Hi all,
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Anyone can help ?
Many thanks in advance
Nik
-----------------------------------
if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1"))
{
//// set variables
$file_temp0=($_ FILES['Logo']['tmp_name']);
$file_temp1=($_ FILES['Foto']['tmp_name']);
//folder of the image on the server
$percorso="foto/";
$nuovo_nome0=$p ercorso.$_POST['Logo'];
$nuovo_nome1=$p ercorso.$_POST['Foto'];
$insertSQL = sprintf("INSERT INTO marcalinea (ID_MarcaLinea, Marca_,
LineaProdotto_, Logo, Foto, Descrizione, Pdf_) VALUES (%s, %s, %s, %s,
%s, %s, %s)",
GetSQLValueStri ng($_POST['ID_MarcaLinea'],
"int"),
GetSQLValueStri ng($_POST['Marca_'], "int"),
GetSQLValueStri ng($_POST['LineaProdotto_ '],
"int"),
GetSQLValueStri ng($nuovo_nome0 , "text"),
GetSQLValueStri ng($nuovo_nome1 , "text"),
GetSQLValueStri ng($_POST['Descrizione'],
"text"),
GetSQLValueStri ng($_POST['Pdf_'], "int"));
//print ($file_temp0); // return nothings
//print ($nuovo_nome0); // returns correctly /foto/img_name
mysql_select_db ($database_Conn _Bianchi, $Conn_Bianchi);
$Result1 = mysql_query($in sertSQL, $Conn_Bianchi) or
die(mysql_error ());
////Everything ok 'till here; the following does't works:
######### upload image########
move_uploaded_f ile($file_temp0 , $nuovo_nome0);
move_uploaded_f ile($_FILES["Foto"]["tmp_name"],"foto/" .
$_FILES["Foto"]["name"]);
############### ############### #
$insertGoTo = "view.php";
etc... 7 2083
Is the directory the system is writing the file to set with the
correct permissions?
On Nov 23, 10:37 am, nicemot...@gmai l.com wrote:
Hi all,
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Anyone can help ?
Many thanks in advance
Nik
-----------------------------------
if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1"))
{
//// set variables
$file_temp0=($_ FILES['Logo']['tmp_name']);
$file_temp1=($_ FILES['Foto']['tmp_name']);
//folder of the image on the server
$percorso="foto/";
$nuovo_nome0=$p ercorso.$_POST['Logo'];
$nuovo_nome1=$p ercorso.$_POST['Foto'];
$insertSQL = sprintf("INSERT INTO marcalinea (ID_MarcaLinea, Marca_,
LineaProdotto_, Logo, Foto, Descrizione, Pdf_) VALUES (%s, %s, %s, %s,
%s, %s, %s)",
GetSQLValueStri ng($_POST['ID_MarcaLinea'],
"int"),
GetSQLValueStri ng($_POST['Marca_'], "int"),
GetSQLValueStri ng($_POST['LineaProdotto_ '],
"int"),
GetSQLValueStri ng($nuovo_nome0 , "text"),
GetSQLValueStri ng($nuovo_nome1 , "text"),
GetSQLValueStri ng($_POST['Descrizione'],
"text"),
GetSQLValueStri ng($_POST['Pdf_'], "int"));
//print ($file_temp0); // return nothings
//print ($nuovo_nome0); // returns correctly /foto/img_name
mysql_select_db ($database_Conn _Bianchi, $Conn_Bianchi);
$Result1 = mysql_query($in sertSQL, $Conn_Bianchi) or
die(mysql_error ());
////Everything ok 'till here; the following does't works:
######### upload image########
move_uploaded_f ile($file_temp0 , $nuovo_nome0);
move_uploaded_f ile($_FILES["Foto"]["tmp_name"],"foto/" .
$_FILES["Foto"]["name"]);
############### ############### #
$insertGoTo = "view.php";
etc...
On 23 Nov, 17:46, Acrobatic <jbn...@gmail.c omwrote:
Is the directory the system is writing the file to set with the
correct permissions?
On Nov 23, 10:37 am, nicemot...@gmai l.com wrote:
Hi all,
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Anyone can help ?
