I'm trying to implement __iter__ on an abstract base class while I don't
know whether subclasses support that or not.
Hope that makes sense, if not, this code should be clearer:
class Base:
def __getattr__(sel f, name):
if name == "__iter__" and hasattr(self, "Iterator") :
return self.Iterator
raise AttributeError, name
class Concrete(Base):
def Iterator(self):
yield 1
yield 2
yield 3
The idea is that if a subclass of Base defines an 'Iterator' method,
instances are iterable. They are not iterable otherwise.
The above gives the expected behaviour: iter(Base()) raises a
"TypeError: iteration over non-sequence", and iter(Concrete() ) returns a
generator.
If, however, I make Base a newstyle class, this will not work any
longer. __getattr__ is never called for "__iter__" (neither is
__getattribute_ _, btw). Probably this has to do with data descriptors
and non-data descriptors, but I'm too tired at the moment to think
further about this.
Is there any way I could make the above code work with new style
classes?
Thanks,
Thomas 13 1937
Thomas Heller <th*****@python .net> writes: I'm trying to implement __iter__ on an abstract base class while I don't know whether subclasses support that or not. Hope that makes sense, if not, this code should be clearer:
class Base: def __getattr__(sel f, name): if name == "__iter__" and hasattr(self, "Iterator") : return self.Iterator raise AttributeError, name
class Concrete(Base): def Iterator(self): yield 1 yield 2 yield 3
The idea is that if a subclass of Base defines an 'Iterator' method, instances are iterable. They are not iterable otherwise.
The above gives the expected behaviour: iter(Base()) raises a "TypeError: iteration over non-sequence", and iter(Concrete() ) returns a generator.
If, however, I make Base a newstyle class, this will not work any longer. __getattr__ is never called for "__iter__" (neither is __getattribute_ _, btw). Probably this has to do with data descriptors and non-data descriptors, but I'm too tired at the moment to think further about this.
Is there any way I could make the above code work with new style classes?
I forgot to mention this: The Base class also implements a __getitem__
method which should be used for iteration if the .Iterator method in the
subclass is not available. So it seems impossible to raise an exception
in the __iter__ method if .Iterator is not found - __iter__ MUST return
an iterator if present.
Thomas
> I'm trying to implement __iter__ on an abstract base class while I don't know whether subclasses support that or not. Hope that makes sense, if not, this code should be clearer:
class Base: def __getattr__(sel f, name): if name == "__iter__" and hasattr(self, "Iterator") : return self.Iterator raise AttributeError, name
class Concrete(Base): def Iterator(self): yield 1 yield 2 yield 3
I don't know how to achieve it, but why don't you simply use
class Base:
pass
class Concrete(Base):
def __iter__(self) :
yield 1
yield 2
yield 3
What is the advantage to have a baseclass that essentially does
some method renaming __iter__ ==> Iterator?
- harold -
--
Always remember that you are unique;
just like everyone else.
--
I'm not sure I understand why you would want to. Just don't define
__iter__ on your newstyle class and you'll get the expected behavior.
Why not define an Iterator method in your Base class that does the
iteration using __getitem__, and any subclass that wants to do
something else just defines its own Iterator method? For that matter,
you could just use the __iter__ methods of Base and Concrete instead of
a separate method.
Something like this: class Base(object):
.... def __getitem__(sel f, key):
.... return key
.... def __iter__(self):
.... yield self[1]
.... yield self['foo']
.... yield self[3.0]
.... class ConcreteIterabl e(Base):
.... def __iter__(self):
.... yield True
.... yield 'Blue'
.... yield 'Foo'
.... class ConcreteNotIter able(Base):
.... pass
.... [x for x in Base()]
[1, 'foo', 3.0] [x for x in ConcreteIterabl e()]
[True, 'Blue', 'Foo'] [x for x in ConcreteNotIter able()]
[1, 'foo', 3.0]
Thomas Heller wrote: I forgot to mention this: The Base class also implements a __getitem__ method which should be used for iteration if the .Iterator method in the subclass is not available. So it seems impossible to raise an exception in the __iter__ method if .Iterator is not found - __iter__ MUST return an iterator if present.
def Iterator(self):
for index in xrange(len(self )):
yield self[index]
def __iter__(self):
return self.Iterator()
....and then override Iterator in subclasses. But this raises the
question of why you need to use a specially-named method instead of
having subclasses override the __iter__.
Thomas Heller wrote: I'm trying to implement __iter__ on an abstract base class while I don't know whether subclasses support that or not. Hope that makes sense, if not, this code should be clearer:
class Base: def __getattr__(sel f, name): if name == "__iter__" and hasattr(self, "Iterator") : return self.Iterator raise AttributeError, name
Is there any way I could make the above code work with new style classes?
Obligatory metaclass approach:
class Base:
class __metaclass__(t ype):
def __new__(mcl, name, bases, classdict):
try:
classdict["__iter__"] = classdict["Iterator"]
except KeyError:
pass
return type.__new__(mc l, name, bases, classdict)
class Alpha(Base):
def Iterator(self): yield 42
class Beta(Base):
def __getitem__(sel f, index):
return [1, 2, 3, "ganz viele"][index]
for item in Alpha(): print item
for item in Beta(): print item,
print
Peter
On Wed, 06 Jul 2005 17:57:42 +0200, Thomas Heller <th*****@python .net> wrote: I'm trying to implement __iter__ on an abstract base class while I don't know whether subclasses support that or not. Hope that makes sense, if not, this code should be clearer:
class Base: def __getattr__(sel f, name): if name == "__iter__" and hasattr(self, "Iterator") : return self.Iterator raise AttributeError, name
class Concrete(Base): def Iterator(self): yield 1 yield 2 yield 3
The idea is that if a subclass of Base defines an 'Iterator' method, instances are iterable. They are not iterable otherwise.
The above gives the expected behaviour: iter(Base()) raises a "TypeError: iteration over non-sequence", and iter(Concrete() ) returns a generator.
If, however, I make Base a newstyle class, this will not work any longer. __getattr__ is never called for "__iter__" (neither is __getattribute __, btw). Probably this has to do with data descriptors and non-data descriptors, but I'm too tired at the moment to think further about this.
Is there any way I could make the above code work with new style classes?
Will a property or custom descriptor do what you want? E.g. class Base(object):
... def __getIter(self) :
... if hasattr(self, "Iterator") :
... return self.Iterator
... raise AttributeError, name
... __iter__ = property(__getI ter)
... class Concrete(Base):
... def Iterator(self):
... yield 1
... yield 2
... yield 3
... iter(Base())
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: iteration over non-sequence iter(Concrete() )
<generator object at 0x02EF152C> list(iter(Concr ete()))
[1, 2, 3]
Regards,
Bengt Richter bo**@oz.net (Bengt Richter) writes: On Wed, 06 Jul 2005 17:57:42 +0200, Thomas Heller <th*****@python .net> wrote:
I'm trying to implement __iter__ on an abstract base class while I don't know whether subclasses support that or not.
Will a property or custom descriptor do what you want? E.g. >>> class Base(object): ... def __getIter(self) : ... if hasattr(self, "Iterator") : ... return self.Iterator ... raise AttributeError, name ... __iter__ = property(__getI ter) ... >>> class Concrete(Base): ... def Iterator(self): ... yield 1 ... yield 2 ... yield 3 ... >>> iter(Base()) Traceback (most recent call last): File "<stdin>", line 1, in ? TypeError: iteration over non-sequence >>> iter(Concrete() ) <generator object at 0x02EF152C> >>> list(iter(Concr ete())) [1, 2, 3]
Yep, that's exactly what I need - thanks.
Thomas This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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