Question about 'sizeof'

[SM]

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

This is the array:

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);
$thumbs_cat_2 = array(
'hello',
'goodbye'
);
This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

$item_total = sizeof($thumbs_ cat_2);
output: 2
Now, i want to replace the parameter in 'sizeof' by a variable

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

Thanks
Marco

[Piotr]

SM wrote:

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

This is the array:

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);
$thumbs_cat_2 = array(
'hello',
'goodbye'
);
This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

$item_total = sizeof($thumbs_ cat_2);
output: 2
Now, i want to replace the parameter in 'sizeof' by a variable

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

You should use variable variable:
$item_total = sizeof($$item);

Mark double $$
This is true in any situation, not only with sizeof

best regards
Piotr N

[ELINTPimp]

On May 8, 11:15 am, SM <servandomont.. [e-mail] e:

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

This is the array:

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);

$thumbs_cat_2 = array(
'hello',
'goodbye'
);

This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

$item_total = sizeof($thumbs_ cat_2);
output: 2

Now, i want to replace the parameter in 'sizeof' by a variable

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

Thanks
Marco

Marco,

You should be getting a return of 1 (integer) for a string passed to
the count() function. (sizeof is an alias of count)

To get the length of a string, you would traditionally use
strlen($item), which would return the length of a string.

Regards,

Steve

[ELINTPimp]

On May 8, 11:36 am, ELINTPimp <smsi...@gmail. comwrote:

On May 8, 11:15 am, SM <servandomont.. [e-mail] e:

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

This is the array:

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);

$thumbs_cat_2 = array(
'hello',
'goodbye'
);

This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

$item_total = sizeof($thumbs_ cat_2);
output: 2

Now, i want to replace the parameter in 'sizeof' by a variable

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

Thanks
Marco

Marco,

You should be getting a return of 1 (integer) for a string passed to
the count() function. (sizeof is an alias of count)

To get the length of a string, you would traditionally use
strlen($item), which would return the length of a string.

Regards,

Steve

Ahhh, now i understand after reading Pitor's reply. Yes, he is
correct, I read the question differently.

Steve

[Piotr]

>$thumb = 1;

>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_ 1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

You should use variable variable:
$item_total = sizeof($$item);

Mark double $$
This is true in any situation, not only with sizeof

Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';

best regards
Piotr N

[SM]

On May 8, 11:36 am, ELINTPimp <smsi...@gmail. comwrote:

On May 8, 11:15 am, SM <servandomont.. [e-mail] e:

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

This is the array:

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);

$thumbs_cat_2 = array(
'hello',
'goodbye'
);

This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

$item_total = sizeof($thumbs_ cat_2);
output: 2

Now, i want to replace the parameter in 'sizeof' by a variable

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

Thanks
Marco

Marco,

You should be getting a return of 1 (integer) for a string passed to
the count() function. (sizeof is an alias of count)

To get the length of a string, you would traditionally use
strlen($item), which would return the length of a string.

Regards,

Steve

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = '$thumbs_cat_' . $thumb;
$item_total = count($item);

Thanks again
Marco

[SM]

On May 8, 11:42 am, Piotr <[e-mail] et.plwrote:

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

You should use variable variable:
$item_total = sizeof($$item);

Mark double $$
This is true in any situation, not only with sizeof

Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';

best regards
Piotr N

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($item);

Thanks again
Marco

[SM]

On May 8, 11:42 am, Piotr <[e-mail] et.plwrote:

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

You should use variable variable:
$item_total = sizeof($$item);

Mark double $$
This is true in any situation, not only with sizeof

Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';

best regards
Piotr N

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

Thanks again
Marco

[SM]

On May 8, 11:50 am, SM <servandomont.. [e-mail] e:

On May 8, 11:42 am, Piotr <[e-mail] et.plwrote:

>$thumb = 1;
>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>$thumbs_cat_ 1

>$item_total = sizeof($item);
>output: Nothing!

>How do i pass a variable to the 'sizeof' function?

You should use variable variable:
$item_total = sizeof($$item);

Mark double $$
This is true in any situation, not only with sizeof

Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';

best regards
Piotr N

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

Thanks again
Marco

Maybe i should open a new post for this one, but here it goes:

I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks

<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

[SM]

On May 8, 12:31 pm, Piotr <[e-mail] et.plwrote:

SM wrote:

On May 8, 11:50 am, SM <servandomont.. [e-mail] e:

On May 8, 11:42 am, Piotr <[e-mail] et.plwrote:

>>>$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_ 1
$item_tota l = sizeof($item);
output: Nothing!
How do i pass a variable to the 'sizeof' function?
You should use variable variable:
$item_total = sizeof($$item);
Mark double $$
This is true in any situation, not only with sizeof
Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';
best regards
Piotr N
I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

Thanks again
Marco

Maybe i should open a new post for this one, but here it goes:

I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks

<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

:)
It should look like this. Mark the { and }
echo ${$item[$i]};

As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?

best regards
Piotr N

I've tried it, It doesn't work. When i look at the source code, i see
empty an empty string:
<img src="images/" alt="" />

Here's what im trying to do:
-From a list, the user selects the category of discography (either
original, compilation, tributes, other)
-Each type of discography is associated with an array that contains
the name of the cd covers.
-Then i show a thumbnail (using a loop) of all the cd covers.

my arrays look like this (one for each category of discography)
$thumbs_cat_1 = array('moonligh t.jpg'', shadow.jpg', 'luna.jpg');
$thumbs_cat_2 = array(...);
$thumbs_cat_3 = array(...);
$thumbs_cat_4 = array(...);

Then i create the thumbs like this:
for($i=0; ...){
....<img src="images/discography/thumbs/<?php echo $thumbs_cat_1[$i]; ?

>" alt="" />

}

All of this works perfectly for the first array.
That's why, i think, i need a variable that contains the selection
from the user (the category of discography) so i can select values
from the correct array.
I do it like this:

$cat = $_GET['cat']; //output: 1
$sel_array = 'thumbs_cat_' . $cat;//create the string: thumbs_cat_1


Then i create the thumbs like this:
for($i=0; ...){
....<img src="images/discography/thumbs/<?php echo ${$sel_array[$i]}; ?

>" alt="" />

}
.... and so on

You think my code makes sense? Maybe i'm doing it wrong.
The last part is were im stock...
Any ideas what's wrong?
Thanks again
Marco