Hey, I'm getting the error:
Parse error: syntax error, unexpected T_VARIABLE in /Users/Oscar/AwesomeSongz/userCake/profile.php on line 7
with this code - <?php
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require_once("models/config.php");
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function signinTimeStamp()
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{
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$sql = "SELECT LastSignIn FROM ".$db_table_prefix."Users WHERE User_ID = '"$user"'";
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$result = $db->sql_query($sql);
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$row = $db->sql_fetchrow($result);
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return ($row['LastSignIn']);
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}
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function signupTimeStamp()
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{
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$sql = "SELECT SignUpDate FROM ".$db_table_prefix."Users WHERE User_ID = '"$user"'";
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$result = $db->sql_query($sql);
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$row = $db->sql_fetchrow($result);
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return ($row['SignUpDate']);
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}
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function groupID()
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{
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$sql = "SELECT ".$db_table_prefix."Users.Group_ID, ".$db_table_prefix."Groups.* FROM ".$db_table_prefix."Users INNER JOIN ".$db_table_prefix."Groups ON ".$db_table_prefix."Users.Group_ID = ".$db_table_prefix."Groups.Group_ID WHERE User_ID = '". $user ."'";
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$result = $db->sql_query($sql);
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$row = $db->sql_fetchrow($result);
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$db->sql_freeresult($result);
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return($row);
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}
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$user = $_GET["user"];
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//Prevent the user visiting the logged in page if he/she is not logged in
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if(!isUserLoggedIn()) { header("Location: login.php"); die; }
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?>
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<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
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<html xmlns="http://www.w3.org/1999/xhtml">
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<head>
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<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
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<title>Welcome <?php echo $loggedInUser->display_username; ?></title>
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<link href="cakestyle.css" rel="stylesheet" type="text/css" />
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</head>
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<body>
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<div id="wrapper">
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<div id="logo"></div>
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<!--
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This is an simple profile page. You can easily get access to
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user properties via $loggedInUser variable which is globally accessible.
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-->
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<div id="regbox">
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<?php if(usernameExists($_GET["user"])) {?>
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<div style="text-align:center; padding-top:15px;">
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Welcome to <strong><?php echo $user ?>'s</strong> profile.</p>
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<p><?php echo $user ?> is a <strong><?php $group = $loggedInUser->groupID(); echo $group['Group_Name']; ?></strong></p>
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<p><?php echo $user ?> joined on <?php echo date("l \\t\h\e jS Y",$loggedInUser->signupTimeStamp()); ?> </p>
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<p><?php echo $user ?> last logged in on <?php echo date("l \\t\h\e jS Y",$loggedInUser->signinTimeStamp()); ?> </p>
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</div>
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<?php
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} else {
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echo "This is not a valid username, <strong> " .$loggedInUser->display_username. " </strong></p>";
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}
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?>
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</div>
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</div>
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</body>
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</html>
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<?php include("models/clean_up.php"); ?>
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14  3596  Dormilich 8,658
Recognized Expert Moderator Expert
Sorry, Typed it wrong, should have been line 7
You most probably have an open parenthesis somewhere.
Like:
if $success) { // missing start paren
// do something
}
Basically, the PHP interpreter has found a variable reference when it was most likely (as mentioned) expecting a parenthesis .
Look in /profile.php which it doesn't appear you've posted above.
see: http://www.php.net/tokens for a explanation of PHP's tokens and other stuff.
Dormilich 8,658
Recognized Expert Moderator Expert
there are the concatenation operators missing around $user.
What line is the $user on?
Dormilich 8,658
Recognized Expert Moderator Expert
this one:
Sorry, Typed it wrong, should have been line 7
Line 7 should be: -
$sql = "SELECT LastSignIn FROM ".$db_table_prefix."Users WHERE User_ID = '$user'";
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Are you sure User_ID is a string?
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If it's an integer, then the line should probably be:
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$sql = "SELECT LastSignIn FROM ".$db_table_prefix."Users WHERE User_ID = $user";
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As a matter of fact, you can just eliminate the concatenation all together.
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i.e.
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$sql = "SELECT LastSignIn FROM $db_table_prefix Users WHERE User_ID = '$user'";
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- or if integer -
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$sql = "SELECT LastSignIn FROM $db_table_prefix Users WHERE User_ID = $user";
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-also-
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$sql = sprintf("SELECT LastSignIn FROM $db_table_prefix Users WHERE User_ID = '%s'",$user);
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-or if intger -
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$sql = sprintf("SELECT LastSignIn FROM $db_table_prefix Users WHERE User_ID = %d",$user);
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Didn't catch the db concatenation chars...
Good catch Dormilich...
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