convert ints in a range to strings

[hokieghal99]

Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file:

192.168.1.0
192.168.1.1
192.168.1.2
....
192.168.1.255

Thanks!!!!

[Duncan Smith]

"hokieghal9 9" <ho********@hot mail.com> wrote in message
news:bk******** **@solaris.cc.v t.edu...

Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file:

192.168.1.0
192.168.1.1
192.168.1.2
...
192.168.1.255

Thanks!!!!

a="192."
b="168."
c="1."
r = 12
a + b + c + str(r) '192.168.1.12' '%s%s%s%d' % (a,b,c,r) '192.168.1.12'

I believe the second approach is generally faster.

Duncan

[Paul Rubin]

hokieghal99 <ho********@hot mail.com> writes:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r

for r in range(256):
print "192.168.1. %d" % r

[hokiegal99]

Thank you (Paul & Duncan) for showing me how to do this!

Paul Rubin wrote:

hokieghal99 <ho********@hot mail.com> writes:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r

for r in range(256):
print "192.168.1. %d" % r

[Heather Coppersmith]

On Wed, 17 Sep 2003 19:02:40 -0400,
hokieghal99 <ho********@hot mail.com> wrote:

Hi,
I'm trying to do this: ------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------ But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file: 192.168.1.0
192.168.1.1
192.168.1.2
...
192.168.1.255

Try any or all of these:

print a + b + c + str( r )

print a + b + c + "%d" % r

print a + b + c + "%s" % r

print "%s%s%s%d" % (a, b, c, r)

Regards,
Heather

--
Heather Coppersmith
That's not right; that's not even wrong. -- Wolfgang Pauli

[hokiegal99]

Thanks Heather... this did it:

outputFile = file('ips.txt', 'w')
r = range(256)
for r in range(256):
f = '192.168.1.%s\n ' % r #Change this line to macth your network.
outputFile.writ e(f)
outputFile.clos e()

Heather Coppersmith wrote:

Try any or all of these:

print a + b + c + str( r )

print a + b + c + "%d" % r

print a + b + c + "%s" % r

print "%s%s%s%d" % (a, b, c, r)

Regards,
Heather

[Michael Sweeney]

> Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

You could try this:

a="192"
b="168"
c="1"
for d in range(256):
print "%s.%s.%s.%s"%( a,b,c,d)
192.168.1.0
192.168.1.1
192.168.1.2
192.168.1.3
....
192.168.1.255

- Mike

[Asun Friere]

hokieghal99 <ho********@hot mail.com> wrote in message news:<bk******* ***@solaris.cc. vt.edu>...

Hi,

I'm trying to do this:

------------------------------
a="192."
b="168."
c="1."
r = range(256)
for r in r:
print a + b + c + r
------------------------------

But, I get this error: cannot concatenate 'str' and 'int' objects. So, I
need to convert the ints in the range to strs, but I do not know how to
do that. Could someone help me? Ultimately, I want to print out
something like this to a text file:

192.168.1.0
192.168.1.1
192.168.1.2
...
192.168.1.255

Thanks!!!!

for x in r :
print a + b + c + str(x)
but why not use ints all the way along like this:

a = 192
b = 168
c = 1
for n in range(256) :
print "%d.%d.%d.% d" % (a, b, c, n)

or simply don't use them at all:

for n in range(256) :
print "192.168.1. %d" % n

[Raymond Hettinger]

[hokieghal99]

a="192."
b="168."
c="1."
r = range(256)
for r in r:
This rebinding of r is an amazing non-error.
I had to read it twice before I believed that it worked.
Working or not, don't do this. Changing the meaning
of variable like this drives some people off the edge
and they end up working in pure functional languages
and never recover.
print a + b + c + r

As the others pointed out, str(r) will do the trick.
Raymond Hettinger

[Duncan Smith]

"hokiegal99 " <ho********@hot mail.com> wrote in message
news:3F******** ******@hotmail. com...

Thanks Heather... this did it:

outputFile = file('ips.txt', 'w')
r = range(256)
for r in range(256):
f = '192.168.1.%s\n ' % r #Change this line to macth your network.
outputFile.writ e(f)
outputFile.clos e()

[snip]

The second line of this code does nothing useful. My feeling is that as r
is an integer you should really use %d, rather than %s.

Duncan