Many thanks in advance
Nik
-----------------------------------
if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1"))
{
//// set variables
$file_temp0=($_ FILES['Logo']['tmp_name']);
$file_temp1=($_ FILES['Foto']['tmp_name']);
//folder of the image on the server
$percorso="foto/";
$nuovo_nome0=$p ercorso.$_POST['Logo'];
$nuovo_nome1=$p ercorso.$_POST['Foto'];
$insertSQL = sprintf("INSERT INTO marcalinea (ID_MarcaLinea, Marca_,
LineaProdotto_, Logo, Foto, Descrizione, Pdf_) VALUES (%s, %s, %s, %s,
%s, %s, %s)",
GetSQLValueStri ng($_POST['ID_MarcaLinea'],
"int"),
GetSQLValueStri ng($_POST['Marca_'], "int"),
GetSQLValueStri ng($_POST['LineaProdotto_ '],
"int"),
GetSQLValueStri ng($nuovo_nome0 , "text"),
GetSQLValueStri ng($nuovo_nome1 , "text"),
GetSQLValueStri ng($_POST['Descrizione'],
"text"),
GetSQLValueStri ng($_POST['Pdf_'], "int"));
//print ($file_temp0); // return nothings
//print ($nuovo_nome0); // returns correctly /foto/img_name
mysql_select_db ($database_Conn _Bianchi, $Conn_Bianchi);
$Result1 = mysql_query($in sertSQL, $Conn_Bianchi) or
die(mysql_error ());
////Everything ok 'till here; the following does't works:
######### upload image########
move_uploaded_f ile($file_temp0 , $nuovo_nome0);
move_uploaded_f ile($_FILES["Foto"]["tmp_name"],"foto/" .
$_FILES["Foto"]["name"]);
############### ############### #
$insertGoTo = "view.php";
etc...
hi acrobatic! - many thanks for your ppt reply
yes, it is; all permission are ok and the script to upload the files
separately works correctly.
The problem rises when i insert the record and upload the image on the
same page...i'm afraid the var are lost somewhere
On Fri, 23 Nov 2007 17:37:28 +0100, <ni********@gma il.comwrote:
Hi all,
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Examine $_FILES['indexname']['error'] http://nl2.php.net/manual/en/feature...oad.errors.php
--
Rik Wasmus
On 23 Nov, 17:59, "Rik Wasmus" <luiheidsgoe... @hotmail.comwro te:
On Fri, 23 Nov 2007 17:37:28 +0100, <nicemot...@gma il.comwrote:
Hi all,
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Examine $_FILES['indexname']['error']http://nl2.php.net/manual/en/features.file-upload.errors.p hp
--
Rik Wasmus
Many thanks Rik,
written like this returns nothing , the record is inserted but the
pics are not uploaded.
.......... GetSQLValueStri ng($nuovo_nome1 , "text"),
GetSQLValueStri ng($_POST['Descrizione'],
"text"),
GetSQLValueStri ng($_POST['Pdf_'], "int"));
$errore=($_FILE S['Logo']['tmp_name']['error']);
print($errore);
mysql_select_db ($database..... ......
However i'm afraid (almost sure) i'm not using "" $_FILES['indexname']
['error'] "" correctly
On Fri, 23 Nov 2007 18:26:55 +0100, <ni********@gma il.comwrote:
On 23 Nov, 17:59, "Rik Wasmus" <luiheidsgoe... @hotmail.comwro te:
>On Fri, 23 Nov 2007 17:37:28 +0100, <nicemot...@gma il.comwrote:
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Examine $_FILES['indexname']['error']http://nl2.php.net/manual/en/features.file-upload.errors.p hp
written like this returns nothing , the record is inserted but the
pics are not uploaded.
......... GetSQLValueStri ng($nuovo_nome1 , "text"),
GetSQLValueStri ng($_POST['Descrizione'],
"text"),
GetSQLValueStri ng($_POST['Pdf_'], "int"));
$errore=($_FILE S['Logo']['tmp_name']['error']);
print($errore);
However i'm afraid (almost sure) i'm not using "" $_FILES['indexname']
['error'] "" correctly
What does var_dump($_FILE S); tell you? 'Logo' might not even be there.....
