hi.i have got a problem.
error message:
Parse error: syntax error, unexpected T_VARIABLE in c:\wamp\www\dyn amic2.php on line 12
for the line: - $result=mysql_query("select company from dynamic where id="$id) or die(mysql_error());
if anyone help me,i will be greatful.
6  2663  Dormilich 8,658
Recognized Expert Moderator Expert
syntax error in function argument
[PHP]// either
mysql_query("sq l" . $var)
// or
mysql_query("sq l $var")[/PHP]
don't forget to sanitize your input!
regards
nathj 938
Recognized Expert Contributor
1. Try using code tags next time
2. Try changing the code to: -
$result=mysql_query("select company from dynamic where id=$id") or die(mysql_error());
-
I have brought the variable inside the string.
Cheers
nathj
Markus 6,050
Recognized Expert Expert
Mushfiq, to date you have named every thread you have started Dynamic Link. This explains nothing of the problem in this thread. We expect you to provide a meaningful title as it helps others who are searching the forum with the same problem.
Please take note of this as I have already warned you for not using code tags (and you have failed to do so again).
Read Posting Guidelines.
Moderator.
change the code to
$result=mysql_q uery("select company from dynamic where `id`="$id) or die(mysql_error ());
Dormilich 8,658
Recognized Expert Moderator Expert
@divyac this will result in the same error (for exactly the same reasons) plus the quotation marks are in the wrong place
* sigh*
for some basics on strings read this Markus 6,050
Recognized Expert Expert
To all concerned it's called 'concatenation' .
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