Hello again.
I have a form for posting news articles.
Form one is the "register" form.
Then I go to the preview form were I can select edit or accept
If I select edit, I got the "edit form" and if I select accept, I
receive a message that say:
The news article "headline" are posted into the database.
When I use the file field and browse to "my photos", select an image
and post it. I can see it in the priview form/page and can also show
it in the article.
But if I select the "edit" button I can't see the image.
I am using <input type="hidden" name="article_p hoto"
value="$article _foto"field to preserve the value of the field:
<input type="file" name="article_p hoto">
Well. I discover that if I not have anything in the field <input
type="file" name="article_p hoto"...
but still have the image.jpg in the hidden field. It use the
$_POST["article_ph oto"] insted of
$_FILES["article_ph oto"];
So I was thinking that this below should do the trick:
if(!isset($_FIL ES["article_ph oto"])){
$article_photo = $_POST["article_ph oto"];
} else {
$article_photo = $_FILES["article_ph oto"];
}
But still the image are not avaible in the edit or preview pages in
the variable $article_photo
BUT if I use the file field and browse, select an image and post it.
Then it show up in those pages.
How can I fix this? Is it better to use setcookie("arti cle_photo",
$_POST['article_photo'] time()+30);
Thanks for all advice. (and sorry my weak english)
Karl 5 2582
Karl wrote:
Hello again.
I have a form for posting news articles.
Form one is the "register" form.
Then I go to the preview form were I can select edit or accept
If I select edit, I got the "edit form" and if I select accept, I
receive a message that say:
The news article "headline" are posted into the database.
When I use the file field and browse to "my photos", select an image
and post it. I can see it in the priview form/page and can also show
it in the article.
But if I select the "edit" button I can't see the image.
I am using <input type="hidden" name="article_p hoto"
value="$article _foto"field to preserve the value of the field:
<input type="file" name="article_p hoto">
Well. I discover that if I not have anything in the field <input
type="file" name="article_p hoto"...
but still have the image.jpg in the hidden field. It use the
$_POST["article_ph oto"] insted of
$_FILES["article_ph oto"];
So I was thinking that this below should do the trick:
if(!isset($_FIL ES["article_ph oto"])){
$article_photo = $_POST["article_ph oto"];
} else {
$article_photo = $_FILES["article_ph oto"];
}
But still the image are not avaible in the edit or preview pages in
the variable $article_photo
BUT if I use the file field and browse, select an image and post it.
Then it show up in those pages.
How can I fix this? Is it better to use setcookie("arti cle_photo",
$_POST['article_photo'] time()+30);
Thanks for all advice. (and sorry my weak english)
Karl
Do you have the image file name in a <img...tag?
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
=============== ===
On 29 Des, 15:54, Jerry Stuckle <jstuck...@attg lobal.netwrote:
Karl wrote:
Hello again.
I have a form for posting news articles.
Form one is the "register" form.
Then I go to the preview form were I can select edit or accept
If I select edit, I got the "edit form" and if I select accept, I
receive a message that say:
The news article "headline" are posted into the database.
When I use the file field and browse to "my photos", select an image
and post it. I can see it in the priview form/page and can also show
it in the article.
But if I select the "edit" button I can't see the image.
I am using <input type="hidden" name="article_p hoto"
value="$article _foto"field to preserve the value of the field:
<input type="file" name="article_p hoto">
Well. I discover that if I not have anything in the field <input
type="file" name="article_p hoto"...
but still have the image.jpg in the hidden field. It use the
$_POST["article_ph oto"] insted of
$_FILES["article_ph oto"];
So I was thinking that this below should do the trick:
if(!isset($_FIL ES["article_ph oto"])){
$article_photo = $_POST["article_ph oto"];
} else {
$article_photo = $_FILES["article_ph oto"];
}
But still the image are not avaible in the edit or preview pages in
the variable $article_photo
BUT if I use the file field and browse, select an image and post it.
Then it show up in those pages.
How can I fix this? Is it better to use setcookie("arti cle_photo",
$_POST['article_photo'] time()+30);
Thanks for all advice. (and sorry my weak english)
Karl
Do you have the image file name in a <img...tag?
Yes, I have.
