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Can't include page on another php page

100+
P: 106
Hi,

I want to include a php page if the url as the variable ?logout

My objective is to show a page (logout-message.php) once user logouts (he goes automatically to mysite.com/?logout)

Please note that the logout-message.php page contains a frame, so want I want is to display that frame over the index page (mysite.com/).

Here's what I have:

Expand|Select|Wrap|Line Numbers
  1. <?php
  2. if(isset($_GET['logout']))
  3. include("logout-message.php");
  4. ?>
The code above is on the index page.

The problem I'm encountering is that the php include seems to take away all the rest of the page. When i navigate to mysite.com/?logout I see only the content of the logout-message.php page, the content of the index page is gone!

I'd appreciate your help, thanks in advance.

If you know of an easier way to do want I want, like i.e. something like php if .... (same as above) .. display content of another page.. i don't know... i'm a newbie on php..

What I want is to display the content of an external page (over the already existing index page) if the url has ?logout.

thank You.
May 5 '10 #1
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1 Reply


dlite922
Expert 100+
P: 1,584
Where is that php code snip you pasted above? is it in index.php or?

Don't know the layout of your page, but your code should work if it's in the proper place.

Let's see your entire code.






Dan
May 5 '10 #2

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