Join equivalent for tuples of non-strings?

[Peter L. Buschman]

I'm trying to think in Python, but am stumped here...

What is the equivalent for the following if you are dealing with a tuple
of non-strings?

import string
foo = ( '1', '2', '3' )
string.join( foo, '.' ) '1.2.3'

With a tuple of integers, this fails with a traceback as below:
bar = ( 1, 2, 3 )
string.join( bar, '.' )
Traceback (most recent call last):
File "<pyshell#1 1>", line 1, in -toplevel-
string.join( bar, '.' )
File "C:\Python23\Li b\string.py", line 135, in join
return sep.join(words)
TypeError: sequence item 0: expected string, int found

--PLB

[Peter Hansen]

"Peter L. Buschman" wrote:

I'm trying to think in Python, but am stumped here...

What is the equivalent for the following if you are dealing with a tuple
of non-strings?

import string
foo = ( '1', '2', '3' )
string.join( foo, '.' )

'1.2.3'

With a tuple of integers, this fails with a traceback as below:

Try this instead, using old and new style Python:

string.join(map (str, foo), '.')

or

'.'.join([str(x) for x in foo])

-Peter

[Ulrich Petri]

"Peter L. Buschman" <pl*@iotk.com > schrieb im Newsbeitrag
news:1a******** *************** ***@posting.goo gle.com...

I'm trying to think in Python, but am stumped here...

What is the equivalent for the following if you are dealing with a tuple
of non-strings?

import string
foo = ( '1', '2', '3' )
string.join( foo, '.' ) '1.2.3'

With a tuple of integers, this fails with a traceback as below:
bar = ( 1, 2, 3 )
string.join( bar, '.' )

try:

foo = (1,2,3,4,5,6)
".".join([str(x) for x in foo])

HTH

Ciao Ulrich

[Peter L. Buschman]

Awesome! Thanks guys :)
--PLB