Hello,
pretend some noob has (in a fake-static class) provided the following method
public static kill_object($ob j)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
Obviously noob is heading at destroying an object!
Does he succeed?
Let's see:
<code>
$blubber = new crazy_object... ;
... some schnickschnack. ..
if (!static_class: :kill_object($b lubber))
exit(0);
print_r($blubbe r);
if (isset($blubber ))
print "I'm Blubber\n";
else
print "I'm Blubber no more\n";
</code>
noob would expect to see no print_r-output and the message should be
"I'm Blubber no more"
Actually, things are quite different:
1st: Object is printed per print_r
2nd: Message is "I'm Blubber"
Haven't I just killed the object...? Objects, when supplied as parameter,
are passed by reference in php5, aren't they?
OK, that obviously did not work (somehow... - remember, I'm a noob).
I reformulate the static kill_object-method:
public static kill_object(&$o bj)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
Note, that there comes the old (deprecated) reference-operator '&' (that -
for objects - is no longer needed in php5, right?)
This time, however, the result is:
1st: Object is no longer printed (per print_r)
2nd: Message is "I'm Blubber no more"
Please assist!
cheers
juergen 4 2024
Juergen-Bernhard Adler wrote:
Hello,
pretend some noob has (in a fake-static class) provided the following method
public static kill_object($ob j)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
Obviously noob is heading at destroying an object!
Does he succeed?
Let's see:
<code>
$blubber = new crazy_object... ;
... some schnickschnack. ..
if (!static_class: :kill_object($b lubber))
exit(0);
print_r($blubbe r);
if (isset($blubber ))
print "I'm Blubber\n";
else
print "I'm Blubber no more\n";
</code>
noob would expect to see no print_r-output and the message should be
"I'm Blubber no more"
Actually, things are quite different:
1st: Object is printed per print_r
2nd: Message is "I'm Blubber"
Haven't I just killed the object...? Objects, when supplied as parameter,
are passed by reference in php5, aren't they?
OK, that obviously did not work (somehow... - remember, I'm a noob).
I reformulate the static kill_object-method:
public static kill_object(&$o bj)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
Note, that there comes the old (deprecated) reference-operator '&' (that -
for objects - is no longer needed in php5, right?)
This time, however, the result is:
1st: Object is no longer printed (per print_r)
2nd: Message is "I'm Blubber no more"
Please assist!
cheers
juergen
First of all, static methods don't work on objects - they work on the class.
But PHP will destroy an object sometime after the last reference to the
object is removed. If this is your ONLY reference to the object, at
some time, when the PHP garbage collector runs, the object will be deleted.
But this isn't necessarily the only reference to the object, and the
garbage collector won't necessarily run immediately.
It's not like C++ or SmallTalk, where the destructor can destroy an
object immediately.
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
=============== ===
Jerry Stuckle wrote:
Juergen-Bernhard Adler wrote:
>Hello,
pretend some noob has (in a fake-static class) provided the following method
public static kill_object($ob j) {
if (!is_object($ob j)) return false;
$obj = null;
return true;
}
Obviously noob is heading at destroying an object!
Does he succeed?
Let's see:
<code>
$blubber = new crazy_object... ;
... some schnickschnack. ..
if (!static_class: :kill_object($b lubber)) exit(0); print_r($blubbe r);
if (isset($blubber )) print "I'm Blubber\n"; else print "I'm Blubber no more\n";
</code>
noob would expect to see no print_r-output and the message should be
"I'm Blubber no more"
Actually, things are quite different:
1st: Object is printed per print_r
2nd: Message is "I'm Blubber"
Haven't I just killed the object...? Objects, when supplied as parameter, are passed by reference in php5, aren't they?
OK, that obviously did not work (somehow... - remember, I'm a noob).
I reformulate the static kill_object-method:
public static kill_object(&$o bj) {
if (!is_object($ob j)) return false;
$obj = null;
return true;
}
Note, that there comes the old (deprecated) reference-operator '&' (that - for objects - is no longer needed in php5, right?)
This time, however, the result is:
1st: Object is no longer printed (per print_r)
2nd: Message is "I'm Blubber no more"
Please assist!
cheers
juergen
First of all, static methods don't work on objects - they work on the
class.
