help with eval usage

[Ciaran]

Can someone please give me a hand with this?

$arr=array(2,4,5,6);

$test='arr';

echo (eval("$".$test."[0]"));

I'm trying to get it to echo 2

Thanks a lot,
Ciarán

[Daniel Kempkens]

Ciaran schrieb:

Can someone please give me a hand with this?

$arr=array(2,4,5,6);

$test='arr';

echo (eval("$".$test."[0]"));

I'm trying to get it to echo 2

Thanks a lot,
Ciarán

Without trying it, this should work:
eval("echo $".$test."['0'];");

[Moot]

On Jun 15, 3:19 pm, Ciaran <[e-mail]:

Can someone please give me a hand with this?

$arr=array(2,4,5,6);

$test='arr';

echo (eval("$".$test."[0]"));

I'm trying to get it to echo 2

Thanks a lot,
Ciarán

Try this:
eval("echo $".$test."[0];");

Don't treat eval like a function that returns a string, make sure the
entire PHP statement is passed to it (including the ;).

An alternative, that looks like what you were trying to accomplish,
but without the eval would be:
echo ${$test}[0];

[Ciaran]

On Jun 15, 8:39 pm, Moot <[e-mail]:

On Jun 15, 3:19 pm, Ciaran <[e-mail]:

Can someone please give me a hand with this?

$arr=array(2,4,5,6);

$test='arr';

echo (eval("$".$test."[0]"));

I'm trying to get it to echo 2

Thanks a lot,
Ciarán

Try this:
eval("echo $".$test."[0];");

Don't treat eval like a function that returns a string, make sure the
entire PHP statement is passed to it (including the ;).

An alternative, that looks like what you were trying to accomplish,
but without the eval would be:
echo ${$test}[0];

Oh great thanks , that works well. I'm used to the eval function in
flash actionscript and I just thought the php one would be the same.
What if I wanted to duplicate the original array?

$arr2=${$test};

??
Cheers

[Daniel Kempkens]

Ciaran schrieb:

On Jun 15, 8:39 pm, Moot <[e-mail]:

>On Jun 15, 3:19 pm, Ciaran <[e-mail]:

>>Can someone please give me a hand with this?
$arr=array(2,4,5,6);
$test='arr';
echo (eval("$".$test."[0]"));
I'm trying to get it to echo 2
Thanks a lot,
Ciarán

Try this:
eval("echo $".$test."[0];");

Don't treat eval like a function that returns a string, make sure the
entire PHP statement is passed to it (including the ;).

An alternative, that looks like what you were trying to accomplish,
but without the eval would be:
echo ${$test}[0];

Oh great thanks , that works well. I'm used to the eval function in
flash actionscript and I just thought the php one would be the same.
What if I wanted to duplicate the original array?

$arr2=${$test};

??
Cheers

Works exactly the way you guessed ;)

[Rik]

On Fri, 15 Jun 2007 21:19:50 +0200, Ciaran <cr*******@hotmail.comwrote:

Can someone please give me a hand with this?

$arr=array(2,4,5,6);

$test='arr';

echo (eval("$".$test."[0]"));

I'm trying to get it to echo 2

Eval doesn't return anything if you don't tell it to. You could use a
return though (the same as in function/methods/included files).

So, to echo it, you could use: echo eval('return $'.$test.'[0]');

The curly braces method as described by others is preferable though.
--
Rik Wasmus

[Ciaran]

On Jun 15, 8:53 pm, Daniel Kempkens <[e-mail]:

Ciaran schrieb:

On Jun 15, 8:39 pm, Moot <[e-mail]:

On Jun 15, 3:19 pm, Ciaran <[e-mail]:

>Can someone please give me a hand with this?
$arr=array(2,4,5,6);
$test='arr';
echo (eval("$".$test."[0]"));
I'm trying to get it to echo 2
Thanks a lot,
Ciarán
Try this:
eval("echo $".$test."[0];");

Don't treat eval like a function that returns a string, make sure the
entire PHP statement is passed to it (including the ;).

An alternative, that looks like what you were trying to accomplish,
but without the eval would be:
echo ${$test}[0];

Oh great thanks , that works well. I'm used to the eval function in
flash actionscript and I just thought the php one would be the same.
What if I wanted to duplicate the original array?

$arr2=${$test};

??
Cheers

Works exactly the way you guessed ;)- Hide quoted text -

- Show quoted text -

Great! That seems to be the functionality I was looking for with eval.
Thanks for the help guys!

[gosha bine]

Ciaran wrote:

Can someone please give me a hand with this?

$arr=array(2,4,5,6);

$test='arr';

echo (eval("$".$test."[0]"));

I'm trying to get it to echo 2

Thanks a lot,
Ciarán

$arr=array(2,4,5,6);
$test='arr';
echo ${$test}[0];

no need of eval.
--
gosha bine

extended php parser ~ http://code.google.com/p/pihipi
blok ~ http://www.tagarga.com/blok