Nested foreach loop over same array

[Ivan S]

I'm using next snippet:

$somearray = array(...);

foreach($somear ray as $item1) {
foreach($item1 as $item2) {
// ... do something ...
}
}

....and I'm getting next error:
Invalid argument supplied for foreach()

on second foreach.

This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
but site seems to work ok.
Is there any way to avoid that error?
Tnx.

[Erwin Moller]

Ivan S schreef:

I'm using next snippet:

$somearray = array(...);

foreach($somear ray as $item1) {
foreach($item1 as $item2) {
// ... do something ...
}
}

...and I'm getting next error:
Invalid argument supplied for foreach()

on second foreach.

Hi Ivan,

Nothing wrong with your code.
The two foreach constructs should be no problem.
I expect that the original array isn't containing what you expect it to
contain.
Since you use a foreach on every value in the $somearray, this array
should contain of arrays itself.

Test that like this:
echo "<pre>";
print_r($somear ray);
echo "</pre>";
exit;

Regards,
Erwin Moller

>
This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
but site seems to work ok.
Is there any way to avoid that error?
Tnx.

[Olaf Schinkel]

Ivan S schrieb:

I'm using next snippet:

$somearray = array(...);

foreach($somear ray as $item1) {
foreach($item1 as $item2) {
// ... do something ...
}
}

...and I'm getting next error:
Invalid argument supplied for foreach()

on second foreach.

This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
but site seems to work ok.
Is there any way to avoid that error?
Tnx.

The function is_array() exists :-)

[Ivan S]

On 9 srp, 12:06, Erwin Moller
<Since_humans_r ead_this_I_am_s pammed_too_m... @spamyourself.c omwrote:

Ivan S schreef:

I'm using next snippet:

$somearray = array(...);

foreach($somear ray as $item1) {
* * * foreach($item1 as $item2) {
* * * * * * // ... do something ...
* * *}
}

...and I'm getting next error:
Invalid argument supplied for foreach()

on second foreach.

Hi Ivan,

Nothing wrong with your code.
The two foreach constructs should be no problem.
I expect that the original array isn't containing what you expect it to
contain.
Since you use a foreach on every value in the $somearray, this array
should contain of arrays itself.

Test that like *this:
echo "<pre>";
print_r($somear ray);
echo "</pre>";
exit;

Regards,
Erwin Moller

This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
but site seems to work ok.

Is there any way to avoid that error?

Tnx.

Hi Erwin. :)

Your advice helped, some items in $somearray weren't arrays it self,
that was reason why i got errors reported.

Thanks for your help.

[Ivan S]

On 10 srp, 05:25, Olaf Schinkel <tr...@schinkel .tvwrote:

Ivan S schrieb:

I'm using next snippet:

$somearray = array(...);

foreach($somear ray as $item1) {
* * * foreach($item1 as $item2) {
* * * * * * // ... do something ...
* * *}
}

...and I'm getting next error:
Invalid argument supplied for foreach()

on second foreach.

This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
but site seems to work ok.

Is there any way to avoid that error?

Tnx.

The function is_array() exists :-)

I know that...I wasn't aware that my input array could contain
unexpected values (such as non array values).

[Barry]

"Ivan S" <iv*********@gm ail.comwrote in message
news:f0******** *************** ***********@i76 g2000hsf.google groups.com...
On 10 srp, 05:25, Olaf Schinkel <tr...@schinkel .tvwrote:

Ivan S schrieb:

I'm using next snippet:

$somearray = array(...);

foreach($somear ray as $item1) {
foreach($item1 as $item2) {
// ... do something ...
}
}

...and I'm getting next error:
Invalid argument supplied for foreach()

on second foreach.

This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
but site seems to work ok.

Is there any way to avoid that error?

Tnx.

The function is_array() exists :-)

I know that...I wasn't aware that my input array could contain
unexpected values (such as non array values).
=========

strictly speaking, avoid the error like this:

$somearray = array(...);
foreach ($somearray as $item1)
{
if (!is_array($ite m1)){ $item1 = array($item1); }
foreach ($item1 as $item2)
{
// do something...
}
}

that way, if $item1 is not an array but still a usable, otherwise valid,
value then your next foreach will be able to process it normally...base d on
whatever '...do something...' is.