And it works if I use the <input type="file" name="article_p hoto">
field.
$article_photo = $_FILES["article_ph oto"]; make it work.
But when I have the image.jpg registred in a <input type="hidden".. .
field, it does not work.
I think that this hidden field use the $_POST["article_ph oto"]
instead of $_FILES["article_ph oto"] because if i "comment out" the
$_FILES... line and insted use $_POST["article_ph oto"] I can find it..
But then the file field not work..
Karl
Karl wrote:
On 29 Des, 15:54, Jerry Stuckle <jstuck...@attg lobal.netwrote:
>Karl wrote:
>>Hello again. I have a form for posting news articles. Form one is the "register" form. Then I go to the preview form were I can select edit or accept If I select edit, I got the "edit form" and if I select accept, I receive a message that say: The news article "headline" are posted into the database. When I use the file field and browse to "my photos", select an image and post it. I can see it in the priview form/page and can also show it in the article. But if I select the "edit" button I can't see the image. I am using <input type="hidden" name="article_p hoto" value="$artic le_foto"field to preserve the value of the field: <input type="file" name="article_p hoto"> Well. I discover that if I not have anything in the field <input type="file" name="article_p hoto"... but still have the image.jpg in the hidden field. It use the $_POST["article_ph oto"] insted of $_FILES["article_ph oto"]; So I was thinking that this below should do the trick: if(!isset($_F ILES["article_ph oto"])){ $article_photo = $_POST["article_ph oto"]; } else { $article_photo = $_FILES["article_ph oto"]; } But still the image are not avaible in the edit or preview pages in the variable $article_photo BUT if I use the file field and browse, select an image and post it. Then it show up in those pages. How can I fix this? Is it better to use setcookie("arti cle_photo", $_POST['article_photo'] time()+30); Thanks for all advice. (and sorry my weak english) Karl
Do you have the image file name in a <img...tag?
Yes, I have.
And it works if I use the <input type="file" name="article_p hoto">
field.
$article_photo = $_FILES["article_ph oto"]; make it work.
But when I have the image.jpg registred in a <input type="hidden".. .
field, it does not work.
I think that this hidden field use the $_POST["article_ph oto"]
instead of $_FILES["article_ph oto"] because if i "comment out" the
$_FILES... line and insted use $_POST["article_ph oto"] I can find it..
But then the file field not work..
Karl
OK, did you write this yourself? Or is this someone else's script?
If the latter, that's who you should be asking.
And <input type="file"...a nd <input type="hidden".. .have two
entirely different uses.
And sure - if you comment out the $_FILES line, there is no way for the
file field will work.
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
=============== ===
On 29 Des, 19:51, Jerry Stuckle <jstuck...@attg lobal.netwrote:
>
OK, did you write this yourself? Or is this someone else's script?
No it's mine :)
>
If the latter, that's who you should be asking.
And <input type="file"...a nd <input type="hidden".. .have two
entirely different uses.
Yes, I know.
And sure - if you comment out the $_FILES line, there is no way for the
file field will work.
Yes, of course. I do it just to try what would happen.
Anyway. If I select to post the image.jpg by the file field on the
"edit" page. It work.
I had hoped to find a way to "transfer" it through this different view
of forms without post it a second time.
Karl
Karl wrote:
On 29 Des, 19:51, Jerry Stuckle <jstuck...@attg lobal.netwrote:
>OK, did you write this yourself? Or is this someone else's script?
No it's mine :)
>If the latter, that's who you should be asking.
And <input type="file"...a nd <input type="hidden".. .have two entirely different uses.
Yes, I know.
>And sure - if you comment out the $_FILES line, there is no way for the file field will work.
Yes, of course. I do it just to try what would happen.
Anyway. If I select to post the image.jpg by the file field on the
"edit" page. It work.
I had hoped to find a way to "transfer" it through this different view
of forms without post it a second time.
Karl
OK, this is a little more clear now.
The only way you can get data from one page to another is either via a
form field or the $_SESSION variable.
In a case like this, I'd just use the hidden field to pass the old name.
If the user uploads a new file, use it. Otherwise just use the old
file (the one passed in the hidden field).
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
=============== === This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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