beginner query help

[Hought, Todd]

Hi all, trying to run a query against a table, to pull the date out, and
order it. problem is, the date is stored in character (string) format,
not as an actual timestamp, so parsing it back into an offical 'date' is
proving tricky.
the last query that I ran, that I'm pretty sure should be working looks
like this:

(stdtime is the field with the date in numeric format, normally outpus
as: Tue Jan 6 11:36:24 2004)
select * from "table" where ticket = xxxxx order by
to_timestamp('s tdtime', 'Day, Mon, DD, HH24:MI:SS, YYYY');

Something tells me this has to be wrong in some obvious way that lack of
sleep is blinding me from. :-)

thanks in advance.

-Todd Hought
to*********@ech ostar.com

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[Andrew Bartley]

try this

select cast('Tue Jan 6 13:36:24 2004' as timestamp)

Andrew Bartley

-----Original Message-----
From: pg************* ****@postgresql .org
[mailto:pg****** ***********@pos tgresql.org]On Behalf Of Hought, Todd
Sent: Friday, 9 January 2004 7:49 AM
To: postgres
Subject: [GENERAL] beginner query help
Hi all, trying to run a query against a table, to pull the date out, and
order it. problem is, the date is stored in character (string) format,
not as an actual timestamp, so parsing it back into an offical 'date' is
proving tricky.
the last query that I ran, that I'm pretty sure should be working looks
like this:

(stdtime is the field with the date in numeric format, normally outpus
as: Tue Jan 6 11:36:24 2004)
select * from "table" where ticket = xxxxx order by
to_timestamp('s tdtime', 'Day, Mon, DD, HH24:MI:SS, YYYY');

Something tells me this has to be wrong in some obvious way that lack of
sleep is blinding me from. :-)

thanks in advance.

-Todd Hought
to*********@ech ostar.com

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