--
Rik Wasmus
On 23 Nov, 18:31, "Rik Wasmus" <luiheidsgoe... @hotmail.comwro te:
On Fri, 23 Nov 2007 18:26:55 +0100, <nicemot...@gma il.comwrote:
On 23 Nov, 17:59, "Rik Wasmus" <luiheidsgoe... @hotmail.comwro te:
On Fri, 23 Nov 2007 17:37:28 +0100, <nicemot...@gma il.comwrote:
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Examine
$_FILES['indexname']['error']http://nl2.php.net/manual/en/features.file-upload.errors.p hp
written like this returns nothing , the record is inserted but the
pics are not uploaded.
......... GetSQLValueStri ng($nuovo_nome1 , "text"),
GetSQLValueStri ng($_POST['Descrizione'],
"text"),
GetSQLValueStri ng($_POST['Pdf_'], "int"));
$errore=($_FILE S['Logo']['tmp_name']['error']);
print($errore);
However i'm afraid (almost sure) i'm not using "" $_FILES['indexname']
['error'] "" correctly
What does var_dump($_FILE S); tell you? 'Logo' might not even be there....
--
Rik Wasmus
Dear Rik,
tks for yr debug suggestions, i'll study and revert
What's strange is that print ($nuovo_nome0); returns correctly /foto/
img_name
...is the $file_temp0=($_ FILES['Logo']['tmp_name']) that does't works
Btw, debug and revert
Ciao by now (dinner time !) eand thanks a lot
Can we see the script/form that you specify the upload file with?
Maybe you don't have the ENCTYPE set correctly. You'll need to set
enctype to "multipart/form-data":
ie:
<form action="..." method="post" enctype="multip art/form-data"
name="...">
etc
</form>
On Nov 23, 10:37 am, nicemot...@gmai l.com wrote:
Hi all,
the following easy script correctly insert a record in the DB but is
not moving the images (Logo and Foto) to the server /foto folder.
can't understand why 'cause the script is easy and correct and i guess
it loses the $file_temp var (actually the printout of $file_temp0
return nothing)
i even tryed to write it repeating the parameters i/o using variables
but no results.
Anyone can help ?
Many thanks in advance
Nik
-----------------------------------
if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1"))
{
//// set variables
$file_temp0=($_ FILES['Logo']['tmp_name']);
$file_temp1=($_ FILES['Foto']['tmp_name']);
//folder of the image on the server
$percorso="foto/";
$nuovo_nome0=$p ercorso.$_POST['Logo'];
$nuovo_nome1=$p ercorso.$_POST['Foto'];
$insertSQL = sprintf("INSERT INTO marcalinea (ID_MarcaLinea, Marca_,
LineaProdotto_, Logo, Foto, Descrizione, Pdf_) VALUES (%s, %s, %s, %s,
%s, %s, %s)",
GetSQLValueStri ng($_POST['ID_MarcaLinea'],
"int"),
GetSQLValueStri ng($_POST['Marca_'], "int"),
GetSQLValueStri ng($_POST['LineaProdotto_ '],
"int"),
GetSQLValueStri ng($nuovo_nome0 , "text"),
GetSQLValueStri ng($nuovo_nome1 , "text"),
GetSQLValueStri ng($_POST['Descrizione'],
"text"),
GetSQLValueStri ng($_POST['Pdf_'], "int"));
//print ($file_temp0); // return nothings
//print ($nuovo_nome0); // returns correctly /foto/img_name
mysql_select_db ($database_Conn _Bianchi, $Conn_Bianchi);
$Result1 = mysql_query($in sertSQL, $Conn_Bianchi) or
die(mysql_error ());
////Everything ok 'till here; the following does't works:
######### upload image########
move_uploaded_f ile($file_temp0 , $nuovo_nome0);
move_uploaded_f ile($_FILES["Foto"]["tmp_name"],"foto/" .
$_FILES["Foto"]["name"]);
############### ############### #
$insertGoTo = "view.php";
etc...
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