action not working after submitting form

52 New Member

This has been confusing me for a while. I don't understand why it isn't working. In my original coding, I have an action called submitted.php and this is what is looks like:

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<?php 

$data=fopen("/home/vchan/ts2/writing.txt","r+");

while(!feof($data)){

$data2=fgets($data);

$tmp=explode(",",$data2);

$project=$tmp[0];

$code=$tmp[1];

$realname=$tmp[2];

$counter=$tmp[3];

$dateentry=$tmp[4];

$name=$tmp[5];

$hours=$tmp[6];

$description=$tmp[7];

echo '$name';

}

fclose($data);
 
?>

<html>

<body>

<?php

echo 'Thank you for submitting. <br> To submit another, please click here.';

?>

</body>

</html>

<?php

echo '<form action="test5.php" method="post"> ';

echo'<p><input type="submit" value="Submit Another"/></p>';

echo '</form>';

?>

This isn't the full code but my problem is that it doesn't do anything after I open that first file hence it doesnt print "name". But oddly, it prints all the things in the end: "Thank you for submitting..."which is not related to the opening of the file. Any help would be greatly appreciated.><

Jun 11 '09 #1

Subscribe Reply

4953

Dormilich

8,658

Recognized Expert Moderator Expert

@phpnewbie26
have you checked the source code? you print the name where you're not supposed to get any visible output (i.e. outside the html page, which essentially renders your document invalid).

put your php code inside the html body.

one more, you should also don't print anything after </html> (the end of the html page)

and you should use a DTD to put IE in standards mode

Jun 11 '09 #2

phpnewbie26

New Member

i put it inside the html body and it still doesnt work..=/ and whats a DTD?

Jun 11 '09 #3

Dormilich

8,658

Recognized Expert Moderator Expert

@phpnewbie26
post your code (and maybe the file), maybe I can see anything.

@phpnewbie26
a document type definition. see XHTML and HTML specification

Jun 11 '09 #4

phpnewbie26

New Member

Okay..well, it seems that I didnt save it in the right folder, but now arises the actual problem. The first line, I changed it to

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$data=fopen("/home/$_POST["name"]/ts2/writing.txt","r+");

My problem is that in my original coding, I type my "name" in another form which is not the same as where my action="submitted.php" is. I was wondering if there is a way to carry over variables like that. I don't know if I explained myself properly.=/

Jun 12 '09 #5

phpnewbie26

New Member

So I actually got it to work by using sessions. Thanks for all the help.=D

Jun 12 '09 #6

smithroy9

New Member

Thanks for solving my problem.

Jun 18 '09 #7

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