But PHP will destroy an object sometime after the last reference to the
object is removed. If this is your ONLY reference to the object, at
some time, when the PHP garbage collector runs, the object will be deleted.
But this isn't necessarily the only reference to the object, and the
garbage collector won't necessarily run immediately.
It's not like C++ or SmallTalk, where the destructor can destroy an
object immediately.
In fact, when the reference to an object are set to NULL, the
object should be inaccessible from that reference. From the
programmers point of view, it should be the same object destroyed.
System may have need to keep the actual data, but that is the benefit of
GC, programmer does not need to manage memory allocation.
B
Hello Jerry, hello "Blueparty" ,
many thanks for your replies.
I know there is garbage collection. However, if you do have a relatively
large script, therein looping through a vast amount of data directories,
faced with the necessity to (re-)instantiate big (mostly aggregated)
objects inside various loop levels... - in situations like these it would -
for the sake of efficiency ?! - be nice to destroy what is no longer needed
(maybe I should change my programming style altogether; but that's a
different story).
Now to the problem itself: My premiss was, that
$object = null;
would effectively destroy the object - as it has been suggested in various
forums. What I erroneously attempted was to put this statement inside a
static method.
<code_version 1>
public static function kill_object($ob j)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
</code_version1>
I learned that calling the method
some_pseudo_sta tic_class::kill _object($someob ject);
by no means killed $someobject. At this point I was wondering why - since in
php5 objects are passed by reference... so passing it to the method and
setting it to null therein, was expected to do the job...
I then tried the deprecated way with the '&' operator:
<code_version 2>
public static function kill_object(&$o bj)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
</code_version2>
This one worked, so I became confused... I thought, with php5, '&' was no
longer needed...
The solution is explained in this article: http://mjtsai.com/blog/2004/07/15/ph...ct-references/
It appears that my problem boils down to a misapprehension of what "passing
an object by reference" really means...
As stated in one of the comments following the article:
<cite>
holy cow, so in PHP5, $obj = $obj2
and $obj =& $obj2 are different things...
</cite>
....and so are
public static function kill_object($ob j)
public static function kill_object(&$o bj)
Cheers
Jürgen
Juergen-Bernhard Adler wrote:
Hello Jerry, hello "Blueparty" ,
many thanks for your replies.
I know there is garbage collection. However, if you do have a relatively
large script, therein looping through a vast amount of data directories,
faced with the necessity to (re-)instantiate big (mostly aggregated)
objects inside various loop levels... - in situations like these it would -
for the sake of efficiency ?! - be nice to destroy what is no longer needed
(maybe I should change my programming style altogether; but that's a
different story).
Now to the problem itself: My premiss was, that
$object = null;
would effectively destroy the object - as it has been suggested in various
forums. What I erroneously attempted was to put this statement inside a
static method.
<code_version 1>
public static function kill_object($ob j)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
</code_version1>
I learned that calling the method
some_pseudo_sta tic_class::kill _object($someob ject);
by no means killed $someobject. At this point I was wondering why - since in
php5 objects are passed by reference... so passing it to the method and
setting it to null therein, was expected to do the job...
I then tried the deprecated way with the '&' operator:
<code_version 2>
public static function kill_object(&$o bj)
{
if (!is_object($ob j))
return false;
$obj = null;
return true;
}
</code_version2>
This one worked, so I became confused... I thought, with php5, '&' was no
longer needed...
The solution is explained in this article:
http://mjtsai.com/blog/2004/07/15/ph...ct-references/
It appears that my problem boils down to a misapprehension of what "passing
an object by reference" really means...
As stated in one of the comments following the article:
<cite>
holy cow, so in PHP5, $obj = $obj2
and $obj =& $obj2 are different things...
</cite>
...and so are
public static function kill_object($ob j)
public static function kill_object(&$o bj)
Cheers
Jürgen
Yes, Jürgen, it can be confusing. In this case, the object is passed by
reference - but not the variable. So anything you do on the object will
affect the object in both places. But if you change the variable
($obj), it will not change the original variable.
A subtle, but important difference in some cases.
But you don't necessarily need to set the variable to null to get rid of
the object - setting the variable to any value (including that of a new
object of the same type) will do the same thing, assuming that is the
only reference to the object.
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
=============== === This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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