Why does this not parse xml?

[npm]

Here's the sample xml:

<?xml version="1.0" encoding="UTF-8"?>
<menu>
    <entry>
        <action>
            Test
        </action>
        <title>
            Test Menu Item 1
        </title>
    </entry>
    <entry>
        <action>
            Test 2
        </action>
        <title>
            Test Menu Item 2
        </title>
    </entry>
</menu>

And here's the php code:

<?php
$dom = new DOMDocument();
$dom->load("menu.xml");
$menu = new domxpath($dom);
foreach($menu->query("//menu/entry") as $entry) {
    echo "Action is: " . $menu->query('.//action',$entry)->item(0)->nodeValue;
    echo "Title is: " . $menu->query('.//title',$entry)->item(0)->nodeValue;
}
?>

So why, when I view the page, do I get this error:

Parse error: parse error, expecting `','' or `';'' in /home/httpd/vhosts/csnradio.com/www/test/2.php on line 6

I'm really clueless as to why this would happen because there are tutorials all over the place that are quite similar to this.

Thanks in advance!

[HaLo2FrEeEk]

Try SimpleXML:

http://us2.php.net/manual/en/functio...oad-string.php

[code green]

You have a basic syntax error, that is all.
The error mesage points to where the error is (possibly the line above), which is line 6.
It is not obvious in the code supplied

[Markus]

Code Green, I don't see it?

[npm]

I can't use SimpleXML because the server is running PHP 4.1.2. If I'm not mistaken, one needs version 5 to use SimpleXML, right?

I can see that the error is expecting a comma or a semicolon, but I don't know enough about php to know where they would go. Especially because the code is basically copied straight from a tutorial from someone who most likely had it working on their end.

[Markus]

I'm struggling to spot the syntax error, also.

And you're using PHP4? Seriously? It's 2011!

[npm]

I know...

I don't see where the error is AND it's been almost 7 years since 5.0.0 was released!

[code green]

Can I stop what seems to be a misunderstanding.
I don't see a syntax error. I don't even believe the error is in the code provided.

I thought npm was panicking because there was an xml parsing error.
I was trying to correct this assumption because the message is a php syntax error.

Now, what we need to see is the block of code, and 'line 6' pointing out.
Sorry for the confusion

[npm]

Would the error be a setting or something with the actual server or in that version of PHP (4.1.2)?

I just don't see where the "," or the ";" should go.

This might be something, but I don't know what:
I switched both of the "echo" commands in lines 6-7 to "print" and now I get this error:

Parse error: parse error in /home/httpd/vhosts/csnradio.com/www/test/2.php on line 6

The error is in the same line, but it's different, right?

[npm]

Sorry, just for clarification, here's a visual of what I changed it to:

<?php
$dom = new DOMDocument();
$dom->load("xml.xml");
$menu = new DOMXPath($dom);
foreach($menu->query("//menu/entry") as $entry) {
    print "Action is: " . $menu->query('.//action',$entry)->item(0)->nodeValue;
    print "Title is: " . $menu->query('.//title',$entry)->item(0)->nodeValue;
}
?>

[HaLo2FrEeEk]

Try creating a new variable:

$entries = $menu->query("//menu/entry");

Now do print_r($entries). Does it print anything? If so, keep the new variable and replace $menu->query("//menu/entry") in your foreach with $entries.

Edit: comment out the entire for loop before doing print_r or the error might still happen.

[npm]

Just to make sure...change it to, and run the following?

<?php
$dom = new DOMDocument();
$dom->load("xml.xml");
$menu = new DOMXPath($dom);
$entries = $menu->query("//menu/entry");
print_r($entries);
?>

[Markus]

I'm going to compile the same PHP version and see if I get the same error.

[npm]

I ran the above code and got this:

Fatal error: Call to undefined function: load() in /home/httpd/vhosts/csnradio.com/www/test/2.php on line 3

Now what?

[HaLo2FrEeEk]

You didn't have to completely remove the foreach loop, but yes, run that and see what output you get.

[HaLo2FrEeEk]

Try creating a new variable:

$entries = $menu->query("//menu/entry");

Now do print_r($entries). Does it print anything? If so, keep the new variable and replace $menu->query("//menu/entry") in your foreach with $entries.

[Markus]

HaLo, I think we might be forgiven for this, considering PHP4 is almost a million years old. ;)

npm, is there any particular reason you're still using PHP4?

[npm]

The server is from an outside company. I've contacted them about the possibility of an upgrade. Thank you all for your time, however in vain in turned out to be. :)

[HaLo2FrEeEk]

Ask them if there's any way you can install your own custom PHP. I'm on Dreamhost and they let users install their own version of PHP, it's not difficult, just a few files to copy and some changes to the .htaccess file. Ok, it's a little more complicated than that, but not much.