Directory $path syntax problem

[WPW07]

Hello,

I have a script that lists the contents of a directory. It was
working properly until we had to change the directory that it reads
from.

The path to this script is:

/home/n/mu1/database/refresh.php.

I'd like it to list the contents in the main directory of the site:
mu1

So I have this code to list (up one level from the script):

$path = "../mu1/";
$dir_handle = opendir($path) or die("Unable to open directory $path");

But I get this error message when I try to run it:

Warning: opendir(../mu1/) [function.opendi r]: failed to open dir: No
such file or directory in /home/n/mu1/database/refresh.php on line 19
Unable to open directory ../mu1/

Any idea what I'm doing wrong?

Thanks!

[ZeldorBlat]

On Mar 4, 12:06 pm, WPW07 <wwisnie...@gma il.comwrote:

Hello,

I have a script that lists the contents of a directory. It was
working properly until we had to change the directory that it reads
from.

The path to this script is:

/home/n/mu1/database/refresh.php.

I'd like it to list the contents in the main directory of the site:
mu1

So I have this code to list (up one level from the script):

$path = "../mu1/";
$dir_handle = opendir($path) or die("Unable to open directory $path");

But I get this error message when I try to run it:

Warning: opendir(../mu1/) [function.opendi r]: failed to open dir: No
such file or directory in /home/n/mu1/database/refresh.php on line 19
Unable to open directory ../mu1/

Any idea what I'm doing wrong?

Thanks!

From your location in /home/n/mu1/database/refresh.php the value
of ../ would be the directory above /database which is /mu1. So, "../
mu1" is really /home/n/mu1/mu1/ which probably isn't what you want.
If you're inside /database you get to mu1 with ../ by itself.

[WPW07]

On Mar 4, 12:45 pm, ZeldorBlat <zeldorb...@gma il.comwrote:

On Mar 4, 12:06 pm, WPW07 <wwisnie...@gma il.comwrote:

Hello,

I have a script that lists the contents of a directory. It was
working properly until we had to change the directory that it reads
from.

The path to this script is:

/home/n/mu1/database/refresh.php.

I'd like it to list the contents in the main directory of the site:
mu1

So I have this code to list (up one level from the script):

$path = "../mu1/";
$dir_handle = opendir($path) or die("Unable to open directory $path");

But I get this error message when I try to run it:

Warning: opendir(../mu1/) [function.opendi r]: failed to open dir: No
such file or directory in /home/n/mu1/database/refresh.php on line 19
Unable to open directory ../mu1/

Any idea what I'm doing wrong?

Thanks!

From your location in /home/n/mu1/database/refresh.php the value
of ../ would be the directory above /database which is /mu1. So, "../
mu1" is really /home/n/mu1/mu1/ which probably isn't what you want.
If you're inside /database you get to mu1 with ../ by itself.

Thank you. That fixed it!