HI all,
I am able to upload the image as blob to mysql. but while displaying the image i cant display it properly .
The code used for uploading image to mysql inserts data into mysql table.The uploading code is: -
MYSQL_CONNECT("localhost","root","");
-
mysql_select_db("sample");
-
-
$data = addslashes(fread(fopen($form_data, "r"), filesize($form_data)));
-
-
$result=MYSQL_QUERY("INSERT INTO PHOTO(description,bin_data,filename,filesize,filetype) ".
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"VALUES ('$form_description','$data','$form_data_name','$form_data_size','$form_data_type')");
-
The code used for displaying the image is as follows -
<?php
-
MYSQL_CONNECT("localhost","root","");
-
mysql_select_db("sample");
-
-
$id=2;
-
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$query = "select filename,filetype,filesize,bin_data from PHOTO where id=$id";
-
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$result = mysql_query($query) or die('Error, query failed');
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//$ROW = mysql_fetch_assocc($result);
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list($name, $type, $size, $content) = mysql_fetch_array($result);
-
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echo '<meta http-equiv="Content-Type" content="img/jpg" />';
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echo $content;
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exit;
-
-
?>
-
This code displays some random characters all over the browser but not the image. I think i have been missing some statements .
Thank you
4 8147 Markus 6,050
Recognized Expert Expert
You have to set the headers properly.
Read this tutorial. (scroll down to the part about downloading.)
this might help u
[PHP]$query = "SELECT Doc,Doc1,Doc2,N ame,Name1,Name2 FROM xyz WHERE id = '".$id."'";
$result = mysql_query($qu ery) or die('Error, query failed');
list($Doc,$Doc1 ,$Doc2,$Name,$N ame1,$Name2) = mysql_fetch_arr ay($result);
//header("Content-length: $size");
header("Pragma: public");
header("Expires : 0"); // set expiration time
header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
//header("cache-Control: no-cache, must-revalidate"); // HTTP/1.1 changed on 27th july commented this and next line and addedprevious 3 lines for IE caching prob
//header("Expires : Mon, 26 Jul 1997 05:00:00 GMT"); // Date in the past
header("Content-type: application/pdf");
header("Content-Disposition: attachment; filename=$Name" );
echo $Name;
echo $Doc;
[/PHP]
Markus 6,050
Recognized Expert Expert
this might help u
[PHP]$query = "SELECT Doc,Doc1,Doc2,N ame,Name1,Name2 FROM xyz WHERE id = '".$id."'";
$result = mysql_query($qu ery) or die('Error, query failed');
list($Doc,$Doc1 ,$Doc2,$Name,$N ame1,$Name2) = mysql_fetch_arr ay($result);
//header("Content-length: $size");
header("Pragma: public");
header("Expires : 0"); // set expiration time
header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
//header("cache-Control: no-cache, must-revalidate"); // HTTP/1.1 changed on 27th july commented this and next line and addedprevious 3 lines for IE caching prob
//header("Expires : Mon, 26 Jul 1997 05:00:00 GMT"); // Date in the past
header("Content-type: application/pdf");
header("Content-Disposition: attachment; filename=$Name" );
echo $Name;
echo $Doc;
[/PHP]
He's not trying to download a pdf.
Hey really srry ...i did not notice tht,,this is wht wll work for him
[PHP]
error_reporting (E_ALL);
$link = mysql_connect(" localhost", "root", "") or die("Could not connect: " . mysql_error());
mysql_select_db ("xyz") or die(mysql_error ());
$sql = "SELECT Pic FROM abc WHERE ID='".$_GET['Id']."'";
//'".$_GET['Id']."'";
$result = mysql_query("$s ql") or die("Invalid query: " . mysql_error());
header("Content-type: image/jpeg");
$test=mysql_res ult($result,0);
$desired_width = 85;
$desired_height = 110;
$im = imagecreatefrom string($test);
$new = imagecreatetrue color($desired_ width, $desired_height );
$x = imagesx($im);
$y = imagesy($im);
imagecopyresamp led($new, $im, 0, 0, 0, 0, $desired_width, $desired_height , $x, $y);
imagedestroy($i m);
header("cache-Control: no-cache, must-revalidate"); // HTTP/1.1
header("Expires : Mon, 26 Jul 1997 05:00:00 GMT"); // Date in the past
header('Content-type: image/jpeg');
imagejpeg($new, NULL, 85);
imagedestroy($n ew);
// echo $test;
mysql_close($li nk);
[/PHP]
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