hii,
I am going to build menus and sub menus.I have fetch data from the table and it sucessfully display the menus and submenus..
But I have problem is that the menus displayed as un -orderd list .That menu i want to display horizontaly..
Here is the php code for that .. - <?php
-
// include your database connection file here (if available)
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// for example require_once("../../db.php");
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include_once('dbconn.php');
-
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$sql = "SELECT id, label, link_url, parent_id FROM dyn_menu ORDER BY parent_id, id ASC";
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$items = mysql_query($sql);
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while ($obj = mysql_fetch_object($items))
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{
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if ($obj->parent_id == 0) {
-
-
$parent_menu[$obj->id]['label'] = $obj->label;
-
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$parent_menu[$obj->id]['link'] = $obj->link_url;
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echo "| ";
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} else {
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$sub_menu[$obj->id]['parent'] = $obj->parent_id;
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$sub_menu[$obj->id]['label'] = $obj->label;
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$sub_menu[$obj->id]['link'] = $obj->link_url;
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if (!isset($parent_menu[$obj->parent_id]['count'])) {
-
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$parent_menu[$obj->parent_id]['count'] = 0;
-
-
}
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$parent_menu[$obj->parent_id]['count']++;
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}
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}
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mysql_free_result($items);
-
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function dyn_menu($parent_array, $sub_array, $qs_val = "menu", $main_id = "nav", $sub_id = "subnav", $extra_style = "foldout") {
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$menu = "<ul id=\"".$main_id."\"> ";
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foreach ($parent_array as $pkey => $pval) {
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if (!empty($pval['count'])) {
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$menu .= " <li><a class=\"".$extra_style."\" href=\"".$pval['link']."?".$qs_val."=".$pkey."\">".$pval['label']."</a></li> ";
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} else {
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$menu .= " <li><a href=\"".$pval['link']."\">".$pval['label']."</a></li> ";
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}
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if (!empty($_REQUEST[$qs_val])) {
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$menu .= "<ul id=\"".$sub_id."\"> ";
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foreach ($sub_array as $sval) {
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if ($pkey == $_REQUEST[$qs_val] && $pkey == $sval['parent']) {
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$menu .= "<li><a href=\"".rebuild_link($sval['link'], $qs_val, $sval['parent'])."\" target=\"_blank\">".$sval['label']."</a></li> ";
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}
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}
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$menu .= "</ul> ";
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}
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}
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$menu .= "</ul>\n";
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return $menu;
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}
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function dyn_menu_folded($parent_array, $sub_array, $qs_val = "menu", $main_id = "nav", $sub_id = "subnav", $extra_style = "foldout") {
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$menu = "<ul id=\"".$main_id."\">\n";
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foreach ($parent_array as $pkey => $pval) {
-
if (!empty($pval['count'])) {
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$menu .= " <li><a class=\"".$extra_style."\" href=\"".$pval['link']."?".$qs_val."=".$pkey."\">".$pval['label']."</a></li>\n";
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} else {
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$menu .= " <li><a href=\"".$pval['link']."\">".$pval['label']."</a></li>\n";
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}
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//if (!empty($_REQUEST[$qs_val])) {
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$menu .= "<ul id=\"".$sub_id."\">\n";
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foreach ($sub_array as $sval) {
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if ($pkey == $sval['parent']) { //
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$menu .= "<li><a href=\"".$sval['link']."\" target=\"_blank\">".$sval['label']."</a></li>\n";
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}
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}
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$menu .= "</ul>\n";
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//}
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}
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$menu .= "</ul>\n";
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return $menu;
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}
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function rebuild_link($link, $parent_var, $parent_val) {
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$link_parts = explode("?", $link);
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$base_var = "?".$parent_var."=".$parent_val;
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if (!empty($link_parts[1])) {
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$link_parts[1] = str_replace("&", "##", $link_parts[1]);
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$parts = explode("##", $link_parts[1]);
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$newParts = array();
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foreach ($parts as $val) {
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$val_parts = explode("=", $val);
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if ($val_parts[0] != $parent_var) {
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array_push($newParts, $val);
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}
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}
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if (count($newParts) != 0) {
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$qs = "&".implode("&", $newParts);
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}
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return $link_parts[0].$base_var.$qs;
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} else {
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return $link_parts[0].$base_var;
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}
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}
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?>
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
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<html>
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<head>
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<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
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<title>Dynamic PHP navigation list example page</title>
-
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<script type="text/javascript" src="dhtml-menu.js" language="javascript"></script>
-
-
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<style type="text/css">
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<!--
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body {
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font-family:Arial, Helvetica, sans-serif;
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padding:0 15px;
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}
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p, li { font-size:12px;line-height:16px; }
-
-
#disply
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{
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width:40 px;
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height:40px;
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display
-
-->
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</style>
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</head>
-
-
<body>
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<!--<h2>Dynamic PHP navigation list tutorial (example)</h2>
-
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<p>The unordered list below is generated by the code used in the tutorial. Click the main items (Job groups) to make the sub-items visible.</p>
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<p>We created also a second menu which shows all sub items, to get this effect we removed the code <strong>$pkey == $_REQUEST[$qs_val] && </strong> from the second <strong>foreach</strong> loop and the if statement <strong>if (!empty($_REQUEST[$qs_val]))</strong>.</p>-->
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<div style="float:right;width:340px;">
-
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<?php
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//echo dyn_menu_folded($parent_menu, $sub_menu, "menu", "nav", "subnav");
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?>
-
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</div>
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<?php
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echo dyn_menu($parent_menu, $sub_menu, "menu", "nav", "subnav");
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?>
-
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<p style="clear:both;"></p>
-
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</body>
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</html>
.........Please Help me out..
Any help would be appriciated...
Thax..
3  3685  Dormilich 8,658
Recognized Expert Moderator Expert
whether you display this menu horizontal or vertical is a CSS problem (because that is where you define the styling). PHP is providing only the bare content.
Im new in php mysql..I dont understand how and where should i palce the css..I tried bt nothing come out
The out put Like some as way..
Home
About Us
Contact Us
Help.
When i clik on Home ....HOme1 & Home2 appears and when click on second it hides first menus&submenus. . THis is fine, But Im confused how should i pace css here...
Please give me solution for this..
thanx...
Dormilich 8,658
Recognized Expert Moderator Expert
CSS definitions usually go into a CSS file that is included in the <head> section.
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