Holiday Planner

4 New Member

Hi, I am trying to build a holiday planner and need to be able to overcome a problem with my output with the dates. I have manipulated a calendar script to output days of the month in columns, (1 2 3 4 5 6 etc) This works fine when the month is input it shows exact days for that month. What I cannot do is repeat this for the days of the month ie M T W T F and so on. Does anyone have any
1 2 3 4 5
idea how I can relove this issue.

Regards Sid

Jun 15 '07 #1

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2405

pbmods

5,821

Recognized Expert Expert

Heya, sidders. Welcome to TSDN!

This works fine when the month is input it shows exact days for that month. What I cannot do is repeat this for the days of the month ie M T W T F and so on.

I'm not sure I understand what you're asking. Do you want to output day-of-the-week headers for your calendar? Or do you need to determine which day of the week a given date is?

Jun 15 '07 #2

Motoma

3,237

Recognized Expert Specialist

PHP has built in functions for dealing with dates, including the ability to get the day of the week.

Jun 15 '07 #3

epots9

1,351

Recognized Expert Top Contributor

u do only want to display Monday to Friday, excluding Suturday and Sunday?

Jun 15 '07 #4

sidders

New Member

Hi again, well what I am looking for is similar to the normal calendar output which shows S M T W T F S, however instead of dropping to the next row I need it to continue along the columns until it reaches the end of the month so the table will look like S M T W T F S S M T W T F S S M T W T F S etc. I have the columns of numbers but not the day headers above. I have posted some code below as to where my problem lies. The code below is just the basic structure, for obvious reasons I have stripped out all the SQL

Thanks in advance Sidders.

Expand|Select|Wrap|Line Numbers

 
    <? 
 
        if(isset($todo) and $todo=="submit"){

        $date_value="$month/$dt/$year";

        echo "mm/dd/yyyy format :$date_value<br>";

        $date_value="$year-$month-$dt";

        echo "YYYY-mm-dd format :$date_value<br>";

            }
 
        $Month = $_GET['month'];

        $Year = $_GET['year'];
 
        //echo $Month;

        //echo $Year;
 
        //This gets todays date

         $date =time ();
 
        //This puts the day, month, and year in seperate variables

        $day = date('d', $date); 

        $month = date('m', $date); 

        $year = date('Y', $date);
 
        //Here we generate the first day of the month

        $first_day = mktime(0,0,0,$month, 1, $year); 
 
        //This get's us the month name

        $title = date('F', $first_day); 
 
        //Here we find out what day of the week the first day of the month falls on

        $day_of_week = date('D', $first_day); 
 
        echo $day_of_week;
 
        ?>

    <html>

    <body>

        <form method='GET' name='Form1' action='<? $_SERVER['PHP_SELF'];?>'>

    <table border="0" cellspacing="0" >

        <tr><td align=left >

        </select>&nbsp;&nbsp;&nbsp; 

        <select name=month value=''>Select Month</option>

        <option value='01'>January</option>

        <option value='02'>February</option>

        <option value='03'>March</option>

        <option value='04'>April</option>

        <option value='05'>May</option>

        <option value='06'>June</option>

        <option value='07'>July</option>

        <option value='08'>August</option>

        <option value='09'>September</option>

        <option value='10'>October</option>

        <option value='11'>November</option>

        <option value='12'>December</option>

        </select>
 
        </td><td align=left > 

    Year(yyyy)<input type=text name=year size=4 value=2005>

        <input type=submit value=Submit>

    </table>

        </form> 

    <?
 
        function showMonth($month, $year)

            {

        $date = mktime(12, 0, 0, $month, 1, $year);

        $daysInMonth = date("t", $date);

        // calculate the position of the first day in the calendar (sunday = 1st column, etc)

        $offset = date("w", $date);

        //echo $offset;

           $rows = 1;

        $dateDay=cal_to_jd(CAL_GREGORIAN,date("m"),date("d"),date("Y"));

        $ddate = (jddayofweek($dateDay,2));

        echo $ddate;

        //for($ddate = 1; $ddate <= $offset; $ddate++)

        function myfunction() 

              {

        for($i = 1; $i != 31; $i++)

        echo $ddate;

              }

    ?>

       <h1>Displaying calendar for  <?  date("F Y", $date); ?> </h1>

    <table border="1">
 
     <tr>

     <td bgcolor="#666666"><? 

        echo $_GET['action'];

    ?> </td>

       <?
 
        for($i = 1; $i <= $daysInMonth; $i++)

            {

    ?>

     <td> 

    <? 

         myfunction()  ?>&nbsp;</td>

    <?

            }

        while( ($i + $offset) <= $rows  )

            {

    ?>

     <td></td>

    <?    

        $i++;

        }

    ?>
 
    </tr><tr>

    <td bgcolor="#666666">&nbsp; </td>        

    <?

         for($day = 1; $day <= $daysInMonth; $day++)

            {

    ?>

     <td> 

    <? echo $day; ?> </td>

    <?

        }

        while( ($day + $offset) <= $rows  )

        {

    ?>

     <td></td>

    <?    

        $day++;

        }

    ?>

    </tr>

 </table>

    <?

        }

    ?>

Displaying the calendar in a page

To display it in a HTML page, you just need to include a call to the showMonth() function, passing the desired month and year as paramters.

For example:

    <? 

    showMonth($Month, $Year); // July 2005

   //showMonth(1, 1980); // January 1980  

  // showMonth(12, 2012); // December 2012 ?>

</body>

</html>

Jun 18 '07 #5

Motoma

3,237

Recognized Expert Specialist

I am sorry, but I couldn't entirely follow what you were trying to do with your code. Could you please elaborate on what you are trying to do, as well as give the errors you are receiving and detail what is going wrong?

Jun 18 '07 #6

sidders

New Member

Hi ok sorry if it a little bit unclear, I will try to get this a simple as possible. A normal calendar out puts 7 days then adds the rows accordingly. I want the planner to show the month dates in line like my code already does. What I want and cannot yet do is to show the day above the day number so for instance June the 1st would be F(Friday) above the 1 and then so forth until S(Saturday) above the 30 in the column. Hope that explains it a little more.

Jun 18 '07 #7

pbmods

5,821

Recognized Expert Expert

So you want to be able to create a calendar with != 7 columns? Or put another way, you want to be able to put every single day of a month on one row? Is this correct?

Jun 18 '07 #8

sidders

New Member

So you want to be able to create a calendar with != 7 columns? Or put another way, you want to be able to put every single day of a month on one row? Is this correct?

Yes that is correct, what it will be able to do is print a list of names that have holidays in that month I can then cross reference graphically the days people overlap with holidays similar to a gantt chart.

Jun 18 '07 #9

Motoma

3,237

Recognized Expert Specialist

Hi ok sorry if it a little bit unclear, I will try to get this a simple as possible. A normal calendar out puts 7 days then adds the rows accordingly. I want the planner to show the month dates in line like my code already does. What I want and cannot yet do is to show the day above the day number so for instance June the 1st would be F(Friday) above the 1 and then so forth until S(Saturday) above the 30 in the column. Hope that explains it a little more.

The following code returns an associative array for the month you specify. The array index is the day of the month, and the value is the three letter representation of the day of the week.

Expand|Select|Wrap|Line Numbers

 
function buildMonth($month, $year)

{

  $ret = array();

  for($i = 1; $i <= mcal_days_in_month($month, $year); $i++)

  {

    $ret[i] = date('D', mktime(0, 0, 0, $month, $i, $year));

  }

  return $ret;

}

Jun 18 '07 #10

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