using fgetc() on array

[phpnewbie26]

I am trying to read the first character in an array but my syntax seems to be wrong as it says I have an error. I have read each line a text file into an array and by using fgetc, I'm trying to see if the first character of each line is an "[". My current coding is:

if(fgetc($invalidcheck[$i])=='[')

Any help would be appreciated. Thanks!

[Markus]

@phpnewbie26
fgetc() expects a file resource handle as it's parameter.

Incidentally, you can check the first character of a string by accessing it like you would an array:

$string = "[hi]";
 
if ($string[0] == "[") {
    echo "yessir";
}
 

[phpnewbie26]

hm..doesnt seem to be working. My problem is that I don't know how to point to let's say $string[2] and get it's first character. I tried $string[2][0] but it still didnt work.=/

[Markus]

@phpnewbie26
Can you provide the full code please.

[phpnewbie26]

okay.=)

$invalidcheck=fgets($invalid);
for($i=0;$i<count($invalidcheck);$i++){
    if (i==0){
        $tmp=explode('=',$invalidcheck[$i]);
        if ($tmp[0]!=='MYNAME'){
            die ("typo in name.");
            }
        else{
            continue;
            }
    elseif ($invalidcheck[$i][0]=='['){
        $tmp2=substr($invalidcheck[$i],1,6);
        if ($tmp2==$todaydate){
           $counter=1;
           }
                else {$counter=0;}
        }
    else{
        $parts2=explode(' % ',$invalid[$i]);
           $parts3=explode('=', $parts2[0]);
        $parts4=explode('.', $parts3[0]);
        $check[0]=$parts4[0];
        $check[1]=$parts4[1];
        if(array_search("$check[0]", $items) && array_search("$check[1]", $items)){
            continue;}
        else{
            or die("Found error in project name/code."); 
            }
        }
fclose($invalid);
 

It's the 11th line. Thanks

[dlite922]

Troubleshooting is an aquired skill,

right after your for loop do a print_r() or var_dump() on your variable to track what they contain and see if they contain the value you expect them to.

When you say it's not working, we expect there's a PHP error, if there isn't, it's most likely has to do with your input/data.

Cheers,




Dan

[phpnewbie26]

hm..it still doesnt seem to be working. Let's say I have an array like so:

array([0]=>'red', [1]=>'green', [2]=>'blue')

how do i read let's say..the g in green.

[Markus]

@phpnewbie26

$array = array('red', 'green', 'blue'); // Note: this is the same as the example you gave.
 
$element = $array[1]; // green
echo $element[0]; // g
 

[Dormilich]

echo $array[1]{0};

works too

[Markus]

@Dormilich
Good point :D

[Markus]

@Dormilich
Just read that in PHP6 the {} notation will be dropped.

http://www.corephp.co.uk/archives/19...for-PHP-6.html

Furthermore, this works too:

<?php
 
$array = array('red', 'blue');
 
echo $array[0][0];
// Outputs 'r'.
 
?>

[phpnewbie26]

thanks guys! all of your ideas worked=).