, 2003 at 10:36:03PM -0400, Kill Bill wrote:
type(i) == "<type 'float'>"
this always returns false. How come?
type(i)returns <type 'float'> if i is a float so why isn't == working?


Because "<type 'float'>" is a string :)

You want
import types
type(i) == types.FloatType

or
type(i) == type(1.0)

or in 2.2 and later you can simply do
type(i) == float


But it's almost always preferable to do
isinstance(i,fl oat)
because that allows subclasses of float to be used. If you really have
to test whether i is an unsubclassed float,
type(i) is float
would be a better choice than
type(i)==float
as it more accurately expresses the intent that only the precise float
type will be allowed.

--
David Eppstein http://www.ics.uci.edu/~eppstein/
Univ. of California, Irvine, School of Information & Computer Science
Jul 18 '05 #12
Emile van Sebille wrote:

"Kill Bill" <bi**@kill.co m> wrote in message
news:bn******** *****@ID-198839.news.uni-berlin.de...
type(i) == "<type 'float'>"


This compares the current type of i to type("string"), which is <type
'str'>.


(Minor correction) Actually it compares it to the actual string
containing the letters "<type 'float'>", which is of course going
to get one nowhere.

The above would have worked if the OP had used

repr(type(i)) == "<type 'float'>"

but that is the absolute worst way of doing this...

-Peter
Jul 18 '05 #13
"Kill Bill" <bi**@kill.co m> writes:
"KefX" <ke**********@a ol.comNOSPAM> wrote in message
news:20******** *************** ****@mb-m07.aol.com... [...]
Use isinstance(), like this:

[...] Can you tell me where you found that method in the docs? I'm having trouble

[...]

Rule of thumb: If you can't find it, it's in section 2 of the library docs.
John
Jul 18 '05 #14
In article <ep************ *************** *@news.service. uci.edu>,
David Eppstein <ep******@ics.u ci.edu> wrote:
In article <bn************ *@ID-198839.news.uni-berlin.de>,
"Kill Bill" <bi**@kill.co m> wrote:
Where can I find all the methods for Dictionaries? They list some here, but
is that all of them?
http://www.python.org/doc/2.3.2/tut/...00000000000000
I think it is, but I don't like how its written. I want it to be written
you know by method, constuctors, like in the Java API. Anyone know what I'm
talking about? Its so quick to skim through the API to see which method you
are looking for. Not the case here.


Try typing help(dict) to the Python interpreter.

Jul 18 '05 #15

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